I need to open a *.py file in the shell (DOS) box, but it returns an error that no file was found at the specified path. But this path is completely correct. Unless Visual Basic are referencing to paths in another matter than C#? 'Cause I am developing in C# and referenced to VB to do this.
View 3 RepliesI am getting the following error when trying to open a vb .net 1.0 project using VS2002."Unable to open Web project 'ProjectName'.The file path 'FilePath' does not correspond to the URL 'ProjectURL'. The two need to map to the same server location. HTTP 404: Object Not Found."I have tried ALL of the links that Google threw at me (on the first page) on searching on "unable to open web project the two need to map to the same server location" term.I get this error when trying to open an existing vb.net 1.0 project and also when creating a new one.
View 1 RepliesI'm working on an application, a GUI front-end for a command-line program. What I need to do is this:-use the OpenFileDialog to retrieve the command-line program's path (as it may be in different places for different users)-save that path string in a variable that I can use later (save "C: arget" in a variable called mainPath)
View 11 Repliesi am using this as my file path of my information Private strInformation As String = Application.StartupPath & "Information.dat" however, when i deploy the application and install it...i get an error when it tries to access the file, am i using the correct file path?
View 17 Repliesi want to have a txt file on my application final .exe the .txt is located at
C:UsersTimhookDocumentsVisual Studio 2008ProjectsWWTBAM WWTBAM inDebughask.txt
thats my project binDebug folder will it include the this hask.txt file after publishing the application?
I'm using VB.NET in Visual Studio 2008 in a Vista 64-bit OS. I'm trying to find an easy way (there must be one) to quickly retrieve from the registry the application file name and path to use in a Shell command to open a particular file. Specifically, I want the user in my app to be able to click on a PDF file and have the app open that PDF file using the application associated with PDF file types - Acrobat Reader, for example. Anyone have any suggestions as to proper coding & syntax for the following sequence?:
(1) Get name of .exe file associated with .pdf file type (most likely from the HKey Root Classes hive)
(2) Get path for the .exe file
(3) Shell("[pathname]appname.exe filename.pdf")
I've spent a couple of hours looking through the forums and haven't found what I'm looking for.
I'm just getting started in VB.net using vb.net 2010 . I thought what I had left to do today was simple but not to be.I am simply trying to open a zip file that the user has selected.No mater how I have tried to send the filename (with quotes added, chr(34) & selfilename, set permissions, confirm file is found) I get Error 53 File Not Found.
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim SelFileName As String
Dim ReturnValue As Boolean
SelFileName = ListBox1.SelectedItem 'Contains the full path and filename
[code].....
If I use the shell command: notepadID = Shell("C:\WINDOWS\system32\notepad.exe", AppWinStyle.MaximizedFocus)When note pad opens I want to control the fileopen box. I can use the SendKeys.SendWait("%(FO)") to get the box opened but then how can I control the initial directory and the file type filter? I would much rather open the fileopen box in code and control it that way. How can I use the code below to control the fileopen on a process that the shell command opened up? [code]
View 5 Repliesi got to do a program in VB.NET that copies a file from a pc to a usb device. I use the method System.IO.File.Copy(FileToCopy, NewCopy) in which i have to specify the destination path. The problem is that when i change pc the destination can change: for example in my pc i read my USB pendrive o G: and on my friend pc i read the usb pendrive on E:. How can i solve that? May i specify a general path to my USB giving it a name or anything similar?
View 5 RepliesI know the "Process.Start" function, but it creates a new object of the cmd shell which terminates itself when the Python script is at its end. How can i open the original Windows Command Shell so that the Python file can run to its end without the box getting closed?
View 6 RepliesHow to make DLL file that returns File Path which is selected in the Dll while creating, using openfiledialog, Button, Textbox.
View 1 Repliesi am trying to open a excel 2007 file using a shell command in visual studio .net 2008 from a button object but it says "File Not Found" even though I created the file and put it into the same folder as the application.
View 2 Replies1.i want to open a text file in the exe.using Shell "mathtype.exe" "Filename" ' Assume file contains "Hai"
2.I have to copy the content "Hai".
3.I have to paste/write the copied content in a text file,
4.Save the text file in "c:"
i am very new @ visual basic just worked in php and html before this i downloaded visual studio 2008 with sp1 before a few days and made my first steps whit it. i want to make something like an software package for myself just to trie out some things, and i would like to add (firefox.3.1.exe to MY RESOURCES, and after that i want to make something like a button and a button click event that when i clikc the button it opens the .exe file in my resourses and i can install it)so i know how to add it to my resources. so is there maybe any way to use SHELL to open a file called firefox_setup.exe in MY.RESOURCES?
