Getting The Error Saying That Index And Length Must Refer To A Location Within The String

Mar 1, 2009

I keep getting the error saying that index and length must refer to a location within the string.

Public Class MainForm
Private Sub btnAdd_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnAdd.Click
Dim description As String = String.Empty
Dim invCount As String = String.Empty

[code]....

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Substring - Error: Index And Length Must Refer To A Location Within The String. Parameter Name: Length

Apr 17, 2009

this is not working?

[Code]...

End WhileI am trying to read from the ": " to the end of the line. I keep getting this error: Index and length must refer to a location within the string. Parameter name: length

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VS 2005 Error:Index And Length Must Refer To A Location Within The String?

Sep 7, 2009

why error "Index and length must refer to a location within the string."appear when the process of the program is going to executeNonQuery, i'm looking the error for 2 day's i still can't find it.

[Code]...

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VS 2005 Uploading Error: Index And Length Must Refer To A Location Within The String

Oct 12, 2009

why when i upload less than 10 item the program do but more than it like 15 and above the program give me error saying "Index and length must refer to a location within the string."

here is my codes below

For Each myDatarow In tblLocal.Select("sync ='0'") '
' tblServer.ImportRow(myDatarow)
' dataimpt = myDatarow.Item(4).ToString

[Code].....

the error appear when the program is going to update the 14th data... meaning from 1st to 13th data program works in the 14th it's not it gives me error "Index and length must refer to a location within the string

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VS 2008 Error Message: Index And Length Must Refer To A Location Within The String

Oct 15, 2010

I'm working on a vb.net project, when I execute the project I get the following error message: "error message: index and length must refer to a location within the string"

Public Sub New(ByVal lineIn As String)
parent = Trim(lineIn.Substring(0, colStarts(1)))
enfant = Trim(lineIn.Substring(colStarts(1), colStarts(2) - colStarts(1)))
des_F = Trim(lineIn.Substring(colStarts(2), colStarts(3) - colStarts(2)))

[Code]...

I get the error msg in the line marked bold. When i checked the input file, the length of all the fields looks fine. I dont understand the cause of this error.

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Output Error "Index And Length Must Refer To A Location Within The String. Parameter Name: Length" With Substring

Mar 23, 2009

"Index and length must refer to a location within the string. Parameter name: length" whenever I run this code

[Code]...

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Index And Length Must Refer To A Location Within The String. Parameter Name: Length Exception

Feb 17, 2011

am getting the above exception while swaping Items in the list(lstRoutePriority).PFB my code

if (lstRoutePriority.SelectedIndex > 0)
{
//Swap the two items

[Code].....

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Index And Length Must Refer To A Location Within The String?

Jul 7, 2009

why this error happens with a bit of code i was trying? The code is actually intended to be for an onclick event, so it actually works there.

But im just curious as to why it errors as an onchange event. This is 9am pre-caffeine, so the reason is probably starring me in the face! On a form i have a text box, and a combo box. The combo box has various options in it, natch. Its a search form, which then fills a gridview with the results.

Drop down list options are: home number, mobile number, post code, Name, DOB

I thought id try and be "clever" and do away with the need for the combo box. Since a mobile number begins with "07", names are just characters, postcodes are character character number, and home number is all numbers and doesent begin with "07", and date of birth has /'s in it.

So i tried this to test the idea:

Private Sub AppSearchTB_TextChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles AppSearchTB.TextChanged
Dim TLength As Integer = 2

[Code]....

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Index And Length Must Refer To Location Within String?

Sep 13, 2011

I am trying to get the first 50 letters, so I used the subString function to get it. As you can see, I used this code to get it:
<%# Eval("BannerDescription").ToString.Substring(1, 50)%>

But unfortunately it's not working and an error message is coming up:
Index and length must refer to a location within the string.
Because the user is the one who is controlling the data entry! Some times he gonna enter 10 letters other times maybe 1000 letter?

I tried them all but can we use it this way :
<%# IIf(Eval("BannerDescription").ToString().Length > 49, Eval("BannerDescription").ToString().Substring(0, 49), Eval("BannerDescription"))%>

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Error: Index And Length Must Refer To A Location?

