I got this error and I don't know what should I do. Index and length must refer to a location within the string. Parameter name: length That's the line that i get the error on:
[Code]...
Dim Phone as string = "478-742-4050 478-256-6550"
If _Phone.Length > 25 Then
_Phone = IsNull(ReturnValue.Substring(0, 25).ToString, "")
End If
Return _Phone
Error: "Index and length must refer to a location within the string. Parameter name: length"
I'm working on a vb.net project, when I execute the project I get the following error message: "error message: index and length must refer to a location within the string"
Public Sub New(ByVal lineIn As String)
parent = Trim(lineIn.Substring(0, colStarts(1)))
enfant = Trim(lineIn.Substring(colStarts(1), colStarts(2) - colStarts(1)))
des_F = Trim(lineIn.Substring(colStarts(2), colStarts(3) - colStarts(2)))
[Code]...
I get the error msg in the line marked bold. When i checked the input file, the length of all the fields looks fine. I dont understand the cause of this error.
this is not working?
[Code]...
End WhileI am trying to read from the ": " to the end of the line. I keep getting this error: Index and length must refer to a location within the string. Parameter name: length
am getting the above exception while swaping Items in the list(lstRoutePriority).PFB my code
if (lstRoutePriority.SelectedIndex > 0)
{
//Swap the two items
[Code].....
why this error happens with a bit of code i was trying? The code is actually intended to be for an onclick event, so it actually works there.
But im just curious as to why it errors as an onchange event. This is 9am pre-caffeine, so the reason is probably starring me in the face! On a form i have a text box, and a combo box. The combo box has various options in it, natch. Its a search form, which then fills a gridview with the results.
Drop down list options are: home number, mobile number, post code, Name, DOB
I thought id try and be "clever" and do away with the need for the combo box. Since a mobile number begins with "07", names are just characters, postcodes are character character number, and home number is all numbers and doesent begin with "07", and date of birth has /'s in it.
So i tried this to test the idea:
Private Sub AppSearchTB_TextChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles AppSearchTB.TextChanged
Dim TLength As Integer = 2
[Code]....
I am trying to get the first 50 letters, so I used the subString function to get it. As you can see, I used this code to get it:
<%# Eval("BannerDescription").ToString.Substring(1, 50)%>
But unfortunately it's not working and an error message is coming up:
Index and length must refer to a location within the string.
Because the user is the one who is controlling the data entry! Some times he gonna enter 10 letters other times maybe 1000 letter?
I tried them all but can we use it this way :
<%# IIf(Eval("BannerDescription").ToString().Length > 49, Eval("BannerDescription").ToString().Substring(0, 49), Eval("BannerDescription"))%>
I keep getting the error saying that index and length must refer to a location within the string.
Public Class MainForm
Private Sub btnAdd_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnAdd.Click
Dim description As String = String.Empty
Dim invCount As String = String.Empty
[code]....
why error "Index and length must refer to a location within the string."appear when the process of the program is going to executeNonQuery, i'm looking the error for 2 day's i still can't find it.
[Code]...
why when i upload less than 10 item the program do but more than it like 15 and above the program give me error saying "Index and length must refer to a location within the string."
here is my codes below
For Each myDatarow In tblLocal.Select("sync ='0'") '
' tblServer.ImportRow(myDatarow)
' dataimpt = myDatarow.Item(4).ToString
[Code].....
the error appear when the program is going to update the 14th data... meaning from 1st to 13th data program works in the 14th it's not it gives me error "Index and length must refer to a location within the string
"Index and length must refer to a location within the string. Parameter name: length" whenever I run this code
[Code]...
If using the following in an if statement I get an error: If trg.Name.Substring(4, 6).ToUpper <> ("ABCDEF") Then I get the error: "Index and length must refer to a location within the string. Parameter name: length"
I assume this is because the string (trg.name) is too small for the 4, 6 substring. What would be the correct method of working around this problem? VB.net Studio 2008.
im basically working on my final years project on the vb.net with the ilog business rules. i have trouble solving this error :Index and length must refer to a location within the string. Parameter name: length And the output show this :[size=2]
View 4 RepliesConsider the Statement:
Dim pstr As String
FileOpen(2, pfilepath, OpenMode.Input)
pstr = LineInput(2)
pstr = pstr.Substring(13, pstr.Length)
Label1.Text = pstr
FileClose(2)
And it is Giving me the following error:
Index and length must refer to a location within the string. Parameter name: length.
