Sql - Removing Final "OR" From String?
Jun 20, 2011
I am building up an SQL query in VB.net and have written a routine to do it dynamically. I want to include each item in an array (of unknown size) in the where clause, as such:
Dim person(10) as String
Dim strSQL, strWhereClause as String
person(0) = "John"
person(1) = "Steve"
[Code]...
The problem here is that there is an extra " OR " at the end. Is there a neat way of removing this? Or perhaps a better way to approach the problem all together. (I think a string.join will not work in this situation, because there is text before and after the array item.)EDIT: Manually removing the final three characters like so:strWhereClause = Left(strWhereClause, strWhereClause.Length - 3) is fine, except it doesn't handle the empty string. After all, I don't know how many elements will be in my array.
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Apr 12, 2012
I have a simple question about string concatenation. Following is the code. I want to ask why s6 = "abcde" and not "akcde"? I have change the s2 value to "k".
Public Class Form1
Public s1 As String = "a"
Public s2 As String = "b"
[Code]....
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Feb 25, 2011
I need to build a comma-delimited string from an array.
For i=0 to ubound(arr)
str+= arr(i) & ","
Next i
The trouble is that I end up with an extra comma at the end.
My current method for removing the comma is:
If str<>"" then
Left(str, Len(str) - 1)
End if
But it seems pretty untidy, and non-generic. I have to do this so often, it's become a pain.
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Mar 18, 2009
when i clicked the final button to display my results "as string" it still showeed the number?? here is the code i wrote, is relativley simple, but the theory doesnt make scence to me Basicly its a box with 3 lables, (first name, surname and age), 3 text boxes (for the user to input this info) and a button at the bottom called "display in message box" so when i click the button, it displays the users input in the form as a message box. [code] what i dont get is if i said to VB that vaiable "Complete" was STRING then howcome it still displays the AGE which is an Integer (a number) not a string??
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Sep 7, 2010
I'm having a variable, which contains characters with tab character in between two words. remove the Tab character.
For Ex;
Input string "Word<tab>1234"
I need the output as "Word1234"
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Aug 10, 2010
0000011 22 331. How do I remove "22"?2. How do I get "0000011" and "33"?
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Mar 22, 2011
i tried to read html contents by striping html tags in a string.when i try to print that string i got - character. how to remove this character?
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Nov 8, 2010
Is there any function in vb.net that removes all spaces in a string. I mean a string like ' What is this' should be 'Whatisthis'
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Jun 13, 2011
I had a quick question. I'm desiging a program that users can enter a currency (dollar amount) in a textbox. Since the string I declared will be based on what the user typed in and I want to convert it to a decimal, I want to remove a "$" sign if the user made one.
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Jun 5, 2009
lbltime.Text.Replace(lbltime.Text, lbltime.Text.Length - 2)That does nothing, no error but it doesnt remove the last 2 characters from the string.
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Feb 10, 2010
I have an object folder, which has an atributte name path, that contains a string with it's current path, say "folder1folder2folder3"
I need to remove the last ocurrence beginning on the last "" (in this case, 'folder3'). The new string would be "folder1folder2"
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Dec 21, 2009
I have two a strings when i use them in msgbox() i get this
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Mar 21, 2010
I'm trying remove non-letters from this string I have. I have an order form for hats and T-shirts, they select everything and click on buy button there order info shows up in a listbox. For the results in the listbox I break down there order info and show there total price. Well the string I have for the sizes comes up with Medium "7 1/8 - 7 1/4" in the list box. I want to remove non-letters and have it just show "Medium". I try using the instr function and the trim function as well but nothing is happening.
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Dec 17, 2009
Alright I am taking an XML file which has a bunch of tags and I'm trying to eliminate everything but whats inbetween certian tags for instance the input maybe
- <w:p w:rsidR="00254C13" w:rsidRDefault="001173CF" w:rsidP="001173CF">
- <w:pPr>
- <w:tabs>
[Code].....
unless they say they are safe. Average consumer can protect themselves>not knowledgeable enough to always protect selves</w:t> I want to go through and remove those end tags but when i used the remove string it didn't let me specify a string to remove it the two arguments were where to start and how long. how do i specify what to remove?
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Jan 16, 2011
I have a string that has three spaces in it.
In the following examples, underscores represent the spaces:
Quote:
_x-xx-xxxx_x.xx.xx_xx
I need to remove just the first space. Now, i tried just replacing the space with nothing, like so:
VB.NET
If s.Contains(" ") Thens = s.Replace(" ", "")End If
But, that removes every space. I also tried .StartsWith, but it still removed every space. I didn't actually expect that to work, but if I hadn't tried it, I wouldn't have actually know.
how to remove just that first space?