Dec 21, 2008

im basically working on my final years project on the vb.net with the ilog business rules. i have trouble solving this error :Index and length must refer to a location within the string. Parameter name: length And the output show this :[size=2]

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VS 2008 Index And Length Must Refer To A Location Within The String?

Sep 28, 2009

Dim Phone as string = "478-742-4050 478-256-6550"
If _Phone.Length > 25 Then
_Phone = IsNull(ReturnValue.Substring(0, 25).ToString, "")
End If
Return _Phone

Error: "Index and length must refer to a location within the string. Parameter name: length"

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VS 2008 ArgumentOutOfRangeException - Index And Length Must Refer To A Location Within The String

Jun 23, 2009

I got this error and I don't know what should I do. Index and length must refer to a location within the string. Parameter name: length That's the line that i get the error on:

[Code]...

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Substring Size - "Index And Length Must Refer To A Location Within The String. Parameter Name: Length"

Jul 21, 2010

If using the following in an if statement I get an error: If trg.Name.Substring(4, 6).ToUpper <> ("ABCDEF") Then I get the error: "Index and length must refer to a location within the string. Parameter name: length"

I assume this is because the string (trg.name) is too small for the 4, 6 substring. What would be the correct method of working around this problem? VB.net Studio 2008.

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SubString Function - Index And Length Must Refer To Location

Feb 13, 2012

Consider the Statement:
Dim pstr As String
FileOpen(2, pfilepath, OpenMode.Input)
pstr = LineInput(2)
pstr = pstr.Substring(13, pstr.Length)
Label1.Text = pstr
FileClose(2)
And it is Giving me the following error:
Index and length must refer to a location within the string. Parameter name: length.

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Ndex And Length Must Refer To A Location Within String

Aug 10, 2009

I was trying to make a simple program to search in my mysql db, but i'm seeing this error :{"Index and length must refer to a location within the string. Parameter name: length"}[code]

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Index And Count Must Refer To Location Within String

Mar 29, 2011

numberofchar = timefull.Length
If timefull = "" Then
Else
If numberofchar = 11 Then
timefull = timefull.Remove(2, 9) ' isolate the hour depends on number of digits in hour parameter
Else
timefull = timefull.Remove(1, 9)
End If
End If
This is my code, it doesn't work when I copy into form load. But when I try it in another form, it works. Index and count must refer to a location within the string. Parameter name: count

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Substring Give Error - Says Index And Location Must Refert To A Location Withing String

Oct 22, 2011

I got a error when I run this code:

Dim btch As String
Dim LeftPart As String

[CODE]...

It says index and location must refert to a location withing string

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Index And Length Error

Dec 9, 2010

I keep getting the error saying that index and length must refer to a location within the string. I am sure there is just something minor that I am missing but I am having a difficult time figuring it out.

CODE:

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Dynamically Create Array Based On String Length Property and Index Of Method

May 4, 2009

I would like to format output to a property of a custom control I have made.For instance I have a literal control in my control and when populated I want to check if it is longer than 30 characters long, if so, then go to the next space (as to not cut the word off) after the 30th character and place a <br /> tag in to place the next 30 characters on the next line.So if there were 100 characters in a string, there would be 3 line breaks in the label.I have the looping worked out to get the label populated but cannot get how to dymaically create the array based on the string lenth property and index of method.

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Get The Index Location Of A Child Node Using The Key String On TreeView .NET?

Oct 27, 2009

trying to determine the index of a child node using the key string so I can add a new child node to it.I am using this code:

vNodesIndex = TreeView1.Nodes.IndexOfKey(Key)

But only works for the root node when I try to find an exiting child node the code returns -1 (Not Found)

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Replace Error - String Cannot Be Of Zero Length

Mar 13, 2009

I am receiving the following error when trying to replace spaces with %. "String cannot be of zero length. Parameter name: oldvalue" Dim Keywords As String = "test abc" Dim sqlkeywords As String sqlkeywords = Keywords.Replace("", "%") I have also tryed sqlkeywords = Replace(Keywords, "", "%") and it just returns the original.... test abc.

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Convert String To Date : Error Out Of Index Range

Dec 19, 2006

In my fresh installation of Visual Studio Professional 2005 Visual Basic I have typed this code

dim olddate as date
olddate=datevalue("01-01-2006")

I receive an error: index out of range exception

On an other pc with the same fresh installation this do not happen. Why ? I have tried with other funtions : ctype, cdate but I receive the same error, while on an other pc this code is fine.

