Ndex And Length Must Refer To A Location Within String
Aug 10, 2009
I was trying to make a simple program to search in my mysql db, but i'm seeing this error :{"Index and length must refer to a location within the string. Parameter name: length"}[code]
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Apr 17, 2009
this is not working?
[Code]...
End WhileI am trying to read from the ": " to the end of the line. I keep getting this error: Index and length must refer to a location within the string. Parameter name: length
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Feb 17, 2011
am getting the above exception while swaping Items in the list(lstRoutePriority).PFB my code
if (lstRoutePriority.SelectedIndex > 0)
{
//Swap the two items
[Code].....
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Jul 7, 2009
why this error happens with a bit of code i was trying? The code is actually intended to be for an onclick event, so it actually works there.
But im just curious as to why it errors as an onchange event. This is 9am pre-caffeine, so the reason is probably starring me in the face! On a form i have a text box, and a combo box. The combo box has various options in it, natch. Its a search form, which then fills a gridview with the results.
Drop down list options are: home number, mobile number, post code, Name, DOB
I thought id try and be "clever" and do away with the need for the combo box. Since a mobile number begins with "07", names are just characters, postcodes are character character number, and home number is all numbers and doesent begin with "07", and date of birth has /'s in it.
So i tried this to test the idea:
Private Sub AppSearchTB_TextChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles AppSearchTB.TextChanged
Dim TLength As Integer = 2
[Code]....
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Sep 13, 2011
I am trying to get the first 50 letters, so I used the subString function to get it. As you can see, I used this code to get it:
<%# Eval("BannerDescription").ToString.Substring(1, 50)%>
But unfortunately it's not working and an error message is coming up:
Index and length must refer to a location within the string.
Because the user is the one who is controlling the data entry! Some times he gonna enter 10 letters other times maybe 1000 letter?
I tried them all but can we use it this way :
<%# IIf(Eval("BannerDescription").ToString().Length > 49, Eval("BannerDescription").ToString().Substring(0, 49), Eval("BannerDescription"))%>
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Mar 23, 2009
"Index and length must refer to a location within the string. Parameter name: length" whenever I run this code
[Code]...
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Jul 21, 2010
If using the following in an if statement I get an error: If trg.Name.Substring(4, 6).ToUpper <> ("ABCDEF") Then I get the error: "Index and length must refer to a location within the string. Parameter name: length"
I assume this is because the string (trg.name) is too small for the 4, 6 substring. What would be the correct method of working around this problem? VB.net Studio 2008.
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Mar 1, 2009
I keep getting the error saying that index and length must refer to a location within the string.
Public Class MainForm
Private Sub btnAdd_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnAdd.Click
Dim description As String = String.Empty
Dim invCount As String = String.Empty
[code]....
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Sep 28, 2009
Dim Phone as string = "478-742-4050 478-256-6550"
If _Phone.Length > 25 Then
_Phone = IsNull(ReturnValue.Substring(0, 25).ToString, "")
End If
Return _Phone
Error: "Index and length must refer to a location within the string. Parameter name: length"
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Sep 7, 2009
why error "Index and length must refer to a location within the string."appear when the process of the program is going to executeNonQuery, i'm looking the error for 2 day's i still can't find it.
[Code]...
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Jun 23, 2009
I got this error and I don't know what should I do. Index and length must refer to a location within the string. Parameter name: length That's the line that i get the error on:
[Code]...
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Oct 12, 2009
why when i upload less than 10 item the program do but more than it like 15 and above the program give me error saying "Index and length must refer to a location within the string."
here is my codes below
For Each myDatarow In tblLocal.Select("sync ='0'") '
' tblServer.ImportRow(myDatarow)
' dataimpt = myDatarow.Item(4).ToString
[Code].....
the error appear when the program is going to update the 14th data... meaning from 1st to 13th data program works in the 14th it's not it gives me error "Index and length must refer to a location within the string
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Oct 15, 2010
I'm working on a vb.net project, when I execute the project I get the following error message: "error message: index and length must refer to a location within the string"
Public Sub New(ByVal lineIn As String)
parent = Trim(lineIn.Substring(0, colStarts(1)))
enfant = Trim(lineIn.Substring(colStarts(1), colStarts(2) - colStarts(1)))
des_F = Trim(lineIn.Substring(colStarts(2), colStarts(3) - colStarts(2)))
[Code]...
I get the error msg in the line marked bold. When i checked the input file, the length of all the fields looks fine. I dont understand the cause of this error.
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Dec 21, 2008
im basically working on my final years project on the vb.net with the ilog business rules. i have trouble solving this error :Index and length must refer to a location within the string. Parameter name: length And the output show this :[size=2]
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Feb 13, 2012
Consider the Statement:
Dim pstr As String
FileOpen(2, pfilepath, OpenMode.Input)
pstr = LineInput(2)
pstr = pstr.Substring(13, pstr.Length)
Label1.Text = pstr
FileClose(2)
And it is Giving me the following error:
Index and length must refer to a location within the string. Parameter name: length.
