Which Is Better To Open .sln File Or .vbproj File
Mar 16, 2012i was just curious to know which is better to open, the .sln file or the .vbproj file?
View 2 Repliesi was just curious to know which is better to open, the .sln file or the .vbproj file?
View 2 RepliesCan I safely move ReferencePath information from a .vbproj.user (or .csproj.user) file into the corresponding project file? Note: All developers will be using developing from the same location on their machines.We'd like to allow users to maintain their own settings for other things, but have this basic info be setup once and checked into source control to be shared to all.
View 1 RepliesI'm gearing up to work on a project which is migrating from VB6 to .NET 4.0. I have Visual Studio 2010 but wanted to try and open the original source code using the VB6 IDE. Can one still acquire this anywhere?I checked here:http:[url].... I have tried opening the original vb project file by changing the suffix from vbp to vbproj (let's call it MyProject.vbproj) but it just says it cannot interpret the file:
Unable to read the project file 'MyProject.vbproj'.
we have a CollabNet Subversion Edge server running on a Windows server. Subversion Server is configured to serve via https. When trying to import a Visual Studio project folder with TortoiseSVN it hangs when adding the project file (.vbproj). Test 1: It happens exactly the same when the server is configured to serve via http.Test 2: Importing any project folder using the console utility (svn) works fine.
Both these tests lead to the conclusion that there is neither a network nor authorization problem.
Following on from my last question, are the AssemblyMajorVersion, AssemblyMinorVersion,AssemblyRevisionNumber and GenerateRevisionNumber properties required in .vbproj files?
All of our components have these entries in the .vbproj files but they are completely out of sync with the AssemblyVersion and AssemblyFileVersion entries in the AssemblyInfo.vb files.
Are they a legacy from the upgrade from previous VS versions?
I am running vb.net in visual studio 2005 and i am fairly new to it all, whilst trying to create a windows application i have lost the .vbproj file and am only left with the .vb code that has been created whilst i have been using the toolbox to create the application graphically. Is there anyway for me to recover the .vbproj file without having to redo the whole thing?
View 3 Replieshow to use open file dialogs to open a file to a text box?
View 6 RepliesDo you have some source code how to open a file (file browser) with file extension specific using Visual basic.net.
Just need to get the path then control this using the vb.net binding
Years ago when coding with VB6 and earlier, I used a file open command to create, read, and write a file that made it easy to store useful information.I believe it was binary and you wrote/read the data to a specific line in the file. When you opened the file with something like notepad, it just showed random ascii chars. When I needed a line of data, I could specify what line to load it from.
View 2 RepliesI've gone through about 16 hours and two packs of cigarettes trying to figure this out. First a little background. I was using 6.0 up until 2004 when I went to prison. I'm out now, and trying to relearn the trade, using VS 2005. I'm currently porting some 6.0 code from another project, SpyCast Webcam Studio, into VB 8.0. It's disheartening, to say the least. None of the old built-in subs/functions work anymore, so I have to scour the forums to relearn each and every function.The section I'm doing now takes a snapshot from the webcam (Video API --> PictureBox --> Save as Jpeg), then upens the file to upload it to the server via HTTP POST. I've been using this code in SpyCast for years with no trouble, but I spent many hours trying to piece together the right code to open the binary file to read its contents. I pieced together two methods I found around the forums, one using FileStream() though the code I found wasn't for binary files, even though it said it was, so that code doesn't really work. Method two uses Microsoft.VisualBasic.FileOpen() and works better.
Here's the kicker. By the time I run through the rest of the rigamarole of uploading the file, by the time I read it on the webserver, it's *slightly* corrupted. It's a valid Jpeg, no errors, but the picture looks like when I use to watch the Playboy Channel when I was a kid scrambled with weird colors and whatnot. [code] Each "chunk" is basically one "line" of the file. It looks like a single LineInput() return is the text between two carriage returns. Am I correct? I tested this with a flat text file, and it looks true. However, That one input line returns the text or data with the carriage returns *stripped*! ***?!? =( Fine, I have no problem adding my own vbCrLf to each LineInput(), if I were opening text. but this's binary. A character could be Chr(10) or Chr(13), both of which are removed from the original file contents.So I could very well need to use something other than LineInput(), but I haven't found any other examples on the web using this method.
I need a code for the open file dialog that if a file is not supported then a message box appears stating the error. This is my open file dialog code. [code] The message box pops up like it is suppose to, when you click ok the open file comes back up like it is suppose to. When you put in the correct file the message box comes back up again. Also the message pops up even if the correct file is put in the open file. but if you close the file dialog the image is where it is suppose to be.I believe the code for the public sub wrongfile is what is the problem. can some one look it over and let me know what changes are needed.
View 7 Replieshow can i save 2 textboxes(string) into 1 file? and when open the file, the string goes to definite texboxes...
[Code]...
