I'm trying to code some programs and i want to use something called " (its in the dialog menu) FileOpen.dialog" i think thats what its called. Anyway i was seeing that if i just clicked on the OpenFile dialog it wouldn't open the file. So i knew i needed a code. I just dont want the OpenFile dialog i was just using that for example.
View 6 RepliesFor some reason I can copy a file from a OFD box from anywhere other than my desktop.Could it be because I'm using the shell command and the file path contains spaces?I've declared the filepath as a variable. I know in a batch file you have to enclose names with spaces in "".
CODE:
Dim filename As String = "cmd.exe"
Dim p As System.Diagnostics.Process = New Process()
[code]...
Specification:A library application maintains a list of all the DVDs, this list is populated from an input text file which is also saved as an output textfile.The filename used is myDVD.txtNeed to write code for a Method SaveDVDFile() - the condition the method should fulfil is - that if the filename is a valid path for the text file , this text file is saved such that each line in the text file has an entry for 1 movie name. Is my pseudo code correct?
aFileName as String
aWriter As StreamWriter
set FileName To
[code]......
I have created a (kind of) 'Desktop' Form for the main basis of my program. Basically it is made up of 3 panel controls.
1. Holds all buttons which load the different forms (Like the windows start menu when expanded). name: StartMenuPanel
2. Holds Information on log in deatails. name: LogCheckPanel (very thin panel at top of screen)
3. Main panel which takes up the majority of the screen (where I want the forms to load). name: MainPanel
My aim is: When a button is clicked from the 'StartMenuPanel' the form will load with-in the 'MainPanel'.
I tried changing the start position to 'centre parent', but the panels are in the way so some of the childform is overlayed by the panels.
[Code]...
When I run this I get the following error: 'Top-level control cannot be added to a control'.
I hope I've explained this well enough.
I am using vb.net 2003 and an Access database connected via Jet 4.0 OleDb. I have identified the location of my database using a relative path with [code]My program was working fine and I began making some cosmetic changes.I thought it would be a nice touch to add a PictureBox on the first form and allow the user to select the image that he would like to see when running the program.I added a menu item to "change the picture" and on a form added an OpenFile Dialog. I added code to capture the location of the selected file and used it to identify the image to be shown.I included a table in my database to store the file name and path which is loaded when the program starts.This all worked fine. I could change from picture to picture and the image would be updated each time in the picture box and in the database. I could access the database and perform all of the functions of the program.
That is as long as the image files that I selected were located in program startup directory. If I selected an image with the openfile dialog which was located else where then I could no longer contect to the database. I receive an "unhandled exceptions error". Below is the openfle code:[code]Can anyone help me with the proper way to get set up the open file dialog so that the results do not conflict with my database connection, or re-establish the connection?[code]
VB beginner here. Just wondering about what code to use when using save file dialog for the user to select a directory to save information made on a program. My open file dialog code works fine but i have tried some save file dialog ideas i found online to no avail.In this case, i just want text that is written in text boxes in my program to be saved to something as simple as .txt's.
View 1 RepliesI am using vb.net 2003. In my program, the user can use an openfile dialog box to locate the address of a image and use it to change the display. The name and path of the image is saved in a database. This image is then loaded upon startup. If the image is located in the start-up directory the image change and saving to the database works great. But if the image is located some where else the image change occurs, but the path of the database has changed to the location of the image. Since the database is not located there, I get an unhandle exception error. What is the code to redirect the program to my startup path?
View 5 RepliesHow to change the database connection by using openfiledilog in windows forms? The application I need to do, need to connect to a database, each time with different path and different name to explore the opened database. All the databases to be accessed are having the same structure, but with different location (in the pc itself), different name, and with different data inside (but the database tables and relations are the same. I understand openfiledialog.filename contains the address for the clicked file, but failed to pass this information to update the Database conection with the new addrerss.
View 8 RepliesI'm currently creating a system for medical record for our school project?i always get this error " Couldn't find 'C:/User/...' " i coudnt retrieve the filename of the picture so that i can store it in my database , BUT when I try my back up file it works .it save image in the Database It's the same code , i did not change anything here is a part my code..
Private Sub MDISaveToolStripButton_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles SaveToolStripButton.Click
If Not didPreviouslyConnect Then
MsgBox("Connecting to database")
[code]....
I'm trying to read and learn the save file dialog coding.[url]....
View 5 RepliesI have a program that in its essence is this:
Public Class Form1
Sub CopyUtility_Load(ByVal eventSender As System.Object, ByVal eventArgs As System.EventArgs) Handles MyBase.Load
[code]......