View 3 RepliesI'm trying to use the Shell to have my application call an external application but its not working...I don't understand why. I get the following error: 'System.windows.shell' is a namespace and cannot be used as an expression!
Heres my code....any ideas what I'm doing wrong. Its got to be a simple...stupid error.
Private Sub mnuUpgrade_Click(ByVal Ctrl As Microsoft.Expression.Web.Interop.Legacy.CommandBarButton, ByRef CancelDefault As Boolean) Handles mnuUpgrade.Click
[CODE].....................
i m creating a simple application that will open files which located in the CD rom... this is wat i got now
System.Diagnostics.Process.Start("F:Test\testing 1-test.pdf")
its works well.. but then not everyone CD rom drive is the same,anyway to do it as open the file without concerning the cd rom path??
Well im making a program that will Add the Safe File Name of the File opened in the Open File Dialog to the first column of the listview and the File name and path to the second. What i want it so when i double click on the Safe file name it will open the file specified in the path in the second column.i already got the add file to it.
View 4 RepliesIs there a better way of finding the path of a file that was opened with the open file dialogue? This is what I did. It works, but it seems like there should be a way to get the path through one of the open dialogue options.
Code:
'm_PicSource = OpenFileDialog1.FileName
'm_PicSource is a global var
Dim strCnt As Integer = m_PicSource.Length - 1
[Code].....
how do i return the file path to a variable when using open file dialog to browse and open a file?
View 14 RepliesI need to delete certain files in a directory so if the file is opened....suppose a xx.doc file i wont be able to delete.
View 6 RepliesI want to make my program so when you click button2 an explorer window opens up going to C:Users. How DO i do that?
View 7 RepliesI have a problem on my project homework to make data CRUD files from drive which files upload using openfiledialog.my problem is I don't know source code how to open file from table, if I click path then open file (likes links url. I try to search but until now I can't found it.
View 3 RepliesI have a database that contains a file path in 4 of the columns. I am using VB Express 2008 on Windows 7 (I have already figured out the 32bit to 64bit problem while working with access databases). This path is generated from code on another form. I have a datagridview that contains the path in a columns. i want to be able to click on the file path column and the file (in this case it is either a .jpg or .pdf) opens.
View 6 RepliesI am working with Visual Studio 2008 to concieve a small program.pdf file is supposed to open when a button is pressed. It work great with the code:
System.Diagnostics.Process.Start("<Full File Path>")
Only, I would like to place the pdf file in the project's folder and that would open wherever the project's folder is (on the Desktop, a USB port, anywhere).
1- How to get this relative path?
2- in which folder to put the pdf?
Is there a way to write a list of all paths and file names of currently open files. The best I can do is use the System.Diagnostics.Process class to grab the processes of the applications in which I am interested and then get the file name from the main window title for each process. There is no way to get the path for these files, however, with this approach.
View 5 RepliesUsing Application.GetOpenFilename I'm wanting to direct the user to a url file location but cannot get the chdir function to change to a valid url. Is there another method for this?thanksegchdir "http://mysite/reports/" (this bit doesn't work)Application.GetOpenFilename ("*.csv,*.csv")
View 1 RepliesI have ListView box with a file path for example
C: est.txt
So how can i open the C: So i just want to open the folder were the file is located and not the file its self.
I have a problem on my project homework to make data CRUD files from drive which files upload using openfiledialog. my problem is I don't know source code how to open file from table, if I click path then open file (likes links url. I try to search but until now I can't found it.
View 1 Repliesthe story goes something like this:i have embedded resource file, a vbs script.i have an error when i use writeallbytes and it says dimensional error cannot be converted to bytes something like that so i decided to make a module instead of writeallbytes,what my program does is it writes the content of the script to textbox and after that this data will be written in a script and will be save on drive C: as .vbs.that is perfectly working on my codes
[Code]...
Recently (I have no idea when) App.Path in VB6 started to return a URI rather than an absolute path for the location. Instead of returning something like "C:program filesmyapplication it has begun returning "\sacoc$program filesmyapplication"Has anyone else noticed this?
It breaks a whole crap-load of my code.It seems like MS, in their infinite wisdom, have decided there is some security breach with the way it was returned before - just guessing.