I'm trying to make a program to send a command through a textbox when a button is clicked, THEN grab the output and put it into another texbox. If you could help i would be great full. This is what I have so far....
Public Class Form3
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Shell("C:DFUs-irecovery.exe")
[code]....
what i am trying to do rather than having all my project files all around my documets is put them into one program by having a log in system that i have made sucssefully and at the moment i have it set out with 10 buttons and for button one i want to open my version of notepad from the debug file in the bin folder there is a .exe program that is the one i want to run i dont know if it is possible but when i came to coding button 1 i coded
dim openfile
("C:Documents and SettingsPeteMy
DocumentsVisual Studio 2010Projects
otepad
otepadinDebug
otepad.exe")
but i got a error like this and i tried this as well
Dim
open
As
New
[code]....
but at the first backslash i got a syntax error
How do I make a textbox appear inside rich text box by clicking on a button. I want the new textbox to appear where the cursor is
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[Code]...
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it says error as "Object reference not set to an instance of an object."
i've done this in my code
Protected Sub InsertButton_Click(ByVal sender As Object, ByVal e As System.EventArgs)
Dim receipt As LinkButton = FormView1.FindControl("LinkButton1")
' receipt.Enabled = "true"
[Code].....
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[code...]
I also need to know how to make the same button create a folder to save a txt file in. I havnt yet figured out how to save changes made into my program, that way next time i open it, i can continue where i left off.
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View 1 RepliesI have a program that needs to see if it is already running and if so bring the other instance to the front and then close itself. Now I figured out how to see if another instance of the program is already running using GetCurrentProcess, but how do I tell the first instance to "BringToFront" from the second instance?[code]...
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I seem to repeating lines of code but changing one thing each time on page load
Dim Sname As String = Request.QueryString("Name")
lblStuName.Text = Sname
tbStuName.Text = Sname
tbStuName.visible=false
[Code] .....
On edit button
tbStuName.visible=true
tbAddress.visible = true
etc..
On the save button
sqlStatement = "UPDATE StuTable SET Name = '" & lblStuName.Text & "', Address = '" & lblAddress.Text
My code seems very repetitive in many parts, I was looking for a better coding style to do this.
want to make the text in the textbox control disappear when clicked
View 6 RepliesImports System
Imports System.Windows.Forms
Class MyButtonClass
[code].....
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View 6 RepliesI'm trying to do is make a program to where when you click an option, a text outputs for each button clicked, the general design looks like this:
That's just a beginning, since the whole rest of the thing will be the same concept pretty much, and what I want to have it do is, like stated earlier, once the option is chosen, a text output, like this:
I know there is an alternative to solving that, but it will take me 10x more time, and that is, creating a new textbox, setting the visibility to False, and typing what I want outputted in that text box, then putting: RichTextBox1 = TextBox1.Text
I know that works, and gives me my output, but I just wanted to know if there was any other way but that.
If e.CommandLine.Count > 0 Then
Dim IncomingCommand As String = e.CommandLine.Item(0).ToString
If IncomingCommand.Substring(0, 2) = "-1" Then
form1.close()
End If
End If
I am trying to make the program close if the -1 string is sent with the program. See my installer allows for me to run certain programs before it actually installs, but it doesn't shut down copies of the program itself. So I have a next startup instance set to shut the program down if the -1 is received. But if the program is not running it starts up instead. This is not desired. form1.close doesn't work. e.cancel = true doesn't work, etc etc. What can I do to make the program not start during this instance.
I want to run a dos command with a button and the output need to come in the outpud textbox.the only problem is that i need to give another option in the dos command, how can i do this?This is what i use. but how can i give the second command in that command that is already running?
Private Sub CMDAutomate2()
Dim myprocess As New Process
Dim StartInfo As New System.Diagnostics.ProcessStartInfo
StartInfo.FileName = "cmd" 'starts cmd window
[code].....
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I am trying to send a command to a command line and then submit the command. I have been trying without success to get this to work in v2008 Express and v2010 Express, Here is the code I am trying to us:
Private Declare Function FindWindow Lib "user32" Alias "FindWindowA" ( _
ByVal lpClassName As String, _
ByVal lpWindowName As String _
[Code].....
How to make my form bigger with a click of a command button?
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View 8 Replies