I've noticed that when you click on a web page in Windows Explorer, or open a file in general, and the default application to open it is internet explorer, ie opens and opens the file. However, when I tried this on my Web Browser it opened, but ignored the file and went on its usual routine. How can I get my Web Browser to open and open the file that was clicked on in explorer?
View 1 RepliesIs there any way I can get around of the apparent issues of using the basic file saving dialog to at least allow another way to save files from my program?What I am talking about is possibly a way to be able to drag something from the program to somewhere on the PC saving it there. I know of a few possible ways to get this done already but the ones I know of aren't exactly great, I could stick with the basic save file dialog but it's a bit slower than you could likely do with simple drag & drop file saving, while then I have to do my own code so files that are allowed to be named to have the special characters like "?" which aren't allowed in filenames in windows will be replaced with different characters instead.
View 7 RepliesI already have this code from another question on this website.
Help.ShowHelp(ParentForm,
("C:UsersBeaudeanDesktopHelp.chm"),HelpNavigator.TableOfContents, Nothing)
That works fine except i need the location of the chm help file to point to "my.resources" where it exists because i need to install my program but in that code example it only works with strings?
i've made a little app that opens .txt files kind of a replacement for notepad now i have set the install package in visual studio to associate .txt with my app however when i double click on .txt files my app opens but blank. so i'm assuming i've gotta code something to get it to open the clicked on file but.... haven't got a clue where to look for inspiration or code i can "borrow" and chop to fit my needs. i assume it's got to be in the load section of the program.[code]
View 6 Repliesattch a file in .net application,which can open from the form on clicked..
View 4 RepliesHow do i make it that when i hit a button file dialog opens and i can select a text file from my computer
then output the text file into listbox1.text
I need a code for the open file dialog that if a file is not supported then a message box appears stating the error. This is my open file dialog code. [code] The message box pops up like it is suppose to, when you click ok the open file comes back up like it is suppose to. When you put in the correct file the message box comes back up again. Also the message pops up even if the correct file is put in the open file. but if you close the file dialog the image is where it is suppose to be.I believe the code for the public sub wrongfile is what is the problem. can some one look it over and let me know what changes are needed.
View 7 RepliesWhat i am trying to do is open a save file dialog and write to a .txt firl the contents of my listview. so far:
[Code]...
i have this, but i'm not to sure how to write to the .txt file i know i need to use a for each to loop the contents of the list view
I have a checked list box that is populated with the text from a text file. I started off with this code:
Dim FileToLoad As String
FileToLoad = TextBox3.Text
Dim fs As FileStream = New FileStream(FileToLoad, FileMode.Open)
[code].....
code snippet that would allow a progress bar to track the input of a text file? Normally I would not bother with this, but the text files are > 10,000 lines long, which is noticable even on a fast machine. The number of lines is variable, so I would assume that one would not use a fixed value to calculate when the progress bar goes 100%.
View 4 Replieshow do i return the file path to a variable when using open file dialog to browse and open a file?
View 14 RepliesI am trying to open a Dialog box to select a file. I then need to drop that value into a FileStream StreamReader to read it so the combo box will show a list of values in the selected .ini file. I've got pieces of it but I am not sure of the glue that will connect the two. I am posted what code I have below.
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
Dim FileParser() As String
[Code]....
I type in openfiledialog1.showdialog() and it says theres in error when i have a openfiledialog on my form Please Respond Quick
View 3 RepliesI have code that fills in a webbrowser form selecting pdf files to download. The files are then requested with:
Private Sub Button3_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button3.Click
[code].....
I have completed the vb tutorial on
[URL]
and have successfully got a file name from the open file dialog when coded as part of the "Public Class Form1" -> Private Function btnOpenXML_Click function that was generated automatically by vb. The openFD was generated by adding the OpenFileDialog to the pane underneath the form.
Private Function btnOpenXML_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnOpenXML.Click
Dim strFileName As String
[Code]....
I'd like to move this code to a module so that it does not clutter my main form1 layout.
However when copy the code to a new module, the openFD is not recognised.
how to I re-declare this openFD or pass it into the function so that it can be used?
I'm trying to display the file path of the file I select using an OpenFileDialog box in a text box on my form.
View 3 Replieshow can i specify dynamically by using open file dialog box
View 1 RepliesFile I/O and Registry :: VB newb Open File Dialog
View 2 Repliesim making a simple program that will copy a single file. im trying to get the name of the file that i selected in the open file dialog but i get the location and file name (C:Users****Documents est est.txt) im trying to just get (test.txt)
View 2 Replies