What i am trying to do is open a save file dialog and write to a .txt firl the contents of my listview. so far:
[Code]...
i have this, but i'm not to sure how to write to the .txt file i know i need to use a for each to loop the contents of the list view
It is saved on my desktop for easy access.I can close the program. I can click the solution to open it right back up, no problems.I then zip my file (also to the desktop)
My problem: I moved the original file (Project A) to another folder and extracted the unzipped Project A onto the desktop. When I open the new Project A's solution file, nothing happens besides VB starting up. It doesn't show me anything.
I get mixed results in Google, so I'm wondering how can I simply launch a ReadMe.txt file in Notepad thats in the same directory as my application?
View 1 RepliesI need to open an excel file from vb.net and then search it for specific data. I then need to take those data and insert them into text boxes on a form that i have created. This is all controlled by a button click. I already have some code that will open a file dialog box and let me navigate to the correct file, but I am having trouble with the search portion. I have tried the Find function but I am not sure of the proper syntax. I am using Visual Studio 2008 and Excel 2003.
[Code]...
I have a checked list box that is populated with the text from a text file. I started off with this code:
Dim FileToLoad As String
FileToLoad = TextBox3.Text
Dim fs As FileStream = New FileStream(FileToLoad, FileMode.Open)
[code].....
Well im making a program that will Add the Safe File Name of the File opened in the Open File Dialog to the first column of the listview and the File name and path to the second. What i want it so when i double click on the Safe file name it will open the file specified in the path in the second column.i already got the add file to it.
View 4 Repliescode snippet that would allow a progress bar to track the input of a text file? Normally I would not bother with this, but the text files are > 10,000 lines long, which is noticable even on a fast machine. The number of lines is variable, so I would assume that one would not use a fixed value to calculate when the progress bar goes 100%.
View 4 RepliesIs there a better way of finding the path of a file that was opened with the open file dialogue? This is what I did. It works, but it seems like there should be a way to get the path through one of the open dialogue options.
Code:
'm_PicSource = OpenFileDialog1.FileName
'm_PicSource is a global var
Dim strCnt As Integer = m_PicSource.Length - 1
[Code].....
what im trying to do and what i have done so far is probably a little backwards not sure sure how to id it any other way.when the user generates an error because a particular file doenst exist ive got my dialoge box to generate an .txt file for each file it errors on, so that the administrator can check and update missing files as an when - shouldnt be many files missing in the first place, should just be new product ranges or item just launched.what im stuck on is:
1. is there a better way
2. how do i open a .txt file and add the extra lines to it, so i re use the file but keeping the previous data.
I am trying to build a simple AutoUpdate application using VB.NET. It was quite simple. That is, I put the newest ZIP file in my hosting site, and then download it using WebClient.DownloadFileAsync. After it get downloaded, I extract it using [URL]
But each time I run the unzip.exe using Process.start, Windows 7 always show Open File Security.
Is it possible for VB.NET to bypass such security restriction?
Btw, this is my code of using WebClient.DownloadFileAsync, in case any one google about it and landed on this page :
Public Class AutoUpdate
Dim installationFolder As String = "C:Program Filesxyzabc"
Dim updateFileNameTarget As String
Private Sub btnStartUpdte_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnStartUpdte.Click
[Code]...
we consistently get a file corrupted error message when opening a docx file from a saved bytestream, evry other file type works just ok
Below is code from a sample form that replciate the issue
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
'Objective is to be able to copy a file to a bytestream then create a new document from that stream and then opne it.
[Code].....
I use this code
[Code]...
what code i use that my application pick test.pdf file from application directory.
im having trouble opening adobe from my coding, also is my file ok or do i need to call from its folder location within the program.i need to be able to open a specific .pdf file from a whole range of file located in the program.what im getting the user to do is press 1 of about 14 buttons to select a brand. then in textbox1,enter the first part of the file name so in this case a274 (adobe runs in .pdf format so the file would be a274.pdf).at the moment i get a win32 error high lighting startinfo as the problem so im thinking its the adobe.exe is the problem. [code]
View 9 RepliesI have been trying to open a solution file downloaded from my class for the past two days. When I open the assignment file on my destop to access the solution file, it's not there. I have the variables design, obj, bin, and others but not the .sln file which is the one that I need. How can I fix that problem?
View 2 Replieshow do i return the file path to a variable when using open file dialog to browse and open a file?
View 14 RepliesI have a Motor Class, along with a Collection to hold objects address. Each Collection object holds the Class fields as a String to display in list box. I am able to write the collection string to the file and save the string. But unable to open the existing file, read the file back into the collection object.
Public Class Motor
Private strId As String
Private strDescription As String
[Code]......
I have looked all over for anything (samples or tutorials for working with files and collection objects) pertaining to type of operation with out any success.
I try to map to the network drives and i am able to read the number of folders in the drives and access right for FULL CONTROL ( READ , write etc. ) is given to me and in fact "everyone in the same domain group that i am in. However i encounter the following code error where FileOpen(1, ReadString, OpenMode.Binary) --> It prompts that access to the path of \xxxxxxxxxfolder is denied.
View 1 Replieshow can i specify dynamically by using open file dialog box
View 1 Replies