Create A Random String With Number And Letters In 8 Characters Long In VB 2008?
Apr 16, 2009I would like to ask for some on how to create a random string with number and letters in 8 characters long in VB 2008
View 1 RepliesI would like to ask for some on how to create a random string with number and letters in 8 characters long in VB 2008
View 1 RepliesI nedd some help in generating a random alph-numeric password for a form that I building. The form should suggest a password that 18 characters long. The user would either agree to this password or enter their own password.[code]When I use this I get a two digit number.
View 5 RepliesA question: How can I create a string that is x characters long, but is made up of "space bar" characters?
View 6 RepliesWith this code...
vb
...Dim random As Long = RandomNumber(1000000000000000, 9999999999999999)... Private Function RandomNumber(ByVal Min As Long, ByVal Max As Long) As Long Dim Random As New Random() Return Random.Next(Min, Max)End Function
...I am getting a OverflowException. Is it so that Random class can't handle Long values?
I want to create a random string (about 20 characters length). Is there any built-in class in .net that able to create random string?
View 9 Repliesi am trying to generate 200 hundred characters (Letters) at random but i m get only 10 numbers!! also i need to search for vowels and their position this is what i got so far.
Private Sub btnGen1stchrblk_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnGen1stchrblk.Click
Dim randomChar As String
Dim randomInstance As New Random
randomChar = "abcdefghijklmnopqrstuvwxyz"
randomChar = randomInstance.Next.ToString
[Code]...
I'm trying to generate random dates in between two dates that are selected with a date and time selection control.Ideally, I would like to get the 'ticks' of each date, generate a random number between those, and then convert that back into a date.However I'm getting arithmetic overflow errors when I try to generate a random number from the between the ticks. I've tried many approaches - directly seeding with both the low and high date ticks, as well as subtracting.
Private Function randomDate() As ULong
Dim rand As New Random(Date.Now.Ticks Mod Integer.MaxValue)
Dim holder As ULong = DateTimePicker2.Value.Ticks - DateTimePicker1.Value.Ticks
[code].....
My homework assignment is to create a project where a user enters a password that must be at least 3 characters long with at least 1 number and 1 alphabet character. After that the password has to be encrypted so that vowels become X, numbers Z, and it reverses. For example, a password of CS2301 would be ZZZZSC. There's supposed to be Loops to extract 1 number/letter at a time and search for them in the string to validate, and I don't know what to do. The form itself has a Text Box to enter a password and a label to display the new one, and a Go button.
This is what my code looks like so far.
Option Strict On
Option Explicit On
Public Class Form1
[CODE]...
How can I generate a random string of 8 numbers and letters?
View 8 RepliesI have to (for class) make a program that generates a safe passwords for people to use. My teacher wants us to make the passwords vary in length, include numbers, letters and upper case letters. I've been able to write code that prints out a random string but it includes unrecognized characters for most passwords. How would I write the code to create a random string that has parameters? (in this case upper case lower case letters and numbers).
View 9 RepliesI made a small license generator app with a datetimepicker, a textbox and a button on the form. When I ran the app and clicked the button to generate a license I got - 16DDD-06DDDD-09DDDDD, and each subsequent button click would get me a license with a different generated character (16444-064444-0944444, etc...).
I thought this was unusual as it should be generating a random character not a repeating one, so I stepped through in debug and the characters generated were random (161g2-06T5ip-0957H9k). I thought perhaps that I needed to seed the value with Now().Milliseconds, no luck, that still resulted in repeating characters. So I tried sleeping the thread and that generated the random values I wanted.
[Code]...
I have a program that requires a string. The string is 20 characters long. The string also have to be split into 2 words the first word is 12 characters and the second is 8. If the strings is not 20 characters long I get an error. I wanted to know how can I get the program to start back over and let me enter another 2 more words if the string is not 20 characters long. At the moment after I get the string is not 20 characters long error it continues to read the rest of the program but I want it to stop after an error and let me start over from the beginning.
View 3 RepliesI have a task to resolve, it is regading extracting characters from a long string to the console, the extracted text shall be reformatted and saved into a CSV file. The string comes out of a database.
It looks something like: UNH+RAM6957+ORDERS:D:96A:UN:EGC103'BGM+38G::ZEW+REQEST6957+9'DTM+Z05:0:805'DTM+137:20100930154
The values are seperated by '.I can query the database and display the string on the console, but now I need to extract the Keyword 'ORDERS' for example, and lets say it's following 5 Characters. So the output should look like: ORDERS:D:96A then I need to extract the keyword 'BGM' and its following five characters so the output should look like: BGM+38G:After extracting all the keywords, the result should be comma seperated and look like:
ORDERS:D:96A,BGM+38G: it should be saved into a CSV file automatically.
I tried already:
'Lookup for containing KeyWords
Dim FoundPosition1 = p_EDI.Contains("ORDERS")
Console.WriteLine(FoundPosition1)
Which gives the starting position of the Keyword.I tried to trim the whole thing around the keyword "DTM". The EDI variable holds the entire string from the Database:
Dim FoundPosition2 = EDI
FoundPosition2 = Trim(Mid(EDI, InStr(EDI, "DTM")))
Console.WriteLine(FoundPosition2)
I need to know how to use a function to do the following: Create an invoice number using the last two letters of the last name and the first four digits of the zip code.
