I have a textbox and the text inside is "2 32 52 14 65". May I know how can I remove all the last spaing until it reach the last string which make it look like "2 32 52 14 65". The number of last spacing might change so i can't use the below code where the number of last spacing is known.
TextBox5.Text = TextBox5.Text.Substring(0, TextBox5.Text.Length - 3)
change the character spacing of a string or textbox output? One possibility is by creating a custom font, but i am unsure if there is a property in one of the overloads that will allow me to change character spacing?!
View 1 RepliesI'm having a variable, which contains characters with tab character in between two words. remove the Tab character.
For Ex;
Input string "Word<tab>1234"
I need the output as "Word1234"
0000011 22 331. How do I remove "22"?2. How do I get "0000011" and "33"?
View 1 RepliesWe know that VB string start and end with double quotes " "
So we have to use "" if we want " in VB string.
I wonder if there is a regular expression pattern which will match VB string?.
i tried to read html contents by striping html tags in a string.when i try to print that string i got - character. how to remove this character?
View 2 RepliesIs there any function in vb.net that removes all spaces in a string. I mean a string like ' What is this' should be 'Whatisthis'
View 3 RepliesI had a quick question. I'm desiging a program that users can enter a currency (dollar amount) in a textbox. Since the string I declared will be based on what the user typed in and I want to convert it to a decimal, I want to remove a "$" sign if the user made one.
View 4 Replieslbltime.Text.Replace(lbltime.Text, lbltime.Text.Length - 2)That does nothing, no error but it doesnt remove the last 2 characters from the string.
View 8 RepliesI have an object folder, which has an atributte name path, that contains a string with it's current path, say "folder1folder2folder3"
I need to remove the last ocurrence beginning on the last "" (in this case, 'folder3'). The new string would be "folder1folder2"
I have two a strings when i use them in msgbox() i get this
View 6 RepliesI'm trying remove non-letters from this string I have. I have an order form for hats and T-shirts, they select everything and click on buy button there order info shows up in a listbox. For the results in the listbox I break down there order info and show there total price. Well the string I have for the sizes comes up with Medium "7 1/8 - 7 1/4" in the list box. I want to remove non-letters and have it just show "Medium". I try using the instr function and the trim function as well but nothing is happening.
View 1 RepliesAlright I am taking an XML file which has a bunch of tags and I'm trying to eliminate everything but whats inbetween certian tags for instance the input maybe
- <w:p w:rsidR="00254C13" w:rsidRDefault="001173CF" w:rsidP="001173CF">
- <w:pPr>
- <w:tabs>
[Code].....
unless they say they are safe. Average consumer can protect themselves>not knowledgeable enough to always protect selves</w:t> I want to go through and remove those end tags but when i used the remove string it didn't let me specify a string to remove it the two arguments were where to start and how long. how do i specify what to remove?
I have a string that has three spaces in it.
In the following examples, underscores represent the spaces:
Quote:
_x-xx-xxxx_x.xx.xx_xx
I need to remove just the first space. Now, i tried just replacing the space with nothing, like so:
VB.NET
If s.Contains(" ") Thens = s.Replace(" ", "")End If
But, that removes every space. I also tried .StartsWith, but it still removed every space. I didn't actually expect that to work, but if I hadn't tried it, I wouldn't have actually know.
how to remove just that first space?
When I try to remove the last few characters of a string, I get an index out of range error. I am using the following to remove the characters from the end of the string:
objJSONStringBuilder.Remove(objJSONStringBuilder.Length - 1, 6)
The string has <hr /> at the end which I want to remove.
I need to be able to pull a list of reference from a database whixh ar 12 characters long. Unfortunatley i dont want the first character from each reference number as it is useless but just has to be there.
anyway of saying "list refernce numbers, not including the first character"?
If I have a string like: (240). Is their a easy way to strip out the "(" and ")" so that I am left with 240?
