I have a long line of text to write to the console so I end up with the following code. Mind you, the IDE (VB 2010 Express) error list gives no error when the code is like this, it even build without error. However when the console runs the debugger gives me an exeption error.
[Code]...
Why must the line continuation character be the last one on the line? Is there a technical reason for this or is this a usual Microsoft "feature"?
In other basic dialects you can add a comment after it, but not in VB.net, so I'm curious as to why Microsoft decided to not allow comments on these lines.
As most of you know, .Net framework 4.0/Visual Studio 2010 supports implicit line continuation in VB, which was not available in previous versions (at least not to my knowledge). I have a situation where I am working on an ASP.Net 3.5 application that is targeting a machine that does not currently have .Net 4.0 installed and from what I understand it won't be installed for some time yet on that machine. Obviously, my development machine does have .net 4.0 installed.
With the implicit line continuation feature in VS2010, I sometimes find myself forgetting to add the continuation, and VS2010 does not have an issue with that even when I am targeting a previous version. Additionally, I know that if I actually compile the code (business objects and such), issues with line continuation are not a problem, as the compiled dll works fine as a 3.5 .net file.
My concern is this. There are areas where I am doing VB.Net coding in the code behind(beside?) for the asp.net pages. These would only be compiled on the server when they are first used, but since the server doesn't have the .net 4.0 framework (or even if it did), does anyone know if this would this cause the compilation to fail if I missed a line continuation? If so, is there a way to enforce using line continuation characters in VS2010?
I realize that some best practices might not be getting followed here, but I'm not about to change all the development dynamics around here just yet. Also, I'm not in an environment where I could easily test this out on my own.
i notice that when i start next line of code and i press enter, it recompacts itself and the continued line moves left a bit... then if i place focus on the second line and press enter again, it (the second line) moves to the left some more, and it keeps doing this every time i focus on second line and press enter. how can i make it so that my second (and third etc) lines are formatted in a pre-determined way so they are always a certain amount of tabs indented to the right from where my line 1 starts?
View 3 RepliesI have following simple code:
[Code]...
I suddenly started having a problem with .vb pages refusing to build in ASP.NET 2010. No errors were displayed but the Output window would display something like:
[Code]...
I am trying to error check a piece of code
This is from my previous thread which 'Codeoder' help me on..
[URL]
I have a RTB which I import with a set of 7 or 9 didit numbers, 7 for Staff and 9 for Students. e.g. Staff numbers
0628189
0628191
0629991
[Code].....
i have a text file which contain 3 lines "ha 0.21, hb 0.35, hc 0.44" I want to read the file and get the second character of every line, which are "a, b and c" and assign them to array. My code below able to read the file but only able to get the last line of text. May i know how to do to get every second character and assign to array?
Dim FILE_NAME As String = "C:Test.txt"
Dim TextLine As String
If System.IO.File.Exists(FILE_NAME) = True Then
[Code]....
i would like to add a character or characters, at the end of every line in a richtextbox..for example, add this ";o)" to the end of every line.[code]
View 5 RepliesI am kind of new to Visual Basic and I got stuck doing a sample Windows Form program. I was trying to write a String into a text file. But I just couldnt get the command for the new line character whereby each time, the new String is concatenated to the next line instead of the same line. I know that in C the new line character is used. But what about in Visual Basic?
View 7 RepliesI need to know how to get a characters Line position in VB 2005..I search for string of text throught a RichTextBox and get outputs like 4086 and 16010 for the character postion. I need to know what lines of the document these fall on, so that I can properly copy those lines.
View 8 RepliesI have a text file and i want to remove all the last character in each line how could i do that?
View 3 RepliesI have some text in a richtextbox and I would like there to be a new line after every
View 1 RepliesHere is an example of a line:
H e l l o t h e r e !
I want to delete every other character so that it looks like this:
Hello there!
I want to get the last index of new line character in the richtextbox
View 1 RepliesRetrieving strings from a serial port with ReadLine works fine as long as the line ends with a linefeed chr$(10).However if no more strings are available to be read, Do Loop or For Next hang up waiting for the linefeed which never occurs.I believe using chr$(0) in place of linefeed would still work with strings ending with a linefeed..Just that the linefeed would be output.I have the complete MSDN Library.
