Ok, so I have a string called item. It's value is "Coffe`". When I try to get the number of caractors by using:
textcount = item.length
However it returns with the value "5". even though there is 6 caracters.
I need a simple method of counting all characters in a text box and when a button is clicked a message must display if the amount of characters has exceeded 25.
View 4 RepliesI would like to know how to count specific characters for a proper split value so I can seperate the name of the file from the rest of this address:
C:\Program Files\Folder\Folder\File.file
The reason is so I can combine it with other addresses taken in my code to cuase a proper copy command using the File.Copy with import IO The character I am trying to count is: \ This is so when I command the split, I can choose the split number (starts at 0) so if there are 4 of the "\" characters, then I would subtract one from this number, and use it as the Split index so I can capture the split data at: File.file
How can I Count the Characters in a DataTabel Field before that Field is DataBound to any TextBox. I thought of using a Variabel, something like this:
Dim Var As String = DataBindings.Add("text", HoofGeregteBindingSource, "Ing1")
If Var.Text.Length > 36 Then
. . . . . . . .
End If
I'am Sure I don't have to tell you guys, it does not work.
I have a little problem with my code.I want to browse a file,display the file,then i want to counting the letters from it.The counting letters i want to display in a textbox(in my code b1),but i don't know how.
Private Sub Button1_Click_1(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Bcalculeaza.Click
Dim action = OpenFD.ShowDialog
[Code].....
I have a string of characters, but I would like to have a string of hexdecimal characters where the hexadecimal characters are converted by turning the original characters into integers and then those integers into hexadecimal characters. How do I do that?
View 3 Repliesi have been trying to remove special characters. i am not able to remove many crlf in middile of the string.
View 3 RepliesI need to create a console program that allows you to enter a string, of which is then outputted in reverse.
Sample:
Input: Diewas
Output: saweiD
Apparently I need to find out about strings and will also need to use a loop.
Not sure if too many people know this, but the following line will cause an error:
GroupName.Substring(0, 3) = "jt_"
....if the length of GroupName is less than 3 characters. I always thought it would simply return whatever characters in GroupName, but no, it errors. I must be thinking of the old VB6 days.So, I now have to change the code to:
If (GroupName.Length > 2) Then
If (GroupName.Substring(0, 3) = "jt_") Then
Note that the two comparisons need to be on separate lines. If they are on the same line, such as:
If (GroupName.Length > 2) and (GroupName.Substring(0, 3) = "jt_") Then then the code will still fail as the length command is executed at the same time as the substring command- which will cause the error when the GroupName length is less than 3.Just thought that those of us not aware of this should be!
dp.SyntaxHighlighter.ClipboardSwf = '/dp.SyntaxHighlighter/Scripts/clipboard.swf'
dp.SyntaxHighlighter.HighlightAll('9844f9bfb55449e6a786fa62aaadfa20')
dp.SyntaxHighlighter.HighlightAll('f6d554fd98464bdba9159b319e51b381')
dp.SyntaxHighlighter.HighlightAll('93bf4ca63ad8447abdf084d8a9991e15')
I'm an inexperienced programmer,I want to count the number of line's in a string.In "hulp" are several line's, all ending with "vbCrlf".I have tryed If hulp.Substring(i, 1) = vbCrLf Then .... but that doesn't seem to work.
View 1 RepliesHow can I count the length of a string and also how many special characters are in the strings.
For instance if I have this string: $how*
How can I count that string is 5 chars long and that there are 2 special characters in the string. (special characters are the $ and
I think that I am going to have to use the .length method to count the length of the string.
I am attempting to write a very basic console application which simply counts the number of times a word appears in a sentence. This sentence is input by the user, as is the word to look for.(I also need this search to ignore the full stop and case, but I'll try and do that myself)For example:
Sentence: "This is the last time that I'll say this."
Look for word: "this"
Expected output "2" (as "this" appears twice in the sentence)
I have written some basic code below, however, the output is a boolean value rather than a count of all the times the word has been used.I have a very limited knowledge of VB, so the solution is probably going to be long winded and simplisitic. I am a mature student at university, hence the reason I am writing these odd looking applications.
Module Module1
Sub Main()
Dim userSentenceInput As String[code]......
I am trying to count the number of times a specific character is in a string. The problem is when I run the program the letter doesn't advance from "d" in the string "debugging" and doesn't display the number of time the character "g" is found.
Private Sub Button2_Click(sender As System.Object, e As System.EventArgs) Handles Button2.Click
Dim letterCount As Integer
[code].....
I would like to count the frequency of words (excluding some keywords) in a string and sort them DESC. So, how can i do it?
In the following string... This is stackoverflow. I repeat stackoverflow.Where the excluding keywords are
ExKeywords() ={"i","is"}
the output should be like
stackoverflow
repeat
this
I have written a program that uses an array of the english alphabet and Morse code. I also built a form with a input box for the alphabetic information and an output box with the Morse Code. What i am trying to do is basically type a word like "Hi" in the input box and produce the Morse Code equivalent in the Morse Code output box. [Code] This works but only one letter at a time. Do i need to Parse the string of characters one at a time, and then run it through a loop like i have created?