Example:
Name: John Doe
Zip: 11111
Invoice number becomes DO1111
I have encrypted a string to something like this:
1. Asak2$)kla1015QAXKFskfa332aSJ2(Ska@Skljcmcel3p.lq,aowpqaskla2@)Skx.:Pdm^),dfs;
what i want to is convert this string to something like this
2. JXK2LB AP2WXB S1P0XE ZXPA3H X1LAKW DOXPS3
both 1 & 2 the above strings are fictitious (i made them up to make my point clear)
I am trying to make a licensing system for my VB 2010 express application. (2) above will act as a serial key which can be derived from (1) which is an encrypted form of something unique of the client computer.
I will then confirm the (2) from the client.
i have errors while creating
View 13 Replieshow to create random characters in vb8
View 10 Replies[Code]...
For each character of this string I want a new character out of the string and then remove the character from the list of characters that still maybe used for other characters. It may not get the same character, you could basically just call this encryption, but it's not what I am making. I don't want to waste my time doing this one hour while VB can do this for me in <1 second.
i wanted to create a random number generator that iterates through a series of number between an upper and lower bound. say between 1 and 100. Basically I want the number generator to pick the numbers randomly and then display them until all 100 numbers are picked without any duplicates. so thats easy I can code that. But what I don't know is how to show those numbers in the order they are generated on a windows form. So i have basically a variable that I will let be changed 100 times (or however many times I want, I don't want their to be a size constraint just using 100 as an example) and each time the number is generated I want it displayed on screen (in a list or something not sure what. Hopefully some type of scrollable list) and each successive number also to be displayed in same format beneath it so that I can see the list in its entirety. What type of form control do i use for that? I could do messagebox.show for each iteration but then user is required to hit ok after each iteration and that would obviously be a bad idea if user selected a large number to work through. Anyways, code isn't exactly necessary just point me in the right direction, i.e.what control (if any) to use.how to format the change in data?
View 7 Repliesis there a code for generating random letters and numbers?? like between 0 to 9 and A to F??
I used this code :
[Code]...
I am using Visual Basics 2008 Express edition. I want my program that I am making to generate a random amount of numbers and letters in this form when I click Button1.
WM9RX-GG6J2-4WKD9-FDJWM-TYH76
Is this possible?
I have a query to solve for which I have coded. But my code produces output only for those hardcoded values found in the text file. I have a text file which is given as the input to my code. The text file contains lines with "_DIA" , "_DIA_some number" etc. In this case I need to remove few letters from that field.
Eg: 1)if the name field contains 1234567_DIA_2.PRT, I need to remove "_DIA_2" from the name field and concatenate the .PRT with the number. 2)if the name field contains 1234567_DIA1.PRT, then remove "_DIA1" and concatenate. I need to store the number of characters removed and add so many number of blank spaces with the name field after the concatenation.
for the 1) case I need to concatenate and add 6 spaces with the name field. for the 2) case I need to concatenate and add 5 spaces with the name field.
I'm not sure how to find the number of characters from "_" to ".", underscore need to be considered in the counting and the dot(.) should not be taken into account.
Say I open a text file in a richtextbox control. After that I search for a specific string like "6.1". The string actually continues like "6.1XXXXXXX". I need to get not just only "6.1", but also 2 more chars after "6.1", like "6.1XX". I will then output this in a textbox, but I can do that, I don't know how to get the X number of characters.
View 4 RepliesI'm attempting to modify some random password generator code, and wanted to do something a little different. I would like to list all uppercase, lowercase, numeric and special characters next to a text box. In the four text boxes, you would select how many characters from each set you would like in your password. For example 4 uppercase, 2 lowercase, 3 numbers and 2 special characters. That would generate a random password 11 characters long. I can generate random passwords now, and have included a text box which allows the length of the password to be specified, but i would like the granularity of selecting from each set.[code]
View 7 RepliesI need to create a random number genrator to generate a membership number when i open my sign up form. i need it to be shown in a text box.
View 9 RepliesCan give me coding to create 6 random number in single word.. .For information i am using this coding to create serial number. This coding will use to generate 6 different number as output.
View 4 RepliesIs there a function in VB.net that allows me to divide a really long String into a specific number of characters? [code] The length of this string is 18 and I'd like to group it by 3, so each group would contain 6 characters. Is there an easier way of doing this? Is there a predefined function in VB.net? I'm already thinking of doing it manually, like converting the string into characters and storing them inside arrays.
View 1 RepliesI want to create an array V0(9) using random number generation. For example I generated V0(9) = {1,2,3,4,5,6,7,8,9,1} I want to use 12345 + 67891. How can I separate to use two parts of the array.
My
Public Class Form1
Dim i As Integer
Dim V0(9) As Double
[Code].....
Does anyone know how to do the following:Get a string with with random characters and numbers in it?I want the string to be 6 characters long.
Basically, when a button is clicked, i want to fetch random letters and numbers and assign them to a string.
I need to format a string in a fixed number of characters.
For example, if someone type TWO
It has too save in the variable
000TWO
if type THREE
0THREE
Always 6 characters and fill the rest with zeros on the left.