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Mar 29, 2011
numberofchar = timefull.Length
If timefull = "" Then
Else
If numberofchar = 11 Then
timefull = timefull.Remove(2, 9) ' isolate the hour depends on number of digits in hour parameter
Else
timefull = timefull.Remove(1, 9)
End If
End If
This is my code, it doesn't work when I copy into form load. But when I try it in another form, it works. Index and count must refer to a location within the string. Parameter name: count
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Oct 22, 2011
I got a error when I run this code:
Dim btch As String
Dim LeftPart As String
[CODE]...
It says index and location must refert to a location withing string
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Dec 20, 2009
How do I refer to a form in my project by using a string variable? I'm running Visual Studio 2008.My main screen has a number of dropdown menus that, when an item is selected, a form will open:
Dim Mdi_frm_Doors As New frm_Doors Mdi_frm_Doors.MdiParent =Mdi_frm_Doors.Show()In this example, I am providing the name of the form directly (frm_Doors). What I would like to do is refer to the form as a string variable.I'm already doing something similar to access specific controls on other open forms (where str_Field is the name of the control I am accessing):
[Code]...
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Apr 22, 2010
I have a string called testlabel, and would like to refer to it via the string "testlabel", how do I do this?
for instance:
dim testlabel as label
dim a as string = "test"
dim b as string = "label"
'what is the line I need here? a & b.text = "hello world"
to get testlabel.text to read "hello world"?
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Nov 12, 2010
Is there a way to reference an object by using the value of a string read from a text file? Here's an example of what I mean: I have a user control called 'Fish', one called 'Cats', and one called 'Dogs' and so on.... I have a text file containing this line, amongst many others in a long script written after compile time by the user:
[Code]...
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Apr 21, 2010
I have a label testlabel. is there some way I can refer to it as:
dim t as string = "testlabel"
(something here referring to the OBJECT with the same name as the string).text = "mytext"
? I have 50 labels with text to change and would love to be able to:
for i = 1 to 50
dim t as string = "testlabel" & i
convertsomehow(t, label).text = "mytext"
next
so that this would change testlabel1, testlabel2, testlabel3, ... , testlabel50.
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May 9, 2011
I have lots of labels that I need to refer to.
E.g. label1 = listbox1.selecteditem.tostring & "123"
label2 = listbox1.selecteditem.tostring & "123"
I have 20 labels which i need to repeat the same process for. What I found was this code which always gives me the null reference error.
CType(Me.Controls("Label" & i), Label).Text = "what i want here"
I have stated dim i as integer = 1
And later i = i + 1 until it is 20.
I've tried i.tostring and cstr(i) when referring to it but it keeps saying it doesn't exists even though i have labels 1 to 20 named label1, label2 etc. on my Form.
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Jun 22, 2009
I know the name of a textbox in string format: txtbox & i. Through the loop, the txtbox name will be txtbox1, txtbox2,.... And I want to change the txtbox & 1 's text dynamically in the code. How can i refer to the textbox obj from the string?
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Feb 20, 2010
when i transfer the bytes sent by the client program to a string the string length is affected.when i put the bytes sent by the client program to a message box. it returns the corrrect text. but when i check the length it will return 8192 or higher. but the actual size is just 5.
My Code
Dim tcpClient As TcpClient = tcpListener.AcceptTcpClient()
RichTextBox1.Text = RichTextBox1.Text & vbNewLine & "Connection accepted."
' Get the stream[code]....
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Sep 11, 2011
I have a long string like this
dim LongString as String = "123abc456def789ghi"
And I want to split it into a string array. Each element of the array should be in 3 characters length[code]...
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Mar 10, 2010
I'm writing some code that takes a report from the mainframe and converts it to a spreadsheet. They can't edit the code on the MF to give me a delimited file, so I'm stuck dealing with it as fixed width. It's working okay now, but I need to get it more stable before I release it for testing. My problem is that in any given line of data, say it could have three columns of numbers, each five chars wide at positions 10, 16, and 22. If on this one particular row, there's no data for the last two cols, it won't be padded with spaces; rather, the length of the string will be only 14. So, I can't just blindly have
[Code]...
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Nov 4, 2010
If I have a string Metal is hot : Metal length is 5 cm ; Metal is red. I want to get the sub string that is talking about length: hence I want to extract "Metal length is 5 cm".
[Code]...
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Oct 29, 2009
How can I count the length of a string and also how many special characters are in the strings.
For instance if I have this string: $how*
How can I count that string is 5 chars long and that there are 2 special characters in the string. (special characters are the $ and
I think that I am going to have to use the .length method to count the length of the string.
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Mar 2, 2012
i had the code belowing workin fine before but all of a suden i have a error init
[Code]...
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Apr 6, 2011
I was trying to grab the string length of readData but when I try msgbox (readData.Length),
its giving me a large numeric digit instead.
Dim readData as string
serverStream.Read(inStream, 0, buffSize)
Dim returndata As String = _
System.Text.Encoding.ASCII.GetString(inStream)
readData = "" + returndata
msg()
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