Get The Program To Start Back Over And Enter Another 2 More Words If The String Is Not 20 Characters Long
Sep 27, 2009
I have a program that requires a string. The string is 20 characters long. The string also have to be split into 2 words the first word is 12 characters and the second is 8. If the strings is not 20 characters long I get an error. I wanted to know how can I get the program to start back over and let me enter another 2 more words if the string is not 20 characters long. At the moment after I get the string is not 20 characters long error it continues to read the rest of the program but I want it to stop after an error and let me start over from the beginning.
I am trying to strip the first 75 characters from various strings (sentences / phrases) and it seems right but I need to ensure that the now words are truncated in the process. Meaning that if the 75 character is part of a word it needs to fall back to the beginning of the word or nearest space..
I thought of stripping the entire string into separate words and then counting the length of combining the words and stopping when I reach the target but what do I do in the case when it is not a valid sentence just a bunch of characters jammed together. I thought of using grammar parsing tool libraries and parsing into tokens etc but that seems to over complicated.
if text.length() > 75 then ctext = text.remove(text.length, 75) & "..." endif
I put elipses at the end but using the above I also get the error:
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I have an HTML string and in that string are certain variables that I need to replace with database values. The variable names are dynamic but all begin with the characters "@@" (just two ampersands, no quotes). Is there a way to get all the words in a string that start with "@@"? I'm assuming you would use regular expressions, but not sure how to begin.
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I have a task to resolve, it is regading extracting characters from a long string to the console, the extracted text shall be reformatted and saved into a CSV file. The string comes out of a database.
It looks something like: UNH+RAM6957+ORDERS:D:96A:UN:EGC103'BGM+38G::ZEW+REQEST6957+9'DTM+Z05:0:805'DTM+137:20100930154
The values are seperated by '.I can query the database and display the string on the console, but now I need to extract the Keyword 'ORDERS' for example, and lets say it's following 5 Characters. So the output should look like: ORDERS:D:96A then I need to extract the keyword 'BGM' and its following five characters so the output should look like: BGM+38G:After extracting all the keywords, the result should be comma seperated and look like:
ORDERS:D:96A,BGM+38G: it should be saved into a CSV file automatically.
I tried already:
'Lookup for containing KeyWords Dim FoundPosition1 = p_EDI.Contains("ORDERS") Console.WriteLine(FoundPosition1)
Which gives the starting position of the Keyword.I tried to trim the whole thing around the keyword "DTM". The EDI variable holds the entire string from the Database:
Dim FoundPosition2 = EDI FoundPosition2 = Trim(Mid(EDI, InStr(EDI, "DTM"))) Console.WriteLine(FoundPosition2)
I'm making a program and was wondering if someone could please help me (its a console app) to display words from a string that the user has inputted starting with certain characters?
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prefixes are not always two chrachters for example can be TOW
SELECT * , left(prod.productcode, LEN(sup.prefix)) AS MyTrimmedColumn FROM MSLStore1_Products prod ,supplier sup WHERE prod.suppid = 9039 AND prod.SgpID = 171
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GroupName.Substring(0, 3) = "jt_"
....if the length of GroupName is less than 3 characters. I always thought it would simply return whatever characters in GroupName, but no, it errors. I must be thinking of the old VB6 days.So, I now have to change the code to:
If (GroupName.Length > 2) Then If (GroupName.Substring(0, 3) = "jt_") Then
Note that the two comparisons need to be on separate lines. If they are on the same line, such as:
If (GroupName.Length > 2) and (GroupName.Substring(0, 3) = "jt_") Then then the code will still fail as the length command is executed at the same time as the substring command- which will cause the error when the GroupName length is less than 3.Just thought that those of us not aware of this should be!
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Here's the code:
Private Sub Timer1_Tick(ByVal sender As System.Object, _ ByVal e As System.EventArgs) _ Handles Timer1.Tick
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Code: Dim onecharacter As Char Dim Enter As String
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