View 6 RepliesI have a string like 0010000.abc. Is it possible to print just the first 3 characters of the string i.e 001?ajaind
View 1 RepliesI.E. replace "http:adf.ly/random"to "adf DOT ly /random"..Removes http: and changes . to DOT and adds spaces.
View 3 RepliesI am trying to manipulate a string to get to a part of the string inside 2 specified characters. Getting anything inside the > and the space. string starting with: jk;fhdididlsls/"f>Dog (467838) fgdad
I am trying to get "Dog" out of this.
dim x as string
dim y as string
x="jk;fhdididlsls/"f>Dog (467838) fgdad"
y = x.Split(">" , " ")
MsgBox(y.Join(""))
It will somehow always error out: value of 1-dimension array of string cannot be converted to string
I have a barcode that once scanned returns a string 8 characters long.
Further along the program I have this line of [code]...
I want to be able to get the first x characters of a string
View 2 RepliesI have a string like this:
1a2b3c4d5e6f7g8h
And I need to rearrange it as follow:
a1b2c3d4e5f6g7h8
Do you understand what I mean? For each two characters, the numerical character swapping place with the following letter, i.e. from 1a change it to a1.how to rearrange the numerical characters and letters in the string? My string always has the said pattern, i.e. one integer then followed by a letter then followed by a integer then followed by a letter and so on.
How can I add space after every 4 characters to string that returned from a function? I know the returned value it is 8 or 12 or ...etc.
for example function myString will return the value of ABCDEF12XY1Z
How can i display in textbox1 as ABCD EF12 XY1Z
I have a string value (which is a hex value) that is displayed as so...F8 30 00 3D FC 13 F8 30 00 01 31 73 34 FE 34 DE F8 30 00 3D FC 13 F8 30 00 01 31 73 34 FE 34 DE F8 30 00 3D FC 13 F8 30 00 01 31 73 34 FE 34 DEThis continues on in this exact pattern. What I am trying to do is to get a " " inserted after the first 24 characters, and then after the next 24, delete a character and place an Enter or Return value. Then I would like another " " after the next 24, and then after 24 more, delete a character and place an Enter or Return value so on until the end of the string. The format would then look like this.[code]I know this is probably done with some type of array and loop, but I'm not even sure where to get started.
View 8 RepliesI've got a program that in a nutshell reads values from a SQL database and writes them to a tab-delimited text file.The issue is that some of the values in the database have special characters (TM, dash, ellipsis, etc.) When written to the text file, the formatting is lost and they come across as junk "â„¢ or â€" etc"
When the value is viewed in the immediate window, before it is written to the txt file, everything looks fine. My guess is that this is an issue of encoding. But, I'm not real sure how to proceed, where to look, or what to look for.Is this ASCII or UTF-8? If it's one of those how do I correct it before it's written to the text file.Here's how I build the text file (where feedStr is a StringBuilder)
objReader = New StreamWriter(filePath)
objReader.Write(feedStr)
objReader.Close()
character manipulation in a String.
How do you change characters in a particular string and set them to a particular value.
For eg. I want to change the third character of the string "hello" to Y = > i get "heYlo".
I tried using the Chars function but it says that the function is read only.
I am just a beginner in VB programming. What if I want to check if a certain subtext is present in a string? For example, what do I code if I want to check if the word "hello" is present in a particular string or not?
View 3 RepliesI am in a rather silly situation...suppose I have a text box in which I enter a line of text/characters/numbers...how would I be able to display the last two or first two (or may be middle two?) characters into another text box.
Example: I write "Hello World!" in the first text box and the program should display the first two characters from that text box, i.e. "he".
I need to return everything between the 2 dashes:
"xxx-12345-xxx"
Here's my conditions:
Sometimes the middle part may contain more than 5 characters, so it could look like this: "xxx-12345AB-xxx" Sometimes there's no second dash, so a string could look like this: "xxx-12345"
how I would find certain characters in a string.
View 4 RepliesI have a query to solve for which I have coded. But my code produces output only for those hardcoded values found in the text file. I have a text file which is given as the input to my code. The text file contains lines with "_DIA" , "_DIA_some number" etc. In this case I need to remove few letters from that field.
Eg: 1)if the name field contains 1234567_DIA_2.PRT, I need to remove "_DIA_2" from the name field and concatenate the .PRT with the number. 2)if the name field contains 1234567_DIA1.PRT, then remove "_DIA1" and concatenate. I need to store the number of characters removed and add so many number of blank spaces with the name field after the concatenation.
for the 1) case I need to concatenate and add 6 spaces with the name field. for the 2) case I need to concatenate and add 5 spaces with the name field.
I'm not sure how to find the number of characters from "_" to ".", underscore need to be considered in the counting and the dot(.) should not be taken into account.