Use .next (random Numbers) To Randomly Select Something From A List Of Numbers But It Can't Repeat The Number?
Aug 16, 2009
So how would I use .next (random numbers) to randomly select something from a list of numbers but it can't repeat the number?I could do:
dim num as integer
dim r as new random
num = r.next(1,5)
if num = 1 then
elseif num = 2 then
etc.
That wouldn't work because it would repeat.If I donwload someone's game can I disect it in VS? :0 I tried going to open project, then I went to the folder and clicked open. It brought me inside of the folder so I tried to open the game but there is no form1 there. It says the games name then .exe in the explorer-like thing in the top right?Also, how would I have a value or something in a label and access it from a button.
Example:This is in a label.
Dim number as Integer
number = 0
Then in the button do
Label.number = 0
How would I do something like that? I want to use that a lot as I did in a different language.
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Mar 6, 2011
I have just about completed a .NET project to write a program to randomly select numbers for a Bingo caller. Over the last month or so Ive learned a lot about .NET but heres something that I consider to be odd and maybe one of you guys can offer an opinion.
One of the features of calling Bingo in a small local club is that callers often use little sayings to accompany certain numbers, I expect youve all heard of (say) All the sixes, clickety click for 66 or 5 and 9 the Brighton line for 59 etc. My little program gives an option to incorporate these with a prompt for the caller that can be edited outside of the program. One of these conventional sayings is used when a number is reversed 12 followed by 21 or 45 followed by 54 for example, when the caller might call (say) 1 and 2, one dozen, number 12 And the other way round 2 and 1, twenty one.
So, I programmed in a bit of code to detect this and to over-ride whatever might otherwise have been the quote with And the other way round and set about testing it. Ive been through literally dozens of full 90 calls watching for the occurrence of a reversed number, spent a few hours doing it, and not once has it occurred which is to say the least, unusual.
So, Im wondering about the Rand Function, could it be that it isnt possible for a reversed number to be selected? Just so you know, I randomly pre-select the order of all 90 numbers, I fill each of the 90 elements of an array with a random number first checking that the number selected hasnt already been stored, if it has, I just get the next random number (and check that too of course), but I cant see how that could prevent reversed numbers being selected, especially in light of the fact that frequently it's not the 'next' number that's used.
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Apr 15, 2009
If I have say 5 numbers: 1, 29, 53, 95, 103 What would be the VB.net code for randomly selecting a number of those 5.
i.e) The random number has to be 1, 29, 53, 95, or 103 and has to be randomly generated.
I've tried using the Int(Rnd() * 104), but I do not know how to make it choose only these 5 numbers!
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May 20, 2012
getting random number from list of numbers is getting me sick. i am trying to do it for like 20 days now but every time i do it ends up in a loop wich crashes the my.settings system. does anyone have an idea how to get a random number from a list. then delete that number so it cannot be called again. my system must mark some items with numbers but non ofthe numbers may be used more then 1 time the max items in my system is 90. so from 1 to 90 without getting 2 times the same number heres the code i tryd
[Code]...
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Oct 14, 2009
I have done this code but what is a smart way to get rid of repeats?
card1 = random.Next(0, 52)
card2 = random.Next(0, 52)
card3 = random.Next(0, 52)
[Code].....
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Mar 16, 2011
Below is a form which produces a graph, the idea is to produce 6 random numbers from a range (0,6) place the numbers in an array then use these numbers to produce columns on the graph, however at the moment it is using the numbers more than once, how can I get it to just use the values once only in the array.
Private Sub btnGraph_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnGraph.Click
txtAns.Text = ""
g.Clear(Me.BackColor)
g.DrawLine(Pens.Black, 50, 70, 50, 420)
[Code] .....
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Dec 2, 2009
In a project I'm working on, I've assigned each user a unique ID with the following code. [code] However, I want to replace the number at the end (RecordCount) with a randomly generated sequence of 4 numbers (no 2 can be the same).
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Mar 25, 2012
Beginning VB 2010, had a project that requires us to create a list box of 25 randomly generated 0s or 1s. Problem is when I put the loop in, it only repeats the same random number, not different one each loop. What am I doing wrong?This is the code I have so far...Code in Question:
'Declare new random object
Dim RandomGenerator As New Random
intRandomNumber = RandomGenerator.Next(0, 2)[code]......
