I have been using the following code to remove text from strings so far;
String = Replace(String, "TextToChange", "")
However, I now would like to remove two words only when the occur consecutively for example, I would like to remove "Task 1", not all instances of the word "Task" and value "1".
I need to parse an alphanumeric string leaving the characters "0-9", ".", "/" and space & remove everything else. I use "[^0-9./ ]" as my regex string and it works well. But now I have a couple other conditions that I dont know how to handle with my regex string. I actually only want to keep the "." character if it falls between two digit characters (ie. 3.5), otherwise remove it. And also I need to replace any "-" characters with a space if it falls between two digit characters (ie. 2-1), otherwise remove it.
View 1 RepliesIf I want to remove 2 characters, or a specific letter or character from a string in VB, how would I accomplish this?
A usual input would be
"63.0" in string format
and I want it to be
"63"
I have a file location as a string. How can i remove the path from the string and just use the file name? For example:c:filesfile.zip - is the stringhow can i just make it so it's file.zip?keep in mind that the location is found by using anpenfiledialog(), so it needs to be able to remove the location wherever the file is.
View 6 RepliesFor Each s As String In list
If s.Contains("Hello") Then
list.Remove(s) 'ERROR Collection was modified; enumeration operation may not execute.
End If
Next
Why do i get that error?
I have strMyString that contains about 5000 lines of data. There are some lines of data that need removing if they contain a certain string, such as "http", "www.", ".com", "cat", "fish", etc. The whole line needs removing. Each line is separated by a vbNewLine or similar.
How can I do that? Does it need pasting into a rich textbox first before processing?
Right now im using
If ListBox1.FindStringExact(TextBox2.Text) = "0" Then
Label2.Text = "yes"
GoTo procheck
[Code]....
and it searches the first item in the listbox correctly but nothing else. Im assuming im going to need to loop through the listbox somehow?
I am using Crystal Enterprise 10 to run Adhoc Query to generate reports.My database has data with 4 digits after decimal point. But, the Ad Hoc query report rounds the data to 2 digits and displays that. Is there a way I can change this default behaviour to show the data as it is without rounding it?
View 5 Replies[Code] Which (when looped) checks all items that contain X, However, I am getting a lot of false positives (i.e. if PGA is legit, PGA, LPGA, JLPGA, WHATEVERPGA will all be highlighted as well) Any way to change .indextof to an .exactindexof or something?
View 1 RepliesI need to remove an instance in a class for which I also created a dictionary with a string key type. Like this...:
vb
'Declare dictionary
Public PersonsList As New Dictionary(Of String, Person)
'At the bottom of frmMain.vb
[code]....
As you see, I end having 120 instances of the class Person, each assigned with a string key consisting in "student1" to "student120".
At other parts of the program I repeatedly refer to PersonsList("student" & n) to set values at those class entries, mainly with a For n ... Next block.
Now... I need a routine to remove one of those instances for good, including its entry at the dictionary, so my first bet is this...:
vb
Public Sub ExpellStudent(ByVal student_index As Integer)
PersonsList.Remove("student" & selected_student_index)
students_count -= 1
End Sub
I assume this is good enough to remove the KVP at the dictionary AND the class instance proper... right?Well, even if that is ok, I foresee one problem... Let's say I removed "student46". Next time I run a For n = 1 to students_count I would bet that I'll receive an exception due to having a gap at "student46" KVP... and that without saying that students_count will be 119, so it will never reach "student120".In short, I need a way to reassign the KVP of the now 119 Person entries, so they're consecutive again (I don't care about them changing their string key values), so I still could use my For n = 1 to students_count ... Next blocks without problems... but I cannot figure out how.
I am working on a VB.Net project and trying to get it to pull data from a database. I have the data base located in my bin folder with in the project but I do not know the exact path how to do it. The code that I am using is noted below
Private Sub btnTotalTravelCost_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnTotalTravelCost.Click
'strsql is a sql statement that selects all the fields from the
'ApprovedTravelRequest table
Dim strSql As String = "SELECT * FROM ApprovedTravelRequests "
'strPath provides the database type and path of the Travel database.
[Code] .....
I want to pull the data from the Bin File. I know the current location shown is incorrect.
I have store the variable in
Dim Lastname, Surname, Middlename, age As String
and the data are saved in notepad. how can I put them back in their exact label.one of my lable is
lbl_surname.Text
I'm having a variable, which contains characters with tab character in between two words. remove the Tab character.
For Ex;
Input string "Word<tab>1234"
I need the output as "Word1234"
0000011 22 331. How do I remove "22"?2. How do I get "0000011" and "33"?
View 1 Repliesi tried to read html contents by striping html tags in a string.when i try to print that string i got - character. how to remove this character?
