BitBlt Copy Bitmap To Screen?

Mar 7, 2012

Edit: Fixed, I created a compatibleDC for the graphics object, and a handle for the bitmap (using b.gethbitmap), then used the SelectObject function inside GDI to select those two, and used the compatibleDC instead of hDc in the BitBlt function I've been trying to draw a bitmap to the screen (device 0), however I have encountered a problem copying the graphics using BitBlt.

Initially, I was drawing directly to the desktop using SetPixel (gdi32), but it was slow, so now I am setting the pixels of a bitmap object and then creating graphics from that object, and copying the hdc of the graphics to the screen.My guess is that I am adding the HDC of the graphics object to an intptr, which essentially gives me the HDC of the container of the graphics object, which is not what I need. However even so, I have not found any information on how I could copy a bitmap to a device other than using BitBlt.

This is my current code (Windows forms app, textbox, button) The textbox is the device to copy to, and the button starts it. For testing purposes, set the textbox text to 0, and press the button. You should see a black box (50x50px) in the top left corner of your screen. The colour should be blue if it is working correctly:

Public Class Form1
Declare Function GetDC Lib "user32.dll" (ByVal hwnd As Int32) As Int32
Declare Function ReleaseDC Lib "user32.dll" (ByVal hwnd As Int32, ByVal hdc As Int32) As Int32

[code]....

The way it works is it calls the function setpx, given a location and color from within a loop iterating through all of the pixels in a box (50x50 in my code). The setpx function will then call the setpixel fuction on a bitmap b. This part is working fine.Next, it will define a graphics object g from the bitmap, and I use BitBlt to copy g's hdc (g.gethdc) to the screen. This is not working correctly?

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[URL]

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