Save Data From DataGridView?

Aug 4, 2011

I am wanting to save row times from a DataGridView when a column button called save is clicked.

here is what i have so far;
Imports System.Data.SqlClient
Public Class Form1

[code].....

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Private Sub dgv_CellClick(ByVal sender As Object, ByVal e As System.Windows.Forms.DataGridViewCellEventArgs) Handles dgv.CellClick
curRow = dgv.CurrentRow.Index

[Code]....

I wish to copy only certain row data when user click on the cell and add in into 2nd datagridview when click button add.

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My code is this:
Me.Validate()
Me.CFTINVENTORYBindingSource.EndEdit()
Me.TableAdapterManager.UpdateAll(CFTDataSet)

At first I can insert data into the cells and save it... but when I try to edit the same cell with data already saved in it I get this error...
sqlcelexception was unhandled
There was an error parsing the query.
[ Token line number = 2,Token line offset = 29,Token in error = , ]
I also get the same error when deleting an already saved cell with data.

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I'm using VB Express 2008 in Windows 7 64-bit. I'm working on a project with a datagridview bound to a MS Access 2007 database. I want to use the datagridview to add, delete and update the data in the MS Access database. When I added the database file to the project through the Datasource Configuration Wizard, I selected 'No' to copy the file to the project folder. The connection string automatically placed in the project settings is: Provider=Microsoft.ACE.OLEDB.12.0;Data Source="F:My MoneyDoBillsDoBills2009.accdb"* The 'Copy to Output Directory" property for the DoBills2009DataSet.xsd is set to '*Do not copy*'(and I've tried every other setting available). So, as I understand it, I am working with the original file, not a copy, and any changes (additions, deletions, field changes, etc.) are made directly to the original file. I have added the following code to the datagridview rowleave event: [code]I'll figure out a way to skip the update if nothing is changed, but for right now, it doesn't work. I've searched MSDN, the MS Community forum and several other forums for a solution and all I have found is what I already have and it doesn't work.I can make changes at run-time alright, but the exception it triggered when I change rows, and the data is not saved to the database file.When I close/re-run the app, the changes to the data are not thereThere has to be a way to save changes to the datafile, but I'm just not finding it.

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I'm using VB Express 2008 in Windows 7 64-bit. I'm working on a project with a datagridview bound to a MS Access 2007 database. I want to use the datagridview to add, delete and update the data in the MS Access database. When I added the database file to the project through the Datasource Configuration Wizard, I selected 'No' to copy the file to the project folder. The connection string automatically placed in the project settings is:Provider=Microsoft.ACE.OLEDB.12.0;Data Source="F:My MoneyDoBillsDoBills2009.accdb" The 'Copy to Output Directory" property for the DoBills2009DataSet.xsd is set to '*Do not copy*'(and I've tried every other setting available). So, as I understand it, I am working with the original file, not a copy, and any changes (additions, deletions, field changes, etc.) are made directly to the original file. I have added the following code to the datagridview rowleave event:

Private Sub dgvSortBills_RowLeave(ByVal sender As Object, ByVal e As System.Windows.Forms.DataGridViewCellEventArgs) Handles dgvSortBills.RowLeave
Try

[code].....

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Dim Dr2 As New OleDb.OleDbCommand
Dr2.CommandType = CommandType.Text
Dr2.CommandText = "SELECT... FROM... WHERE..."
Dim Dr1 As OleDb.OleDbDataReader
Dr1 = Dr2.ExecuteReader

The above code was originally written in VS2003 to retrieve and display data from Access 03 database, and runs without error. In VS2010, this code is throwing a "Command Text was not set for the Command Object" error and points to the last line as the source of the error.

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I'm using VB Express 2008 in Windows 7 64-bit. I'm working on a project with a datagridview bound to a MS Access 2007 database. I want to use the datagridview to add, delete and update the data in the MS Access database. When I added the database file to the project through the Datasource configuration Wizard, I selected 'No' to copy the file to the project folder. The connection string [code]...

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I'm using VB Express 2008 in Windows 7 64-bit. I'm working on a project with adatagridview bound to a MS Access 2007 database. I want to use the datagridview to add, delete and update the data in the MS Access database. When I added the database file to the project through the Datasource Configuration Wizard, I selected 'No' to copy the file to the project folder. The connection string automatically placed in the project settings is:

Provider=Microsoft.ACE.OLEDB.12.0;Data Source="F:My MoneyDoBillsDoBills2009.accdb"* The 'Copy to Output Directory" property for the DoBills2009DataSet.xsd is set to '*Do not copy*'(and I've tried every other setting available). So, as I understand it, I am working with the original file, not a copy, and any changes (additions, deletions, field changes, etc.) are made directly to the original file. I have added the following code to the datagridview rowleave event:

Private Sub dgvSortBills_RowLeave(ByVal sender As Object, ByVal e As
System.Windows.Forms.DataGridViewCellEventArgs) Handles dgvSortBills.RowLeave
Try

[code].....

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[Code]...

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please see the code below it all works fine its just the last two line im struggling with, which is where i am trying to save the data from the two columns in my DataGridView [code]...

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[Code]....

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I save data from datagridview to text file. I also load the same data from text file into datagridview for edit and update the same thing to text file. Let say this text file i called as Drill.txt. I have another text file called header.txt which need to match its value with the value of Drill.txt file then overwrite value from Drill.txt to header.txt. Now i want to make my Drill.txt in encrypted format to prevent anyone to open that file and modify out of program. They only can modify it through the program

[Code]...

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