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ObservableCollection.Insert On Index Bigger Than Length Of Collection

Mar 15, 2012

I'm wondering, what happens when you do following:

Collection.Insert(55, "Input")

The collection contains 20 items, so 19 would be the last index. This doesn't work, I get the expected outofrangeException. But when I do :

Collection.Insert(20, "Input")

That works without a problem, even though it is 1 out of the collection.

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Custom Checkbox List Control Error In "startIndex Cannot Be Larger Than Length Of String"

Jun 25, 2009

I am creating a custom checkbox control to add a div after each checkbox in a checkboxlist.The class is below.

Imports System.Web.UI.WebControls
Imports System.ComponentModel
Imports System.Globalization

[Code]...

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VS 2005 Error:Index Was Out Of Range. Must Be Non-negative And Less Than The Size Of The Collection.Parameter Name: Index

Oct 23, 2009

Getting error filling grid view from reading through data table:

Dim myDataTable As DataTable = myDataSet.Tables("SunTrust")
Dim myRow As DataRow
Dim i As Integer = 1
Try

[code]....

Error:Index was out of range. Must be non-negative and less than the size of the collection.Parameter name: index

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Error - Index Was Out Of Range. Must Be Non Negative And Less Than The Size Of The Collection. Parameter Name: INDEX

Jan 22, 2009

What im trying to do is send vars to a flash file.The following is my code:

Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
Dim oTitle As New ArrayList
Dim oSub As New ArrayList
Dim oRate As New ArrayList

[code]....

What I'm expecting the output to display is something like "t1=value&s1=value&r1=rate&t2=value&s2=value&r2=rat&t3=value&s3=value&r3=rat" But... i keep getting this exception: index was out of range. must be non negative and less than the size of the collection. Parameter name: INDEX.

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Error - Index Was Out Of Range. Must Be Non-negative And Less Than Size Of The Collection. Parameter Name: Index

Aug 25, 2011

I have a datagridview, with 3 columns, each containing dropdown filters (in the column header). Of the 3 columns, 2 are working perfectly fine, but whenever I try to filter the 3rd column, it gives me this error: (Also all of the column's have the ColumnType property set to: DataGridViewAutoFilterTextBoxColumn) "Index was out of range. Must be non-negative and less than size of the collection. Parameter name: index." The error points to the part that begins with "If dgv1.Rows(e.RowIndex)..."

Private Sub dgvWPS_CellFormatting(ByVal sender As Object, ByVal e As System.Windows.Forms.DataGridViewCellFormattingEventArgs) Handles dgv1.CellFormatting
If e.ColumnIndex = 1 Then

[code]....

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Cant Get The Index Location Of An Array?

Jan 19, 2010

just wanna get that simple problem.,but i am confused bout this i cant get the index location of an array>

my problem is have to display 5 elements so the index is 0 to 4 right?

example i entered 1 2 3 4 5 then i searched 3 the location should be index 2?right?

how can i get the index location of the searched number?if you can make me understand sub and functions too..

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[2008] Error: InvalidArgument=Value Of '6' Is Not Valid For 'index'. Parameter Name: Index

Mar 5, 2009

I've got the web browser with tabs in all working fine, but there's one bug, i can add tabs, delete em, etc.. but when i delete a tab then go to create a new tab, it gives me the error: InvalidArgument=Value of '6' is not valid for 'index'. Parameter name: index '6' is the number of tabs i had open.Here's the bit of code i use to create the tabs with the browser in it:

vbcode

Dim browse As New WebBrowser
browse.Name = "b1"
browse.Dock = DockStyle.Fill

[code]....

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Error - You Cannot Start Application <App_Name> From This Location Because It Is Already Installed From A Different Location

Dec 10, 2009

we have a user that my program works fine for.. and another that it just crashes for.. they get this error

"You cannot start application <App_Name> from this location because it is already installed from a different location."

then they run it up again and it comes up.. and then just closes..in reading some stuff online it says its a framework 2.0 sp 1 issue ?these pc's have 3.5, but my program uses all 2.0 stuff..so is this a 2.0 sp level issue ? or should I make my programs start to use framework 3.0 instead ?

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