Im trying to remove all text before "Informations here" this is what i currently have.
dim mychar as char () = {"<"c, "s"c, "p"c, "a"c, '....thatandlike20moretill.... "e"c, """"c}
string1 = string1.TrimStart(mychar)
(Note that each letter or symbol inbetween the quotations is a part of the string (span = "s" "p"...)Now this works. Not all the time though and its a pain in the .. having to do "letter"c, all the time.. (I got over 10 strings lol) Im wondering if theres a way easier method to remove part of string from the beginning, maybe like still a certen part of the length..
I have a file location as a string. How can i remove the path from the string and just use the file name? For example:c:filesfile.zip - is the stringhow can i just make it so it's file.zip?keep in mind that the location is found by using anpenfiledialog(), so it needs to be able to remove the location wherever the file is.
'm currently having trouble with a textbox. If the text in the textbox is longer than the textbox itself, it will display the end of text to the user. I need it to display the beginning of the text to the user. Is there a possible way to force that to
I have 20 checkboxes (I don't use checkboxlist because if user click on checkbox then new window appear) in one form. I want to do that when user select few of those checkboxes they will appear in new textbox or label in new form. But I have a problem, when user uncheck checkbox the data is not removed from textbox or label. How can I do, that only text of that unchecked checkbox is removed from textbox or label.I tried with for each look up but i don't know how to do that either, so I am doing that with IFs for every checkbox.
DnsGetHostEntry takes an IPaddress as an argument but the one I'm supplying it while debugging is throwing an exception of "No such host is known" when I know that this is a perfectly valid host.
Somehow a space or character has been introduced at the beginning of the strong as per the text in quotes below. I tried a Trim(" ",
" 10.0.110.37" "" & vbLf & "10.0.110.37" this is what I see when clicking on Edit Value in Quickwatch
I have a string:*Local Disk*:Users*UserName*DirectoryTestFile.txtand im trying to get rid of everything behind the "Test" so it would show everything after.so the string would look like:TestFile.txtno matter how many directories and/or files come after the Test. I just want to get rid of everything behind it.
Basically I have a webresponse stream:dim lol as string = readstream.tostring there is a lot of information within the string but only one link starting with http: located near the end of the string - however there is no constant character point where I can start... (i.e. 38)
I want to extract the link from the string i.e. dog cat plane car [URL]..that is approximately how it looks above - words and url substituted I want to just extract [URL]..I had an idea of parsing the string from http: to the end Then after that splitting the string up again to remove the }], however it does not return anything
I have a string of 5 characters out of which the first two characters should be in some list and next three should be in some other list.How could i validate them with regular expressions? [code]My Strings are going to be: VBBEG, CSBEG, etc.My regular expression should find that the input string first two characters could be either VB, CS, HT and the rest should also be like that.
I need to remove a "!" from the beginning of a string. I've added a watch in the debugger and it's not recognizing the string -contains- the !, but under the definition on the watch it's showing !XXX-XX-XXX
Dim Fewl As String = " " Dim ExPoint As Char = "!" Fewl = textSKU.ToString
One number is represented with four hex values.First two hex parts are my "whole number" part, third and fouth hex numbers are my "decimal" part. I just wanted to store my complete number (whole and decimal) in an excel table.My problem is following when I am storing whole part and decimal part of my number separately, then it works fine am getting f.e. 3017 and 0,9445123 in my excel table, but when I am concatenate them, then I am getting following expression in my excel table f.e. 30,179,445,123 but I want 3017,9445123.
I had a quick question. I'm desiging a program that users can enter a currency (dollar amount) in a textbox. Since the string I declared will be based on what the user typed in and I want to convert it to a decimal, I want to remove a "$" sign if the user made one.
I'm trying remove non-letters from this string I have. I have an order form for hats and T-shirts, they select everything and click on buy button there order info shows up in a listbox. For the results in the listbox I break down there order info and show there total price. Well the string I have for the sizes comes up with Medium "7 1/8 - 7 1/4" in the list box. I want to remove non-letters and have it just show "Medium". I try using the instr function and the trim function as well but nothing is happening.
Alright I am taking an XML file which has a bunch of tags and I'm trying to eliminate everything but whats inbetween certian tags for instance the input maybe
unless they say they are safe. Average consumer can protect themselves>not knowledgeable enough to always protect selves</w:t> I want to go through and remove those end tags but when i used the remove string it didn't let me specify a string to remove it the two arguments were where to start and how long. how do i specify what to remove?
In the following examples, underscores represent the spaces:
Quote:
_x-xx-xxxx_x.xx.xx_xx
I need to remove just the first space. Now, i tried just replacing the space with nothing, like so:
VB.NET
If s.Contains(" ") Thens = s.Replace(" ", "")End If
But, that removes every space. I also tried .StartsWith, but it still removed every space. I didn't actually expect that to work, but if I hadn't tried it, I wouldn't have actually know.
How do i detect a part of a string from a string? For example: i want to check if the part of the string "mummy" exists in a string:"Mummy loves Daddy and loves me too"
How to cut part from this string..."abb.c.d+de.ee+f.xxx+qaa.+.,,s,"... where i know position by this: Result is always between "." (left side of result) and "+" (right side).I know number of "." from left side and number of "+" from right side, to delimit resulting string.Problem is right side, cause i need to count "+" from end.
Say... from left side: begining is at 4th "." ( this is easy ), result is =
When I try to remove the last few characters of a string, I get an index out of range error. I am using the following to remove the characters from the end of the string:
I need to be able to pull a list of reference from a database whixh ar 12 characters long. Unfortunatley i dont want the first character from each reference number as it is useless but just has to be there.
anyway of saying "list refernce numbers, not including the first character"?
