Able To Add Times Such As 2:39 Instead Of Decimal Numbers Using VB?
Jul 15, 2011
I am creating a Time Sheet Calculator Application and just need to find out how to add numbers that are in hourly form. For example 2:39 (two hours and thirty nine minutes). I know how to create code for simple addition of decimal numbers, but does VB 2010 have some kind of way of adding hours and returning a number in hourly form.
How would I go about rounding up decimal numbers to the nearest 2 decimal places? For example $7.0000032 would be $7.01 In theory, VB would make it $7.00 but if it is > $7.00, I want it to reflect that to the nearest penny... so $3.0000001 would be $3.01
I have an id called "AM01". I separated them by truncating the numbers out and increase it by 1 each time I want to add a new record. Therefore before I add the record, I would have to combine them back. I managed to truncate them and combine them back. However, the results turn out to be "AM2" instead of "AM02". So, is there a way where I could make the numbers as "02" instead of just "2"?
I am trying to write a random number function that can just be called from my main module to generate different random numbers. I have tried this several different ways and I am having odd results. Approximately 19 times out of 20 the numbers come back exactly the same, but approximately 1 in 20 they come back as two different numbers. Im using Visual Basic Studio 2008. Here is the code I have so far, or rather, the current version of my many tests I have been running to try and figure it out. Sometimes it takes many runs of the program before the two seperate numbers apear.I've been researching it and have come up with nothing so far.I know I could put them in the module section as two different randoms and it works, but I get extra points if i use a couple classes in my program.This is the main module.
Module Module1 Sub Main() Dim randomNumOne As New RandNum[code]...........
I'm trying to compare Office version numbers in vb.NET How can I determine if: 12.0.64 is greater or less than say 12.0.62 or 14.0.4762 It seems the fact that there is 2 decimals, vb doesn't like it.
Possible Duplicate: How to convert numbers between hexadecimal and decimal in C#? In C, you can do something like int x = 255; printf("x is: %d and in HEX, x is: %x", x, x); How can I do that in C# or VB.net? print the variable's hex equivalent
I'm having a bit of an issue getting the number formatting of VB .NET 3.5 to work just right for me. I have to convert numbers to scientific notation, with 2 digits for the exponent and 6 digits after the decimal. I've been able to get this for numbers that have enough digits, but for other numbers, it truncates the number to use as few digits as possible. For example, I would like 0 to be converted to 0.000000e00, or 123.4 to be 1.234000e02.
I'm a noob, so please bear with me. I'm working with VB in Visual Studio 2008. I have an application that displays dollar amounts. With the application installed on my desktop all of the dollar values display with 2 decimal places. However, after moving the application to the server and executing from there, trailing zeroes after the decimal point are lost.
For example - 7.00 displays as 7 - 10.60 displays as 10.6 I'm guessing there's an options file somewhere that determines how these numbers are displaying but I have no idea what that file might be.
Can someone tell me how to get both digits following the decimal point to display all of the time?
how to limit number into 2 decimal places sample when i got number of 1000.7585545 is should be 1000.76 i have this code below but based on the given sample it will result to 1001.00
If txtpassPrice.Text <> "" Then Dim dblTranspo As Double dblTranspo = txtpassPrice.Text txtpassPrice.Text = Format(dblTranspo, "#,##0.00") End If
i tried this one but i will result to 1001 only
If txtpassPrice.Text <> "" Then Dim dblTranspo As Double dblTranspo = txtpassPrice.Text txtpassPrice.Text = Format(dblTranspo, "#,##0.##") End If
I was wondering how can I get the two numbers right of the decimal period? If I had 2.85874125639, I would want to get this: 2.86 since it was rounded...
In short let's say i have a form with a text box and a label. I am going to insert a number for example "1365" in the text box and then in the forms label it'll output "one thousand three hundred sixty five".
I have a hw assignment and it asks this: program Description: Write a program that has four sub procedures that will calculate and print out a table of numbers 0 to 17 in decimal, hex, octal, and binary notation. Statements Required: output, loop control, subprogram
Sample Output: (you will design your own output but 4 adjacent label boxes would be suitable) [Code] What I want to know is how do I display my numbers from 1 to 17 as either Hex, Decimal, Octal or Binary. Also how would I display that on my form?
I want to specify the user to enter only the numbers and decimal point in the text box.[code]values something like that which contain only numbers and dot.This is the code to enter the numbers only.[code]How to make the code to accept dot also?
I'm trying to limit the number of decimal values to 3 in numbers such as .3125 but I also have numbers such as .5 which I need to leave as is.
how can I determine if a number is 4 decimal places and cut off the last number.. I don't want to round up either.. .3125 should be .312 not .313 and .5 should stay at .5 and not .500.
I've found plenty of examples of accepting numbers only in a text box, but the code won't allow decimal points. This is crucial because I'm dealing with US currency.
01.' Force numbers only in a text box 02.' place this in the 'Keypress' event of a text box 03.
[Code]....
How can I change the IF statement to accept the ascii code of decimal points? Then... how can I make sure the user doesn't enter 354.5.3535.5.0 as a number? Is there some sort of built in library in VB that has a pattern matching for US currency or do I have to write it myself?
I have a series of text boxes with numbers. They are an array called txtBF(0 to 16). I am trying to take the value that is to be displayed in the text box and make it have only one decimal place. I have tried using this code below but I keep getting an error message Run Time Error 13: Type Mismatch.
txtBF(11).text = Round(txtBF(11).text, 1) and I have also tried this txtBF(11).text = Math.Round(txtBF(11).text, 1)