View 3 Repliesprogram makes strings from webbrowser documenttext.For example
String1 = "<span class""long-title"" title"" Informations here"
Im trying to remove all text before "Informations here" this is what i currently have.
dim mychar as char () = {"<"c, "s"c, "p"c, "a"c, '....thatandlike20moretill.... "e"c, """"c}
string1 = string1.TrimStart(mychar)
(Note that each letter or symbol inbetween the quotations is a part of the string (span = "s" "p"...)Now this works. Not all the time though and its a pain in the .. having to do "letter"c, all the time.. (I got over 10 strings lol) Im wondering if theres a way easier method to remove part of string from the beginning, maybe like still a certen part of the length..
I wrote a palindrome earlier for a project which I figured out but I talked to a friend in another class and he was having issues with how to take out the punctuation. I dont think it was required on mine but I am just currious how that could be done using commands such as str.lenght, or str.trim those basic commands. Here is my last post that is related
[Code]...
I have a string like
FVAL(XXX)="TRUE" AND FVAL(TT)="FALSE"
I want to replace all "TRUE" and "FALSE" by TRUE AND FALSE.
Now the resultant string should be
FVAL(XXX)=TRUE AND FVAL(TT)=FALSE
Will the code shown below be upto the mark for this.
Regex.Replace("FVAL(XXX)=""TRUE"" AND FVAL(TT)=""FALSE""", "[""]TRUE[""]", "TRUE", RegexOptions.IgnoreCase)
So im trying to do a simple system in my VB Express Edition 2008 and what it does is add some car models (example) to a list box and stores it in a .txt file for future use. But when the user clicks a delete button it should delete from both the listbox and the .txt. I have to use only the FileOpen(OpenMode.Append or OpenMode.Input/Output) functions.
View 3 RepliesSo im trying to do a simple system in my VB Express Edition 2008 and what it does is add some car models (example) to a list box and stores it in a .txt file for future use. But when the user clicks a delete button it should delete from both the listbox and the .txt.I have to use only the FileOpen(OpenMode.Append or OpenMode.Input/Output) functions.
View 1 Repliesthis is driving me crazy , I have a string like this dim s as string = "<a href="url.aspx? target=_BLANK>mik, H</a>" I want to remove "mik, h" from the string, how can i do that?
View 4 RepliesRemoving the first 8 characters from a text string. How can I do it?
View 6 RepliesI need to parse an alphanumeric string leaving the characters "0-9", ".", "/" and space & remove everything else. I use "[^0-9./ ]" as my regex string and it works well. But now I have a couple other conditions that I dont know how to handle with my regex string. I actually only want to keep the "." character if it falls between two digit characters (ie. 3.5), otherwise remove it. And also I need to replace any "-" characters with a space if it falls between two digit characters (ie. 2-1), otherwise remove it.
View 1 RepliesIf I want to remove 2 characters, or a specific letter or character from a string in VB, how would I accomplish this?
A usual input would be
"63.0" in string format
and I want it to be
"63"
I have a file location as a string. How can i remove the path from the string and just use the file name? For example:c:filesfile.zip - is the stringhow can i just make it so it's file.zip?keep in mind that the location is found by using anpenfiledialog(), so it needs to be able to remove the location wherever the file is.
View 6 RepliesI have not had much time to go threw my code properly as this is some urgency. I need to remove line 1 from a textfile if it contains a string but its not working.I have 500 files and not going to do this manually.
Code:
Private Sub btnRemove_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnRemove.Click
If String.IsNullOrEmpty(txtDirectory.Text) Then
OpenFolderDialogDirectory()
[code]....
I also feel the function is very pointless sime i am opening the file twice.
I'm trying to build an app that would search a text file for a string entered by the user, and delete the line of text containing that string. Here's the code I have. The code works, but since I'm relatively new to VB and programming as a whole, I was wondering if there's a better method out there. he strFilePath is handled by the openfilediaglog
Dim strSearch As String = Replace(MaskedTextBox1.Text, "-", "")
Dim strLine As String = Nothing
Dim strAllText As String = Nothing
[code].....
I have been using the following code to remove text from strings so far;
String = Replace(String, "TextToChange", "")
However, I now would like to remove two words only when the occur consecutively for example, I would like to remove "Task 1", not all instances of the word "Task" and value "1".