Split The String By " " Space?
Jun 20, 2012lets say that this is my string:
1 2 3
i want to split the string by " " space and display evrey time part of my string
lets say that this is my string:
1 2 3
i want to split the string by " " space and display evrey time part of my string
I have an string that is returned from an xml file and looks similar to this name1="test 1" name2="test2" name3="test 3".I want to split this into 3 elements of key=value. I can't just split using a space because some of my values may contain spaces, e.g., test 1.So, I'd like to split the string using the " before the space. I've tried many variations but can't figure out the correct syntax to specify that my split characters are a " followed by a space. For instance, I've tried text.split({""" "}) but that returns elements split by " and ignores the space after the ".It shouldn't be this difficult. Can someone please help me with the correct syntax?
View 2 RepliesI'm trying to split a Yahoo historical stock price csv file, downloaded into a string, by what looks like a space character. I want a new row for each split. The split function works for other characters I see in the string. I suspect the characters may be a non breaking space character but I've been unable to split on them. This is the test csv file that is downloaded into the string: [URL] I'm trying to split the string like this:
[Code]...
I have a string like "op1a op1b" op2 op3 op4 im using Dim inp2 As String() = Split(inp1, " ")this would output
[Code]...
I am trying to split a long string based on an array of words. For Example:Words: trying, long, array Sentence: "I am trying to split a long string based on an array of words."Resulting string array:Multiple instances of the same word is likely, so having two instances of trying cause a split, or of array, will probably happen.
View 5 RepliesWhat if we wanted seconded index of? ' example this is a long message after a few spaces. If we wanted to split this message from the second index of " " (space) returned result long message after a few spaces
View 3 Repliesmy code is :
[Code]...
The error is Value of type '1-dimensional array of string' cannot be converted to 'String'.
Say I have a string LineOfText = "UserName1 Password1 UserName2 Password2" how would I just grab the last word (Password2)
View 4 RepliesHow would i get a certain text inside a textbox to equal that text space to space or null to space?
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
If Textbox1.Text.StartsWith(Textbox2.Text + " ") And Not String.IsNullOrEmpty(Textbox2.Text) Then
Textbox1.Text = Textbox1.Text.Remove(0, Textbox2.TextLength)
Textbox3.AppendText("a")
End If
Btw: after i finish this step my project will be finished!
These is the content of my txt file which is saved in D drive in my pc abc,1,2,3..I tried the flowing but it didn't work:[code]I am getting error on this line.. data = line.Split(","c)...it says this line isn't in use anymore or something and that I rather use LineInput but thats asks for filenumber and i don't know what that is. I am sorry but I am a complete beginner. what else can I try? [code]ok that error is gone now but now if I want to add these values to a list box..how can i do that?
View 1 RepliesIs there a way to use the string.split command to get a section of a string without using an intermediary array?for example, if my string is "1 2" and I want to get the "2" part using string.split(" "), is there a way to avoid creating a new array, and just get the bit of the string I want in a single line?
View 4 RepliesAfter having some trouble in my own code using String.Split and the Split(String(), Int32, StringSplitOptions) overload, I decided to look to the MSDN.I copied the entire VB.NET code example from this link: url...I placed it in a new class, and received the following errors (same errors as my own code example):[code]Why can my code not recogognize the string() parameter overloads to String.Split? Remember, i took the code from the MSDN link above, copied and pasted and it still did not work.I am counting on using the string() instead of char() overloads shown here: url...
View 15 RepliesBackground: I have a winForm app that registers a user in the database based on the information provided, auto-generates a random password and username, and e-mails the user a link to take an application based on the marketing company selected. Problem: hen the user clicks "Send Invitation" with data inputted iton all fields except the bundles listbox in debug, the NullReferenceException Error is thrown highlighting the line: Dim MCShort As String = Trim(splitMC(0))How do I fix this issue Here's a screenshot of the web app: Here's the code of the Send_Button_Click method off default.asx.vb:
Private Sub Send_Button_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Send_Button.Click
'TODO Add code to validate that all selections that are reaquired are met.
[code].....
i have a requirement that my <xsd:string> should allow space.it should not validate the space. but naturally it will not allow space. but i need it should allow space.
View 1 RepliesI would like to get the width of some text drawn by GDI+ in an Integer so that I can adjust the position of a cursor.
I used:
"lCursor = g.MeasureString(vInputText, Font)"
In which 'lCursor' is the offset for the original location of the cursor. But apparently the output of MeasureString is not integer and can't even parse it to integer.