View 2 RepliesI'm trying to find a character in a specific character space, on a particular line, for instance:
Line 2, Charspace (or column) 75.
After I find that I would be writing a read and replace to change that character.
Can someone point me in the direction on how to specify this location?
I am creating an interface to control my av receiver, so far I can control it but now I want to receive the feedback from it and process it. The feed back I get is in the form of "!1PWR00"[End of line]. I am having a problem with the end of line part, what is end of line in VB? If I display the feed back in a message box it shows the end of line as a little arrow pointing to the right, how can I look for this end of line character in the datareceived in my code? CR is easy as it is simply vbCR. So what do I use for end of line?
View 5 RepliesCurrently I have the code:textbox1.text = textbox1.text.insert(textbox1.getfirstcharIndexFromCurrentLine(),";")But this means it has to reload the entire textbox, which with large files is noticeable slow.What are the alternatives?
View 3 RepliesI am making a program that loads files into a ListBox, loops through each one, and if the last line of the file begins with "@", it removes that last line.Now, I am not really sure how to do this.Would I use LineReader?How would I check the first character?
View 4 Repliesi want that when the user presses enter (ctrl+enter) in a datagridview cell the pilcrow sign will be inserted.is there any automated way to do this or do i have to catch the event and substitute the new line character with the ascii pilcrow sign ?
View 3 RepliesI have a program to read line by line from text file. [code]There is run time error while TextLine data has ' or "May I know how to read the data with ' or " character?
View 6 RepliesI get the following error:
Line 1: Incorrect syntax near ','. Unclosed quotation mark before the character string ' )'. at System.Data.SqlClient.SqlConnection.OnError(SqlException exception, Boolean breakConnection) at System.Data.SqlClient.SqlInternalConnection.OnError(SqlException
[code]....
Dim hex = "41"
Dim text As New System.Text.StringBuilder
For i As Integer = 0 To hex.Length - 2 Step 2
text.Append(Chr(Convert.ToByte(hex.Substring(i, 2), 16)))
[code].....
but yet this fails.. (the output isn't itself in a new line) what's the explanation for that?From what I know, doesn't System.Diagnostics.Debug.Writeline does something which looks like this:
System.Diagnostics.Debug.Write(input)
System.Diagnostics.Debug.Write("
")
so regardless of my input it should always have a newline char even if there is a terminating 00 char in my input?
This is another continuation of an issue with a List(of T) as a property of a class.Following the excellent advice of AtmaWeapon and others on this forum, I have my classes working fine except for something that is inexplicable to me.I initialize my "course" class at a public level in a module. This is so the data in the class will be available program wide and for the application's lifetime. "Public newCourse As New Course".I initialize a local instantiation of the class TimeTable as newTimeTable [code] This issue is: The List(of T) is populated with data, however, when the loop finishes, what I have is the last set of values repeated "X" number of times in the List instead of the data being different in each element of List( Of T). [code]
View 2 RepliesErrorComma, ')', or a valid expression continuation expected.
View 1 RepliesI need my VB.net to write a file containing the following line
objWriter.WriteLine ("TEXTA " (FILEA) " TEXTB")
Unfortunatly the variable (FILEA) is causing problems i now get the error
Comma, ')', or valid expression continuation expected.
I get this error at the second dot of the IP address specified in my connection string.
Error1Comma, ')', or a valid expression continuation expected.
The code is as follows:
Option Strict Off
Option Explicit On
Imports System.Data
Imports System.Data.SqlClient
[code].....
Several times while debugging a VB.Net program I have found that continuation lines are missing from a subroutine designed to handle an event. The continuation character "_" is there but the following line is missing
[Code]...
The first few times I figured I had made some editing error, but this has happened 3 times now, always in the same way (different subroutines but same place). As far as I can tell, no other continuation lines have changed. Is this a bug or some feature I have missed?
I am working on RSS feed. In Rssfeed <description> (string) tag suggest using approximately 300 characters and then showing continuation with [...] after a word break.
<description>Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, when an unknown printer took a galley of type and scrambled it to make a type specimen book. It has survived not only five centuries, but also the leap into electronic typesetting, remaining essentially [...]</description>
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How we can do with a string by showing continuation with [...] after a word break?