VS 2008 - Displaying A Random Number In A Textbox
Feb 4, 2010Each time my application opens, how can i display a random number in a textbox? and i can only be between 1-100?
View 7 RepliesEach time my application opens, how can i display a random number in a textbox? and i can only be between 1-100?
View 7 RepliesI have an app with 4 buttons that each generate a random number into textbox, before this number is entered i would like to have a progress bar at the bottom, well show that its processing basically.
View 4 Repliesi want to set a default number and you type in a textbox a random number it should tell you whether it's high or low ,and when you typed in the right nmber it a lable should says something like you win .And also how can you change PART of a lable by typing in a text in a DIFFERENT FORM
View 6 Repliesi need 35 randoom numbers from 1 to 48, it may not contain 2 times the same number!Private myRand As New Random, numList As New List(Of Integer)[code]how do i put the numbers inside the txtboxes?!?
View 2 Repliesmy textbox will shows a random number some time it match, some time it don't. for example: my textbox is displaying "56" and my listview was added "11" instead of "56".here is my code...
TextBox1.Invoke(New Action(Of Integer)(AddressOf UpdateTextBox), CurrentNumber)
Trying to send random number to text box in a web page. Can't figure it out.
Dim rand As New Random()
Dim number = rand.Next(1, 100)
Dim randnumber As HtmlElementCollection =
[Code].....
I am currently enrolled in the class. My final project for the class will generate random numbers within a range of numbers. For example, if I give the user five text windows to choose whether to input a number OR generate a random number, I will have a button called RANDOMIZE. Unfortunately, I do not know the line(s) of code for the random function.
View 2 RepliesHow can I make a random number generator in vb 2008? I just want a simple one that displays a random number in a label.
View 4 RepliesWith this code...
vb
...Dim random As Long = RandomNumber(1000000000000000, 9999999999999999)... Private Function RandomNumber(ByVal Min As Long, ByVal Max As Long) As Long Dim Random As New Random() Return Random.Next(Min, Max)End Function
...I am getting a OverflowException. Is it so that Random class can't handle Long values?
I want to create a random number with the combination of the text entered in textbox. Suppose the textbox contains bharani. So now the random number generation is the first 3 letters from textbox and the random number from 1 to 1000. So my output must be "bha876"
View 7 RepliesI've got a global random type variable, let's call it rRandom.In my code, I generate a random number like below:
Dim iRandom As Integer = rRandom.Next(0, x)
9 out of 10 times iRandom is 0, the other time it was 1. The code isn't on a timer, it happens when I do something (say clicking a button), so the frequency of the code being called is about 2-3 seconds, I say this because I've had similar issues when generating random numbers really fast in a timer, or with a for loop IIRC.X is a variable that, presently, starts at 3, and will decrease until 0, in which it'll return back to 3. Obviously, if X is 0, iRandom will be 0, but it shouldn't be 0 all the time.I'm declaring the variable globally because I remember, again, having similar issues using local variables, idk whether I should be or not.
I was before knew how to code that it will give me a random number! Also i know it was 2 ways i could make it. A range from like 0 to 100 if i want that. And then it draws a random number from that! And i knew another there i could type in the numbers and it draws a random from there.
View 3 RepliesI've read numerous posts and threads about random number generation, but I havent' run across this.If I generate a bunch of random numbers, the results are radically different if I create a new Random generator for each number than if I use on Random generator for all the numbers. The results are much more consistent and evenly distributed if I use the same Random generator.I would have thought the opposite,because creating a new Random generator each time should reduce the number of random repetitions, if a different time slice is used to create the random number.[code]......
View 9 RepliesHow to generate random number in VB express 2008,2010...I want to generate number between 1 and 10.
View 14 RepliesI've ran into an overflow error when using a private sub and a random number generator...
Private Sub computerpicker()
Dim RandomNumGen As New System.Random
Dim rnum = (RandomNumGen.Next(3))
If rnum = 0 Then
rnum = (RandomNumGen.Next(3))
Call computerpicker()
[Code] .....
Even if bt1=0 and bt2=0 i still get an overflow error...
i follow this script Quote:
[Code]...
I am trying to make a texas hold em game and it is of the utmost importance that my code generate a random number. But using a random number function that I always end up with a lot of the same numbers over and over again. Any ideas on how to make it "TRULY" random? [code]
View 3 RepliesI've made an image viewer which opens a random image from a specified folder, but the random number is not that random at all... I've already used Randomize(), but without result.
View 3 RepliesRight so my generator is working, but I now want to take the numbers that it generates and add them to a list of generated numbers. So you can monitor what numbers have been generated. then ideally a way to exclude these numbers from being generated again.
