Write Decimal Numbers In SQL 2008?
Dec 14, 2010In need to write the number 7.2 in a table field. What type the field needs to be. And what type needs the variable to be?
View 1 RepliesIn need to write the number 7.2 in a table field. What type the field needs to be. And what type needs the variable to be?
View 1 Repliesi m trying to write a program that displays in a textbox a table of the binary, octal, and hexadecimal equivalents of the decimal numbers in range 1-222.
View 3 RepliesI was wondering how can I get the two numbers right of the decimal period? If I had 2.85874125639, I would want to get this: 2.86 since it was rounded...
View 4 RepliesIn short let's say i have a form with a text box and a label. I am going to insert a number for example "1365" in the text box and then in the forms label it'll output "one thousand three hundred sixty five".
View 4 RepliesHow would I go about rounding up decimal numbers to the nearest 2 decimal places? For example $7.0000032 would be $7.01 In theory, VB would make it $7.00 but if it is > $7.00, I want it to reflect that to the nearest penny... so $3.0000001 would be $3.01
View 5 RepliesintLoginTime = txtLoginTime.Text
intLogoutTime = txtLogoutTime.Text
[CODE]..........
The problem is that the numbers seem to round after the decimal point, so if I entered a login-time of 8.15 and log-out 9.30, instead of showing 1.15 as the difference, it shows '1'. is there a way around this?
I'm trying to do this division and the result to be displayed on a eight decimal number.
Dim r1 As Integer
Dim r2 As Double
r1 = Val(TextBox16.Text)
r2 = r1 / 60
TextBox18.Text = FormatNumber(r2, 8)
The value or R1 on this case is 273.4 but it varies according with the result obtained so I can not allocate a constant number to r1. The problem is the result that I am getting is 4,55000000 instead of 4.5566666
I have an id called "AM01". I separated them by truncating the numbers out and increase it by 1 each time I want to add a new record. Therefore before I add the record, I would have to combine them back. I managed to truncate them and combine them back. However, the results turn out to be "AM2" instead of "AM02". So, is there a way where I could make the numbers as "02" instead of just "2"?
View 6 RepliesI have one textbox and one label i want to see the distances between the numbers imediately when i write them example 1476=365-32-1
View 39 RepliesHow to let textbox1 only enter positive whole numbers and positive decimal numbers
View 4 RepliesI am creating a Time Sheet Calculator Application and just need to find out how to add numbers that are in hourly form. For example 2:39 (two hours and thirty nine minutes). I know how to create code for simple addition of decimal numbers, but does VB 2010 have some kind of way of adding hours and returning a number in hourly form.
View 1 RepliesI want to display decimal numbers like 12.75 on my result .... but its keep showing like 12 or 13...
View 6 RepliesHow to allow two numbers after decimal points ?
View 1 RepliesI'm trying to convert random numbers between 0.1 and 1. Here is what I have done.
[Code]...
how to round up a decimal numbers.. 5.63 = 6.00, 5.43 = 5.00
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Using .net To add a $ symbol for numbers I did Texbox1.Text.Format = "C"
How to add % symbol at the end of each integer to represent a string in textbox.
I'm trying to compare Office version numbers in vb.NET How can I determine if: 12.0.64 is greater or less than say 12.0.62 or 14.0.4762 It seems the fact that there is 2 decimals, vb doesn't like it.
View 1 RepliesPossible Duplicate: How to convert numbers between hexadecimal and decimal in C#? In C, you can do something like int x = 255; printf("x is: %d and in HEX, x is: %x", x, x); How can I do that in C# or VB.net? print the variable's hex equivalent
View 7 RepliesI'm having a bit of an issue getting the number formatting of VB .NET 3.5 to work just right for me. I have to convert numbers to scientific notation, with 2 digits for the exponent and 6 digits after the decimal. I've been able to get this for numbers that have enough digits, but for other numbers, it truncates the number to use as few digits as possible. For example, I would like 0 to be converted to 0.000000e00, or 123.4 to be 1.234000e02.
View 1 RepliesI'm a noob, so please bear with me. I'm working with VB in Visual Studio 2008. I have an application that displays dollar amounts. With the application installed on my desktop all of the dollar values display with 2 decimal places. However, after moving the application to the server and executing from there, trailing zeroes after the decimal point are lost.
For example - 7.00 displays as 7 - 10.60 displays as 10.6 I'm guessing there's an options file somewhere that determines how these numbers are displaying but I have no idea what that file might be.
Can someone tell me how to get both digits following the decimal point to display all of the time?
how to limit number into 2 decimal places sample when i got number of 1000.7585545 is should be 1000.76 i have this code below but based on the given sample it will result to 1001.00
If txtpassPrice.Text <> "" Then
Dim dblTranspo As Double
dblTranspo = txtpassPrice.Text
txtpassPrice.Text = Format(dblTranspo, "#,##0.00")
End If
i tried this one but i will result to 1001 only
If txtpassPrice.Text <> "" Then
Dim dblTranspo As Double
dblTranspo = txtpassPrice.Text
txtpassPrice.Text = Format(dblTranspo, "#,##0.##")
End If
I input a value with decimal numbers in textbox to save a records in access..when i try to open an access, and it's value is whole number...
View 4 RepliesI have a problem which is that Class Big integer Doing a miscalculation
For example: -
5 / 2 = 2.5
With Class
5 / 2 = 2
I want to do to show the numbers after the decimal point (.5)
How can I make it so that decimal numbers round up or down to the nearest integer?
View 3 RepliesI have a hw assignment and it asks this: program Description: Write a program that has four sub procedures that will calculate and print out a table of numbers 0 to 17 in decimal, hex, octal, and binary notation. Statements Required: output, loop control, subprogram
Sample Output: (you will design your own output but 4 adjacent label boxes would be suitable) [Code] What I want to know is how do I display my numbers from 1 to 17 as either Hex, Decimal, Octal or Binary. Also how would I display that on my form?
I want to specify the user to enter only the numbers and decimal point in the text box.[code]values something like that which contain only numbers and dot.This is the code to enter the numbers only.[code]How to make the code to accept dot also?
View 5 RepliesI'm trying to limit the number of decimal values to 3 in numbers such as .3125 but I also have numbers such as .5 which I need to leave as is.
how can I determine if a number is 4 decimal places and cut off the last number.. I don't want to round up either.. .3125 should be .312 not .313 and .5 should stay at .5 and not .500.
I am trying to restrict the the number of decimal places to two in a textbox.
I've already made it so only numbers and decimals can be added, now this is the only thing that isnt done
Private Sub MoneyTxtxbx(ByVal sender As System.Object, ByVal e As System.Windows.Forms.KeyPressEventArgs) Handles _
MoneyTxtbx.KeyPress
[Code]....
I've found plenty of examples of accepting numbers only in a text box, but the code won't allow decimal points. This is crucial because I'm dealing with US currency.
01.' Force numbers only in a text box
02.' place this in the 'Keypress' event of a text box
03.
[Code]....
How can I change the IF statement to accept the ascii code of decimal points? Then... how can I make sure the user doesn't enter 354.5.3535.5.0 as a number? Is there some sort of built in library in VB that has a pattern matching for US currency or do I have to write it myself?
I have a series of text boxes with numbers. They are an array called txtBF(0 to 16). I am trying to take the value that is to be displayed in the text box and make it have only one decimal place. I have tried using this code below but I keep getting an error message Run Time Error 13: Type Mismatch.
txtBF(11).text = Round(txtBF(11).text, 1)
and I have also tried this
txtBF(11).text = Math.Round(txtBF(11).text, 1)