VS 2005 Uploading Error: Index And Length Must Refer To A Location Within The String
Oct 12, 2009
why when i upload less than 10 item the program do but more than it like 15 and above the program give me error saying "Index and length must refer to a location within the string."
here is my codes below
For Each myDatarow In tblLocal.Select("sync ='0'") '
' tblServer.ImportRow(myDatarow)
' dataimpt = myDatarow.Item(4).ToString
[Code].....
the error appear when the program is going to update the 14th data... meaning from 1st to 13th data program works in the 14th it's not it gives me error "Index and length must refer to a location within the string
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Sep 7, 2009
why error "Index and length must refer to a location within the string."appear when the process of the program is going to executeNonQuery, i'm looking the error for 2 day's i still can't find it.
[Code]...
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Apr 17, 2009
this is not working?
[Code]...
End WhileI am trying to read from the ": " to the end of the line. I keep getting this error: Index and length must refer to a location within the string. Parameter name: length
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Mar 1, 2009
I keep getting the error saying that index and length must refer to a location within the string.
Public Class MainForm
Private Sub btnAdd_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnAdd.Click
Dim description As String = String.Empty
Dim invCount As String = String.Empty
[code]....
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Oct 15, 2010
I'm working on a vb.net project, when I execute the project I get the following error message: "error message: index and length must refer to a location within the string"
Public Sub New(ByVal lineIn As String)
parent = Trim(lineIn.Substring(0, colStarts(1)))
enfant = Trim(lineIn.Substring(colStarts(1), colStarts(2) - colStarts(1)))
des_F = Trim(lineIn.Substring(colStarts(2), colStarts(3) - colStarts(2)))
[Code]...
I get the error msg in the line marked bold. When i checked the input file, the length of all the fields looks fine. I dont understand the cause of this error.
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Mar 23, 2009
"Index and length must refer to a location within the string. Parameter name: length" whenever I run this code
[Code]...
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Feb 17, 2011
am getting the above exception while swaping Items in the list(lstRoutePriority).PFB my code
if (lstRoutePriority.SelectedIndex > 0)
{
//Swap the two items
[Code].....
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Jul 7, 2009
why this error happens with a bit of code i was trying? The code is actually intended to be for an onclick event, so it actually works there.
But im just curious as to why it errors as an onchange event. This is 9am pre-caffeine, so the reason is probably starring me in the face! On a form i have a text box, and a combo box. The combo box has various options in it, natch. Its a search form, which then fills a gridview with the results.
Drop down list options are: home number, mobile number, post code, Name, DOB
I thought id try and be "clever" and do away with the need for the combo box. Since a mobile number begins with "07", names are just characters, postcodes are character character number, and home number is all numbers and doesent begin with "07", and date of birth has /'s in it.
So i tried this to test the idea:
Private Sub AppSearchTB_TextChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles AppSearchTB.TextChanged
Dim TLength As Integer = 2
[Code]....
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Sep 13, 2011
I am trying to get the first 50 letters, so I used the subString function to get it. As you can see, I used this code to get it:
<%# Eval("BannerDescription").ToString.Substring(1, 50)%>
But unfortunately it's not working and an error message is coming up:
Index and length must refer to a location within the string.
Because the user is the one who is controlling the data entry! Some times he gonna enter 10 letters other times maybe 1000 letter?
I tried them all but can we use it this way :
<%# IIf(Eval("BannerDescription").ToString().Length > 49, Eval("BannerDescription").ToString().Substring(0, 49), Eval("BannerDescription"))%>
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Dec 21, 2008
im basically working on my final years project on the vb.net with the ilog business rules. i have trouble solving this error :Index and length must refer to a location within the string. Parameter name: length And the output show this :[size=2]
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Sep 28, 2009
Dim Phone as string = "478-742-4050 478-256-6550"
If _Phone.Length > 25 Then
_Phone = IsNull(ReturnValue.Substring(0, 25).ToString, "")
End If
Return _Phone
Error: "Index and length must refer to a location within the string. Parameter name: length"
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Jun 23, 2009
I got this error and I don't know what should I do. Index and length must refer to a location within the string. Parameter name: length That's the line that i get the error on:
[Code]...
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Jul 21, 2010
If using the following in an if statement I get an error: If trg.Name.Substring(4, 6).ToUpper <> ("ABCDEF") Then I get the error: "Index and length must refer to a location within the string. Parameter name: length"
I assume this is because the string (trg.name) is too small for the 4, 6 substring. What would be the correct method of working around this problem? VB.net Studio 2008.
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Feb 13, 2012
Consider the Statement:
Dim pstr As String
FileOpen(2, pfilepath, OpenMode.Input)
pstr = LineInput(2)
pstr = pstr.Substring(13, pstr.Length)
Label1.Text = pstr
FileClose(2)
And it is Giving me the following error:
Index and length must refer to a location within the string. Parameter name: length.