[Code]...
I'm converting a user generated list box to an array and then generating a user defined number of random strings and placing it in a textbox.The code I have works fine as it will generate the number of random strings the user wants, except sometimes a line is blank at the top of the list but is counted as a string.
View 4 RepliesI would like to ask for some on how to create a random string with number and letters in 8 characters long in VB 2008
View 1 RepliesI am attempting to create a game in Visual Studio 2008 that allows a user 10 attempts to guess a random number between 1 and 50. I have a label box in which I would like to display the remaining guesses as they decrement. The code so far appears below.
My two (I am sure very basic) questions are:
1. How would I pass the random integer generated through the Generate Integer function to the AmIRight button's click function? I was trying to decrement the counter each time the "Am I Right " button is pressed.
2. I would also like to evaluate each "guess" when the "Am I right button is pressed. Is it possible to nest a Select Case statement in a For Next Loop?
vb.net Option Explicit OnOption Strict OnOption Infer Off Public Class frmMain Private Sub btnExit_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles btnExit.Click Me.Close() End Sub Private Sub txtGuess_Enter(ByVal sender As Object, ByVal e As System.EventArgs) Handles
[CODE]...
i wanted to create a random number generator that iterates through a series of number between an upper and lower bound. say between 1 and 100. Basically I want the number generator to pick the numbers randomly and then display them until all 100 numbers are picked without any duplicates. so thats easy I can code that. But what I don't know is how to show those numbers in the order they are generated on a windows form. So i have basically a variable that I will let be changed 100 times (or however many times I want, I don't want their to be a size constraint just using 100 as an example) and each time the number is generated I want it displayed on screen (in a list or something not sure what. Hopefully some type of scrollable list) and each successive number also to be displayed in same format beneath it so that I can see the list in its entirety. What type of form control do i use for that? I could do messagebox.show for each iteration but then user is required to hit ok after each iteration and that would obviously be a bad idea if user selected a large number to work through. Anyways, code isn't exactly necessary just point me in the right direction, i.e.what control (if any) to use.how to format the change in data?
View 7 RepliesI am trying to create a lotto simulation, but don't know how to continue.I am using numericupdowns to allow users to select 6 lotto numbers. and labels to display what they have chosen, but i'm not sure how to prevent duplicates without creating a large number of If statementsMy question is, is there an easier way to prevent duplicates without writing a bunch of if statements?here is my code:
Public Class Form1 Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click Dim Lotto1, Lotto2, Lotto3, Lotto4, Lotto5, Lotto6 As Single Lotto1 = Val(NumericUpDown1.Text) lblLotto1.Text = Lotto1 Lotto2 = Val(NumericUpDown2.Text) lblLotto2.Text = Lotto2 Lotto3 = Val(NumericUpDown3.Text)
[code]....
I don't understand how to save the user selected numbers, let the computer generate 6 random numbers, and match the two sets of numbers together to see how many matches there are. As far as I understand the numbers should be stored in 2 separate arrays and then matched together to find any matches.
Im trying to Assign the date to a text box without the time, using a button. i also want to be able to use the text box to enter a alternate date. i have found some basic..Basically i am making a form for personal use to help me do my paper work..[code]
View 10 RepliesI have this program generating a firstname and lastname from a file. When I run this program I enter information in three textboxes. The first two are the salary low and high(salary1.text, salary2.text) and the last one is the number of "copies"(copies.text) that I want.. When I put a number such as 10 in the text box it outputs some of the same names. The firstname file has around 100 records and the lastname file has about 1000 records Why is it generating the same name The problem is even worse if I do something like 1000 copies.. it outputs the same thing 8 times and then does something different another 8 times
Public Class Form1
Dim sex As String
Function randomfirstname()
Dim infile As IO.StreamReader
[code]....
What is the advantage of using a text box to display an answer in Visual Basic versus a label?
View 2 RepliesVS2010 (SP1) / .NET 4 on Windows XP. The question is simple, the answer; not so much. When generating a salt, should the LENGTH of the salt be random, fixed or a random number within a (min/max) range? I am using RNGCryptoServiceProvider to generate the salt, just unsure of the length of the salt.
View 12 Repliesis there a way to generate a random number and then display that number?
like for example i want to say "i got # - # pencils" or something like that
I heard that you have to add some code to a random number generator
results(1) = Int((5 - 1 + 1) * Rnd() + 1)
so that if it is used again and again it keeps generating new numbers as apposed to what this piece of code does by itself which is creates the same number every time.what is the code?