I got the following code to capture information for files on a specified drive, I ran the script againts a 600 GB hard drive on one of our servers and after a while I get the error [code]How can I avoid getting this error? The server drives are quite a bit <????> and I would imagine that the CSV file would be at least 40 MB.I commented out some lines in the code, using double ticks ('') so you can see where.
View 1 RepliesI have some code that splits a session into strings by a -
My session looks something like this 123-456-789- and I split it like this
Dim MyString As String() = Session("MySession").Split("-"C)
And i've got a some code like this
Dim x as Integer
For x = 0 to MyString - 1
Response.write("Ref: " & MyString(x) & "<br>")
Next
This writes the code like this
Ref: 123
Ref: 456
Ref: 789
Ref:
So it's adding an extra Ref where it shouldn't be because there is no data after the last -
Is there a way to stop this adding in the extra one?
I have a long string like this
dim LongString as String = "123abc456def789ghi"
And I want to split it into a string array. Each element of the array should be in 3 characters length[code]...
I have a string which I've split into an array. I need to change a value in the array and join the string together. However I cannot set the value of the array variable as it's read only.Is there any way to do this without creating another array?
Dim LineOfText As StringDim aryTextFile As String[code...]
I want to take a string from a text box and split each letter of the string into an array. Then, I want to take the first item in the array(the first letter of the string)and capitalize it. Once I've done all that, I want to combine the array and convert it back to the original string it was, except I want the first letter to be capitalized(I've already placed this into a variable.)
Here's what I've come up with so far:
[Code].....
how to combine the array back to a string except I replace the first letter of the original string with the "firstLetter" variable I created.
How do I add a space between every character in a string of text?For example:Change abcdefg"
To "a b c d e f g"I have two text boxes on my form, one for input, the other for output of the re-formatted string.
How can I add space after every 4 characters to string that returned from a function? I know the returned value it is 8 or 12 or ...etc.
for example function myString will return the value of ABCDEF12XY1Z
How can i display in textbox1 as ABCD EF12 XY1Z
I have a string that has three spaces in it.
In the following examples, underscores represent the spaces:
Quote:
_x-xx-xxxx_x.xx.xx_xx
I need to remove just the first space. Now, i tried just replacing the space with nothing, like so:
VB.NET
If s.Contains(" ") Thens = s.Replace(" ", "")End If
But, that removes every space. I also tried .StartsWith, but it still removed every space. I didn't actually expect that to work, but if I hadn't tried it, I wouldn't have actually know.
how to remove just that first space?
I want to Replace a string with space here string is comming from DB, here string looks like as followes (This is my first name : "rama" and my second name : "krishna") so now i want to replace the above String as ( This is my first name : rama and my second name : krishna ) So i want to replace " this with Space..
View 4 Repliesi have this code
Dim RandomNumber As New Random()
Dim msg As String = "My name is Nick from Neptune"
For each space as char in msg
msg = msg.replace(" ", RandomNumber.Next(0, 33))
Next
[Code]...
So I basically want to make sure that a string entered by the user is valid. Valid being over 10 characters, containing only upper case characters, and only characters A - Z and spaces. The first two were easy, but I'm having trouble with the third, though.What I originally attempted to do was create a loop which checks if the first invalid character is present with the InStr function, by using the characters ASCII value. The next ASCII value is then checked, and so on until it has checked the string for every single invalid character. If an invalid character gets picked up, 1 is added to a variable, and after the loop is finished executing, if the variable is no longer 0, invalid characters have been detected.
View 3 RepliesHow to check if the string in textbox has space/spaces then I will put it in if condition.
View 9 RepliesI've always use String.IsNullOrEmpty to check for a empty string. It recently come to my attention that a " " count as not a empty string. For example,
Dim test As String = " "
If String.IsNullOrEmpty(test) Then
MessageBox.Show("Empty String")
[Code]....
It will show "Not Empty String". So how do we check for " " or " " in a string?
edit: I wasn't aware that " " count as character.
I try to remove empty space from a large string, using replace(), and using regex.
the replace method:
replace
Do While (stripped.IndexOf(Space(2)) >= 0)
stripped = stripped.Replace(Space(2), " ")
Loop
and with regex using its replace with : "/ss+/" - regular expression.
but I am still stuck with empty strings such as :
temp ""String
these string have lengths ranging between 3 and 8, so I have tried to adapt the replace function with something like this:
replace 2
Do While (stripped.IndexOf(Space(4)) >= 0)
stripped = stripped.Replace(Space(4), Space(1))
Loop