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Oct 28, 2009
I have an array of integers like these; dim x as integer()={10,9,4,7,6,8,3}.Now I want to pick a random number from it,how can I do this in visual basic?
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May 8, 2012
i need a simple way to get a random number from 2 numbers. This means that for example if my 2 numbers are 3 and 7, i don't need a random number between 3 and 7 that would be like 3,4,5,6,7 but only a random that is either 3 or 7. Meaning not all the numbers between x and y, but either x or y.
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Feb 26, 2012
I'm so confused. Please help me with this program. My teacher wants Receive a lower bound and an upper bound of a range.Also receive a number of random numbers to generate.Generate this many numbers in the specified range and keep track of how many are even, odd, negative, 0, and positive. Do not save the numbers, just the category counts.
Lower bound must be less than or equal to the upper bound (negative or positive or mix).Number to generate must be greater than or equal to 1.Use the GetInput Boolean function (written in class) to retrieve the numbers for data validation, however it must be changed from Double to Integer. Then use additional functionality to test whether they are in the specified ranges. For example, if you successfully GetInput for LB and GetInput for UB, then test LB <= UB. If successful, continue with GetInput for Number to Generate and check >= 1.
[Code]...
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Oct 6, 2011
The program must generate 6 unique random numbers but when I click display numbers sometimes it gives me 6 unique numbers and sometimes I get duplicate numbers. I will add the code I have so far.
Public Class frmMain
Private Sub btnExit_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnExit.Click
[CODE]...
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Apr 1, 2010
I am trying to write a random number function that can just be called from my main module to generate different random numbers. I have tried this several different ways and I am having odd results. Approximately 19 times out of 20 the numbers come back exactly the same, but approximately 1 in 20 they come back as two different numbers. Im using Visual Basic Studio 2008. Here is the code I have so far, or rather, the current version of my many tests I have been running to try and figure it out. Sometimes it takes many runs of the program before the two seperate numbers apear.I've been researching it and have come up with nothing so far.I know I could put them in the module section as two different randoms and it works, but I get extra points if i use a couple classes in my program.This is the main module.
Module Module1
Sub Main()
Dim randomNumOne As New RandNum[code]...........
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Apr 13, 2011
I basically have a .avi file that speaks numbers (random number only). Want I want the program to do is:
1. Load up the .avi
2. Play the .avi and write down the numbers that are begin said.
3. Write them in a textbox / notepad
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Nov 23, 2010
Right so my generator is working, but I now want to take the numbers that it generates and add them to a list of generated numbers. So you can monitor what numbers have been generated. then ideally a way to exclude these numbers from being generated again.
[Code]...
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Feb 22, 2012
I'm creating an application that creates a list of 20 ramdomly selected numbers within an array and displaying those numbers in a listbox. I then need to display the duplicate numbers in an adjacent listbox by clicking the find duplicates button. How would I be able to access those 20 numbers in order to find the duplicates?
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Aug 23, 2005
I'm realy green when it comes to programming but I like to think I am learning quickly. However, I cant figure out how to generate a number of random numbers baised on the vailu of a numeric slider. So for example I am generating a number between 1-12 where each point of value for the slider would generate an indiigual number that can all be added to a final total. I would also like to be able to back the slider down to a previous number and have the same total I had last time I was at position x. This is what i have so far:
[Code]....
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Feb 19, 2011
Im working on writing a program for doing standard deviation and as of right now im running into one slight issue with subtracting my mean from the original numbers. I will post most of my code so you can get an over view but i mostly just want help on this one little part for now. Im going to be making a website for school and put some programming stuff on it so i wanted to make just some random programs for it so this is school related but not really homework. It's line 26 and 27 that this is relating to. When i put a stop in my code and look at the result of arrayDifferences it gives me 0.0 when it should be -1. I know i can go this route and say arrayDifferences(1) = arrayDifferences(1) - arrayAvg but seeing as how i want this to be a random number of numbers input by the user i cant do that.