View 2 RepliesIs there any function in vb.net that removes all spaces in a string. I mean a string like ' What is this' should be 'Whatisthis'
View 3 RepliesI had a quick question. I'm desiging a program that users can enter a currency (dollar amount) in a textbox. Since the string I declared will be based on what the user typed in and I want to convert it to a decimal, I want to remove a "$" sign if the user made one.
View 4 Replieslbltime.Text.Replace(lbltime.Text, lbltime.Text.Length - 2)That does nothing, no error but it doesnt remove the last 2 characters from the string.
View 8 RepliesI have an object folder, which has an atributte name path, that contains a string with it's current path, say "folder1folder2folder3"
I need to remove the last ocurrence beginning on the last "" (in this case, 'folder3'). The new string would be "folder1folder2"
I have two a strings when i use them in msgbox() i get this
View 6 RepliesI'm trying remove non-letters from this string I have. I have an order form for hats and T-shirts, they select everything and click on buy button there order info shows up in a listbox. For the results in the listbox I break down there order info and show there total price. Well the string I have for the sizes comes up with Medium "7 1/8 - 7 1/4" in the list box. I want to remove non-letters and have it just show "Medium". I try using the instr function and the trim function as well but nothing is happening.
View 1 RepliesAlright I am taking an XML file which has a bunch of tags and I'm trying to eliminate everything but whats inbetween certian tags for instance the input maybe
- <w:p w:rsidR="00254C13" w:rsidRDefault="001173CF" w:rsidP="001173CF">
- <w:pPr>
- <w:tabs>
[Code].....
unless they say they are safe. Average consumer can protect themselves>not knowledgeable enough to always protect selves</w:t> I want to go through and remove those end tags but when i used the remove string it didn't let me specify a string to remove it the two arguments were where to start and how long. how do i specify what to remove?
I have a string that has three spaces in it.
In the following examples, underscores represent the spaces:
Quote:
_x-xx-xxxx_x.xx.xx_xx
I need to remove just the first space. Now, i tried just replacing the space with nothing, like so:
VB.NET
If s.Contains(" ") Thens = s.Replace(" ", "")End If
But, that removes every space. I also tried .StartsWith, but it still removed every space. I didn't actually expect that to work, but if I hadn't tried it, I wouldn't have actually know.
how to remove just that first space?
When I try to remove the last few characters of a string, I get an index out of range error. I am using the following to remove the characters from the end of the string:
objJSONStringBuilder.Remove(objJSONStringBuilder.Length - 1, 6)
The string has <hr /> at the end which I want to remove.
I need to be able to pull a list of reference from a database whixh ar 12 characters long. Unfortunatley i dont want the first character from each reference number as it is useless but just has to be there.
anyway of saying "list refernce numbers, not including the first character"?
If I have a string like: (240). Is their a easy way to strip out the "(" and ")" so that I am left with 240?
View 3 Repliesprogram makes strings from webbrowser documenttext.For example
String1 = "<span class""long-title"" title"" Informations here"
Im trying to remove all text before "Informations here" this is what i currently have.
dim mychar as char () = {"<"c, "s"c, "p"c, "a"c, '....thatandlike20moretill.... "e"c, """"c}
string1 = string1.TrimStart(mychar)
(Note that each letter or symbol inbetween the quotations is a part of the string (span = "s" "p"...)Now this works. Not all the time though and its a pain in the .. having to do "letter"c, all the time.. (I got over 10 strings lol) Im wondering if theres a way easier method to remove part of string from the beginning, maybe like still a certen part of the length..
I wrote a palindrome earlier for a project which I figured out but I talked to a friend in another class and he was having issues with how to take out the punctuation. I dont think it was required on mine but I am just currious how that could be done using commands such as str.lenght, or str.trim those basic commands. Here is my last post that is related
[Code]...
I have a string like
FVAL(XXX)="TRUE" AND FVAL(TT)="FALSE"
I want to replace all "TRUE" and "FALSE" by TRUE AND FALSE.
Now the resultant string should be
FVAL(XXX)=TRUE AND FVAL(TT)=FALSE
Will the code shown below be upto the mark for this.
Regex.Replace("FVAL(XXX)=""TRUE"" AND FVAL(TT)=""FALSE""", "[""]TRUE[""]", "TRUE", RegexOptions.IgnoreCase)
So im trying to do a simple system in my VB Express Edition 2008 and what it does is add some car models (example) to a list box and stores it in a .txt file for future use. But when the user clicks a delete button it should delete from both the listbox and the .txt. I have to use only the FileOpen(OpenMode.Append or OpenMode.Input/Output) functions.
View 3 Replies