I'm working with VB.Net. I have imported some data into the Data Set.I have four columns of data.
[Column 1]This is a test[/Column 1]
[Column 2]This is a comma, Test.[/Column 2]
[Column 3]This is a double quote " test.[/Column 3]
[code].....
I'm trying to use VB.NET to parse a very large plain text file (2 GB). It is a database and has a field delimiter of SOH and a record delimiter of STX. I want to separate the fields and records of the file.
I would normally read each line of a text file and then use the split function to separate out the fields. I can't use this approach as there isn't always a delimiter on every line.
Is there any way to read a file until STX is found (rather than one line at a time)?
I am wanting to write an application which opens a delimited text file (either comma, pipe, colon, semi colon) and displays the file on the form. The same feature is in Excel when you import a data file. After selecting the file it shows the contents and you can choose the delimiter. Once the delimiter is chosen the data shown reflects this and updates to show the correctly formatted data.
View 5 RepliesAlright, im trying to load a text file into a list box using a delimiter(sp?)I have 2 list box's lstFirstName and LstLastName I have the code to load it into a list box
r = New IO.StreamReader("c:\test.txt")
While (r.Peek() > -1)
lstFirstName.Items.Add(r.ReadLine)
End While
r.Close()
And at the moment this will just load the whole list box, how can I use a delimiter to split it up?So John Doe in the text pad will show up as lstFirstName: John lstLastName: Doe Sorry if im not all that clear, if you dont understand I will try to explain it clearer.
I want to read a text file with unlike delimters into a collection.This is what the file looks like:
_Item 4916 0.00 781.21
_Item 2831 0.02 842.25
there are 10029 items and i am trying to get each items description into 3 different collections: Item "names" (first column), Item "weights"(second column), and Item "values"(third column).the delimiters are as follows:
______(3 spaces)____(1 space)____
considering the amount of items in the file, it would be a complete waste of time to edit it.
How can I change the delimiter when writing my Access table to a text file? I was hoping it would be as easy as adding a similar option like we do for HDR=No; maybe Delimiter=|
Dim AccessConn As New System.Data.OleDb.OleDbConnection("Provider=Microsoft.Jet.OLEDB.4.0;Data Source=|DataDirectory|mydatabase.mdb")
AccessConn.Open()Dim AccessCommand As New System.Data.OleDb.OleDbCommand("SELECT * INTO[Text;HDR=No;DATABASE=" & userPath & "].[" & fileName & "] FROM tblMyTable", AccessConn)
AccessCommand.ExecuteNonQuery()
AccessConn.Close()
I have the following problem in VB.net. I have a string like Dim str as String = "ABCDEFGHIJKLMNOPQRSTUVWX" now i want to add a delimiter from any one of them (Comma, Hyphen, Slash, Tab) into the string at the specified position like after every One, Two and so on characters. i WANT THE RESULTANT STRING LIKE
[Code]....
I am working on finishing up a mvc 3 vb.net app... I have to parse about 2000 entries in a database and get the string value to the right of a " : " delimiter from one of the columns... Everything to the left I am not worried about but I need the value that is to the right of the colon for that item.. I have more issues involving needing to select string characters to the right or left of a delimiter... But if someone can show me how to achieve the above I can figure out the rest from there...
a example of the string is Jackson Smokehouse Fish Food:John Jacob JinggleHimer Schmit I would want to eliminate the first part of the string or just select the second part and put it in a variable for later processing...
I've been working on this program all week and I've been able to finally get it to work except for one problem. The program is suppose to parse strings from a text box to a list box and then from a list box to a text box using the users choice of delimiters. I can't seem to figure out how to get the last comma off the end of the list. ie cat,dog,elf,It seems it should be easy, but since I've worked on this program so long I believe I can't see the forest for the trees. I don't want for you to do my work for me.
[Code]...
I want to split a string at a delimiter, but I don't want to discard the delimiter; It needs to become its own variable. [code] Is there any way of achieving this short of writing my own method?
View 3 RepliesI have word : "Banana". And i want it to split into :
B
a
n
[code].....
this is my code -
With ad.Tables(2)
For i As Integer = 0 To .Rows.Count - 1
If .Rows(i)("name") & "" <> "" Then
temp &= .Rows(i)("name") & ", "
[Code]...
I have a Java-based csv file that uses the format:
"data","data","data, data","data",
"data","data","data, data","data",
"data","data","data, data","data",
[code].....
I am developing an appilcation which requires a text box with auto-complete/suggestions (drop down) for multiple words (seperated by a delimiter like space) like the tags text box here in SOF. E.g. I start typing 'app' it should show all words in the suggestions list starting with app, and when I enter a word and press space and start typing a new word it should show all suggestions for that part-word.