CODE:
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Feb 15, 2012
am writing an system application for a company that must generate inquiry id and order id automatically. Whenever a customer makes a new inquiry or new order by clicking the add button, an automatic number should be displayed in the text box and when it's saved, it should be saved in the database access.
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Aug 18, 2009
I would like to know how I can have an enumeration that has multiple values and can be passed to a function.
Example:
Public
Enum
ActionEnum
NoAction = 0
[code]....
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Jan 10, 2010
Basically, I want to divide two numbers together and they should be 2 random numbers from 1-12 (I have done that part) but, the answer should be a whole number (i.e. Integer, so no decimal points etc) So, I did the following:
' Initialize the random-number generator.
Randomize()
' Generate random value between 1 and 12.
Dim value5 As Integer = CInt(Int((12 * Rnd()) + 1))
[code]....
but the problem here is that the program crashes after only a few clicks on the button. So I guess the question is: How can I make the program generate two numbers (from 1-12) that when divided become a whole number?(Is there any code that may tell the random generator that I want the numbers to be even?-so all even numbers from 1-12?)
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Feb 21, 2009
I'm having trouble using the Random class. I have this [code]...
I have this code in a function and everytime I call it it return a random number. The problem is I only want the number to be return/generate once. There be times I call the function and it returns the same number as in the pass. Is there a way to random the number once? I know in C++ you use like "Seed" or something and it will only generate once.
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Aug 2, 2009
I would like to generate a random number less than 50, but once that number has beengenerated I would like it so that it cannot be generated again.
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Apr 14, 2010
I am making an application that randomly generates numbers. I then have to find out if those numbers are even or odd. Then place them in the corresponding array ( EvenNumbers() or OddNumbers() ). Then display the random numbers array then the even and odd numbers array. I am up to the point where I have the generated numbers and can tell if they are even or odd, but can't get them into an array. I am trying to do it like this....
[Code]...
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Jan 15, 2010
How long it would take to generate all of the numbers between 1 and X randomly.
X=1,000,000 took 6 seconds, and for 10,000,000 took over a minute.
Does that sound reasonable?
Experiment
stopwatch start
count = 0
do while count < x
select a random number between 1 and X inclusive
have i selected this number before?
no-add 1 to count
yes -
loop
stopwatch stop
display elapsed time
I made the Do Loop UI un-friendly and ran this from the IDE using CTRL-F5. My PC is 1.8Ghz and has 2GB of memory. I am using VB 2008, .Net 3.5 SP1.
Looking for work - Zip 65101 [URL]
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Jan 8, 2010
What's the fastest way to randomly generate numbers, either randomly or simulating random? I don't really need a true random number generator, it would be acceptable to simulate random. I tried other random simulation methods but none were faster than this. Here's the fastest way I have now:
[Code]...
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Apr 4, 2010
The class Random is out right defective. It always produces the same random numbers in the same sequence. Things I have tried so far is every kind of seed you can think of as well as Randomize. The result is that I always get the same random numbers in exactly the same sequence.
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Nov 17, 2010
This code raise the FTP server files
[Code]....
Now I want to know how to do the following:
1. Select a maximum size per file
2. Promotion system randomly choose a name (with numbers and letters - at least 5) Then the program will show me a link to a file after uploading (for example: [URL] in TextBox2.text)
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Jul 3, 2009
i want to know how to generate 7 "differents" random numbers.
I need to use a tab() with 7 entries and verify(with a loop?) if the generated number is or not present in the the table, if not then increment a counter by 1 and add the number in the table and increment the table position by 1 for the next randomized number.
Im not sure how to do the verification, so far all i have is a function i made for the random number between min and max:
Private Function randGen(ByVal min As Integer, ByVal max As Integer)
Dim random As New Random()
Dim i As Integer
[Code]....
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Jul 11, 2009
I want to get random numbers between 0 to 100..But i do not want the random number to be repeated.
Private Sub Form2_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
Dim objRand As New Random
objRand.Next(0, 100)
End Sub
Suppose first time random numb generated is 10..Next time if same random number is generated,den i want to get the other random number..I want to get all the numbers b/w 1 to 100..but only one time
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