I was trying to make a simple program to search in my mysql db, but i'm seeing this error :{"Index and length must refer to a location within the string. Parameter name: length"}[code]
View 4 Repliesnumberofchar = timefull.Length
If timefull = "" Then
Else
If numberofchar = 11 Then
timefull = timefull.Remove(2, 9) ' isolate the hour depends on number of digits in hour parameter
Else
timefull = timefull.Remove(1, 9)
End If
End If
This is my code, it doesn't work when I copy into form load. But when I try it in another form, it works. Index and count must refer to a location within the string. Parameter name: count
I got a error when I run this code:
Dim btch As String
Dim LeftPart As String
[CODE]...
It says index and location must refert to a location withing string
I would like to format output to a property of a custom control I have made.For instance I have a literal control in my control and when populated I want to check if it is longer than 30 characters long, if so, then go to the next space (as to not cut the word off) after the 30th character and place a <br /> tag in to place the next 30 characters on the next line.So if there were 100 characters in a string, there would be 3 line breaks in the label.I have the looping worked out to get the label populated but cannot get how to dymaically create the array based on the string lenth property and index of method.
View 7 RepliesLoopBegin:
Do Until strXMLSingle.Contains("ENDOFXMLCHECK")
strXMLSingle = getTempFile.ReadLine
If strXMLSingle.Contains("<character") Then
[code]....
I have that so far. It was working great for the names part until I attempted to do the level part, now i get the following error:
System.ArgumentOutOfRangeException: InvalidArgument=Value of '1' is not valid for 'index'.
Also at the line where i use a goto statement to go back to the beginning of the loop, is there any way i can do that without a goto statement? Like a second loop statement or something?
trying to determine the index of a child node using the key string so I can add a new child node to it.I am using this code:
vNodesIndex = TreeView1.Nodes.IndexOfKey(Key)
But only works for the root node when I try to find an exiting child node the code returns -1 (Not Found)
I have lots of labels that I need to refer to.
E.g. label1 = listbox1.selecteditem.tostring & "123"
label2 = listbox1.selecteditem.tostring & "123"
I have 20 labels which i need to repeat the same process for. What I found was this code which always gives me the null reference error.
CType(Me.Controls("Label" & i), Label).Text = "what i want here"
I have stated dim i as integer = 1
And later i = i + 1 until it is 20.
I've tried i.tostring and cstr(i) when referring to it but it keeps saying it doesn't exists even though i have labels 1 to 20 named label1, label2 etc. on my Form.
I keep getting the error saying that index and length must refer to a location within the string. I am sure there is just something minor that I am missing but I am having a difficult time figuring it out.
CODE:
I have a problem to make the comparison from char to string array using Naive Algorithm in vb.net.[code]The problem is the system cannot compare the input from s1 to compare with s2.
View 15 Replieshow to split a string into an array based on it's length?Say if I want the length to be 350 then every 350 chars in a textbox will be split into an array like [code]
View 14 RepliesI'm wondering, what happens when you do following:
Collection.Insert(55, "Input")
The collection contains 20 items, so 19 would be the last index. This doesn't work, I get the expected outofrangeException. But when I do :
Collection.Insert(20, "Input")
That works without a problem, even though it is 1 out of the collection.
just wanna get that simple problem.,but i am confused bout this i cant get the index location of an array>
my problem is have to display 5 elements so the index is 0 to 4 right?
example i entered 1 2 3 4 5 then i searched 3 the location should be index 2?right?
how can i get the index location of the searched number?if you can make me understand sub and functions too..
How would I take the location of a file that a user has opened and save it to a string? Say the user opened the file picture.jpg @ C:picture.jpg. How could I save that file path or assign it to a string?
View 5 RepliesIs there any way by which I can add a location to Windows 7 search index and make it indexed in .Net?
View 1 Repliesi need to find the location of element by index
example i enter 5 numbers
1 2 3 4 5
search a number, i search 3 it should display the lindex location? for me to understand more about vb,,more on arrays..
I am trying to import a text file into a data table using VB.NET. I need to loop thru each line of the text file and put certain elements of that line in a new row of the data table. The line may contain 50 elements, but I only need to get 15 of them. The very first line is a header row, which contains "File Name", "Object Name", "Object Weight", etc. The trick is the element locations move from file to file. For example, "File Name" element may be located at 0 in one file and then 15 in the next file. I need to find the exact location of my desired elements and save them to a variable. Then use that variable to locate the exact piece of data in the text file line to place in my new row.
The code below obviously doesn't work, but it kind of illustrates what I need to have done.
Try
With dt
.Columns.Add("fltObjectWeight", Type.GetType("System.Double"))
.Columns.Add("vchObjectName", Type.GetType("System.String"))
[Code].....