View 1 Replieslets say I have a string that I want to split based on several characters, like ".", "!", and "?". How do I figure out which one of those characters split my string so I can add that same character back on to the end of the split segments in question?
Dim linePunctuation as Integer = 0
Dim myString As String = "some text. with punctuation! in it?"
For i = 1 To Len(myString)
[Code].....
I have an string that is returned from an xml file and looks similar to this name1="test 1" name2="test2" name3="test 3".I want to split this into 3 elements of key=value. I can't just split using a space because some of my values may contain spaces, e.g., test 1.So, I'd like to split the string using the " before the space. I've tried many variations but can't figure out the correct syntax to specify that my split characters are a " followed by a space. For instance, I've tried text.split({""" "}) but that returns elements split by " and ignores the space after the ".It shouldn't be this difficult. Can someone please help me with the correct syntax?
View 2 RepliesThe Data looks like this:
Quote:
057359-001 Pip Drt329 Auburndale, Fl (aub) - Pompano Beach, Fl (pob) 1:0 10gbe Lan Phy.
MyArr(0) ends up "057359-001" which is correct.
MyArr(1) ends up "Pip" only which is incorrect.
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When the user clicks any item in the listbox ie lviproducts it passes that item to a textbox. The problem is that I want everything before the $ sign not to appear so only the amount ie 4.50 etc would appear in the textbox. So far I have no idea how to do this, but have the following code which is not working at all.
[Code]...
I have a string builder that has a structre like[code]...
View 6 RepliesWhat would be the simplest way to find the n-th position of delimiter in a string.For example, say, I have a string variable called FullFilePath that contains the path of a file, like, C:SourceFiles<mthyr><subject><filename>.txt From this, I would like to extract out mthyr, subject, and filename, using the delimiter, "".
I was hoping string.IndexOf would let me find the n-th position of the delimiter "", in which case I can use the result to do a string.Substring. But it looks like IndexOf only finds the first occurence of a certain string, which means I would have to interate this somehow to look for the n-th occurence.
Or is there another method that will help me do this more efficiently.
How should I split a string separated by a multi-character delimiter in VB?
i.e. If my string is say - Elephant##Monkey, How do I split it with "##" ?
I have a multiline textbox which I need to split into an array using new line as a delimiter, I've tried what I think should work but it doesn't:
HTML
Dim strArr() As String
strArr = TextBox2.Text.Split(Environment.NewLine)
I need to take the items in a listBox and post it in a textBox with a delimiter. I worked some code but it does not work correctly. I think my array is wrong but i am lost.
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eally been struggling with this one, and i cant seem to find a simple method of doing it...surely there must be one? I have a list of values that i am loading into a variable. I am trying to split that variable by the whitespace that separates each value...the only thing is the whitespace varies in size. eg.
View 3 RepliesI have a csv file which I am populating to a datagridview. I am delimiting it using "," and "space". My csv file has "," at first instance and "space" in next two instances. I want to delimit the first instance using "," and the second instance using "space" and the third instance though has "space" I wanna ignore that space.
My CSV file :
HTML
jarnvagstag,Mantel,Mantel1,Mantel2
100tag,01/01/1750 11:45:32 PM
200tag,01/02/1750 12:57:57 AM
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Okay so what I'm trying to do is get the filename from OpenFileDialog/SaveFileDialog, only without the full path, and dump said filename into a variable so I can use it for other things.
Using the Split function, I can get any part of the array between the delimiters (""), but what I'm trying to do is get all the information after the LAST delimiter in the string.
I've made a rudimentary program that combines multiple files into one single file. Currently if I combine two .csv files together the output comes out correctly for what I need, which is a coma delimited file. When I try to combine two .csv files into a .xls file it doesn't format correctly (I get all the data separated by commas, but thrown into one column in the .xls file). For this reason I believe I need to add a delimiter.I'll post my code below.
[Code]...
A word document has several pages. How to split this pages into separate documents using VB.Net ?
I wish to automate this process.I used ms tutorial for basic learning: [URL]..But i do not know how to find page breaks in a document and move content of that page to separate document.
Last year (2010) I came across a FANTASTIC command that allowed me to take a string of variables with a common delimiter and break it all back out into separate variables (possibly an array) with one statement.
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As long as the delimiter was a unique specifiable character, this one-statement command could break it out into elements. my memory and point me in the right direction.
Whats the best way to convert a list(of string) to a string with the values seperated by ,
View 3 Replies