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Aug 10, 2009
I was trying to make a simple program to search in my mysql db, but i'm seeing this error :{"Index and length must refer to a location within the string. Parameter name: length"}[code]
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Mar 29, 2011
numberofchar = timefull.Length
If timefull = "" Then
Else
If numberofchar = 11 Then
timefull = timefull.Remove(2, 9) ' isolate the hour depends on number of digits in hour parameter
Else
timefull = timefull.Remove(1, 9)
End If
End If
This is my code, it doesn't work when I copy into form load. But when I try it in another form, it works. Index and count must refer to a location within the string. Parameter name: count
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Oct 22, 2011
I got a error when I run this code:
Dim btch As String
Dim LeftPart As String
[CODE]...
It says index and location must refert to a location withing string
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Dec 9, 2010
I keep getting the error saying that index and length must refer to a location within the string. I am sure there is just something minor that I am missing but I am having a difficult time figuring it out.
CODE:
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Oct 23, 2009
Getting error filling grid view from reading through data table:
Dim myDataTable As DataTable = myDataSet.Tables("SunTrust")
Dim myRow As DataRow
Dim i As Integer = 1
Try
[code]....
Error:Index was out of range. Must be non-negative and less than the size of the collection.Parameter name: index
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May 4, 2009
I would like to format output to a property of a custom control I have made.For instance I have a literal control in my control and when populated I want to check if it is longer than 30 characters long, if so, then go to the next space (as to not cut the word off) after the 30th character and place a <br /> tag in to place the next 30 characters on the next line.So if there were 100 characters in a string, there would be 3 line breaks in the label.I have the looping worked out to get the label populated but cannot get how to dymaically create the array based on the string lenth property and index of method.
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Oct 27, 2009
trying to determine the index of a child node using the key string so I can add a new child node to it.I am using this code:
vNodesIndex = TreeView1.Nodes.IndexOfKey(Key)
But only works for the root node when I try to find an exiting child node the code returns -1 (Not Found)
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Oct 12, 2009
In VB6 if you do this,
keyStr = Left$(baseKey + encPassword, 56)
the string will be 56 characters even if it means appending whitespaces to the end.
in VB.NET
keyStr = Left$(baseKey + encPassword, 56)
will not necessarily be 56 characters. How can I force it to append whitespaces at the end if the baseKey + encPassword is less than 56 characters long?
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Nov 26, 2010
I have a project which has a table with a list of stores. Originally the store code was a string of 3 and was padded so 1 would be 001 etc. I have had to increase this column to 8. The problem is when I read in data from a XML file the store code is padded so it looks like this '500 ' rather than '500'. This is now causing a major problem when I do a comparison.Is there a way to it does not auto pad to the full string length?
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Dec 23, 2009
I want to upload files from particular location. I got problem with GetRequestStream() function.
Here is the
Dim path() As String = Directory.GetFiles("C:files") 'I tried and with("C:/files/")
For Each files As String In path
Dim ftprequest = DirectCast(WebRequest.Create("ftp://" & FTPHost & "/" & files), FtpWebRequest)
ftprequest.EnableSsl = True
ftprequest.Credentials = New NetworkCredential(user, password)
[Code] .....
Error message is:
The remote server returned an error: (500) Syntax error, command unrecognized.
When I tried with My.Computer.Network.UploadFile(...)
I got this error:
The remote server returned an error: (550) File unavailable (e.g., file not found, no access).
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Mar 13, 2009
I am receiving the following error when trying to replace spaces with %. "String cannot be of zero length. Parameter name: oldvalue" Dim Keywords As String = "test abc" Dim sqlkeywords As String sqlkeywords = Keywords.Replace("", "%") I have also tryed sqlkeywords = Replace(Keywords, "", "%") and it just returns the original.... test abc.
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Apr 13, 2009
I want to uploadfiles on ftp location through inet control in vb6.0. I created ftp location on my pc on iis. The control works fine if i give path like ftp://myhostname, but when I created new ftp location in my pc. It is not working. The new path is c:myftp, I created new virtual directory in ftp locations and publish the location as ftp named myFTP. below is a code
[Code]....
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Mar 25, 2010
So I have a string that I need to search through for certain strings. If they exist, then copy that string to a text box. There has to be an easier way to do this then what I have below
[Code]...
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Dec 19, 2006
In my fresh installation of Visual Studio Professional 2005 Visual Basic I have typed this code
dim olddate as date
olddate=datevalue("01-01-2006")
I receive an error: index out of range exception
On an other pc with the same fresh installation this do not happen. Why ? I have tried with other funtions : ctype, cdate but I receive the same error, while on an other pc this code is fine.
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Mar 15, 2012
I'm wondering, what happens when you do following:
Collection.Insert(55, "Input")
The collection contains 20 items, so 19 would be the last index. This doesn't work, I get the expected outofrangeException. But when I do :
Collection.Insert(20, "Input")
That works without a problem, even though it is 1 out of the collection.
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Jun 25, 2009
I am creating a custom checkbox control to add a div after each checkbox in a checkboxlist.The class is below.
Imports System.Web.UI.WebControls
Imports System.ComponentModel
Imports System.Globalization
[Code]...
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