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Feb 11, 2011
When I try to remove the last few characters of a string, I get an index out of range error. I am using the following to remove the characters from the end of the string:
objJSONStringBuilder.Remove(objJSONStringBuilder.Length - 1, 6)
The string has <hr /> at the end which I want to remove.
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Apr 3, 2009
I need to be able to pull a list of reference from a database whixh ar 12 characters long. Unfortunatley i dont want the first character from each reference number as it is useless but just has to be there.
anyway of saying "list refernce numbers, not including the first character"?
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Jul 16, 2010
If I have a string like: (240). Is their a easy way to strip out the "(" and ")" so that I am left with 240?
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Jun 25, 2010
program makes strings from webbrowser documenttext.For example
String1 = "<span class""long-title"" title"" Informations here"
Im trying to remove all text before "Informations here" this is what i currently have.
dim mychar as char () = {"<"c, "s"c, "p"c, "a"c, '....thatandlike20moretill.... "e"c, """"c}
string1 = string1.TrimStart(mychar)
(Note that each letter or symbol inbetween the quotations is a part of the string (span = "s" "p"...)Now this works. Not all the time though and its a pain in the .. having to do "letter"c, all the time.. (I got over 10 strings lol) Im wondering if theres a way easier method to remove part of string from the beginning, maybe like still a certen part of the length..
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Jun 21, 2009
I wrote a palindrome earlier for a project which I figured out but I talked to a friend in another class and he was having issues with how to take out the punctuation. I dont think it was required on mine but I am just currious how that could be done using commands such as str.lenght, or str.trim those basic commands. Here is my last post that is related
[Code]...
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Jun 11, 2012
I have a string like
FVAL(XXX)="TRUE" AND FVAL(TT)="FALSE"
I want to replace all "TRUE" and "FALSE" by TRUE AND FALSE.
Now the resultant string should be
FVAL(XXX)=TRUE AND FVAL(TT)=FALSE
Will the code shown below be upto the mark for this.
Regex.Replace("FVAL(XXX)=""TRUE"" AND FVAL(TT)=""FALSE""", "[""]TRUE[""]", "TRUE", RegexOptions.IgnoreCase)
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Nov 16, 2009
So im trying to do a simple system in my VB Express Edition 2008 and what it does is add some car models (example) to a list box and stores it in a .txt file for future use. But when the user clicks a delete button it should delete from both the listbox and the .txt. I have to use only the FileOpen(OpenMode.Append or OpenMode.Input/Output) functions.
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Mar 11, 2010
So im trying to do a simple system in my VB Express Edition 2008 and what it does is add some car models (example) to a list box and stores it in a .txt file for future use. But when the user clicks a delete button it should delete from both the listbox and the .txt.I have to use only the FileOpen(OpenMode.Append or OpenMode.Input/Output) functions.
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Apr 14, 2010
this is driving me crazy , I have a string like this dim s as string = "<a href="url.aspx? target=_BLANK>mik, H</a>" I want to remove "mik, h" from the string, how can i do that?
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Feb 1, 2011
Removing the first 8 characters from a text string. How can I do it?
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Nov 22, 2011
I need to parse an alphanumeric string leaving the characters "0-9", ".", "/" and space & remove everything else. I use "[^0-9./ ]" as my regex string and it works well. But now I have a couple other conditions that I dont know how to handle with my regex string. I actually only want to keep the "." character if it falls between two digit characters (ie. 3.5), otherwise remove it. And also I need to replace any "-" characters with a space if it falls between two digit characters (ie. 2-1), otherwise remove it.
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Oct 23, 2011
If I want to remove 2 characters, or a specific letter or character from a string in VB, how would I accomplish this?
A usual input would be
"63.0" in string format
and I want it to be
"63"
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Oct 9, 2010
I have a file location as a string. How can i remove the path from the string and just use the file name? For example:c:filesfile.zip - is the stringhow can i just make it so it's file.zip?keep in mind that the location is found by using anpenfiledialog(), so it needs to be able to remove the location wherever the file is.
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Aug 8, 2011
I have not had much time to go threw my code properly as this is some urgency. I need to remove line 1 from a textfile if it contains a string but its not working.I have 500 files and not going to do this manually.
Code:
Private Sub btnRemove_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnRemove.Click
If String.IsNullOrEmpty(txtDirectory.Text) Then
OpenFolderDialogDirectory()
[code]....
I also feel the function is very pointless sime i am opening the file twice.
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Jul 10, 2010
I have a textbox and the text inside is "2 32 52 14 65". May I know how can I remove all the last spaing until it reach the last string which make it look like "2 32 52 14 65". The number of last spacing might change so i can't use the below code where the number of last spacing is known.
TextBox5.Text = TextBox5.Text.Substring(0, TextBox5.Text.Length - 3)
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