i need to find the location of element by index
example i enter 5 numbers
1 2 3 4 5
search a number, i search 3 it should display the lindex location? for me to understand more about vb,,more on arrays..
I got a error when I run this code:
Dim btch As String
Dim LeftPart As String
[CODE]...
It says index and location must refert to a location withing string
i am having trouble putting a value in a textbox. Each time a ticket is sold i put the total price in a textbox, each time a ticket is sold for the same concert it increases by adding its self to the total price. It works at the first sale, but after that it breaks down. here is the code
Private Function DisplayMoneyTaken() As Integer
Dim totalMoney As Integer
'open the database connection
[Code].....
How can i get the index of an element in datatable which i got using the select method of datatable as
dim d as new datatable= 'some data source'
dim dr() as datarow
dr=dt.select("some condition")
now i want to find the index of first or second item which i have retrieved in data row. i mean there index in data table with out use of loops as loops take a lot of time when there is huge data in data table.
i have a 1 dimension boolean array and i need to get the index of the array element value = true.Anyone can point me a direction?I know i have to use.indexof() but when i try to use Variable.indexof(True) but it won't work.
View 28 RepliesI have panel1 and button1. what i want to do is setting a new location for the panel when pressing the button1.
View 3 RepliesI need a HTML element location (X and Y) in WebBrowser... Not the OffsetRectangle.Location one where you get a location coordinates inside parent element. I need a location coordinates inside the webbrowser...
View 14 Replieslet say a site has 2 forms: one search form and the other is a registration form[code]...
View 1 Repliesjust wanna get that simple problem.,but i am confused bout this i cant get the index location of an array>
my problem is have to display 5 elements so the index is 0 to 4 right?
example i entered 1 2 3 4 5 then i searched 3 the location should be index 2?right?
how can i get the index location of the searched number?if you can make me understand sub and functions too..
Is there any way by which I can add a location to Windows 7 search index and make it indexed in .Net?
View 1 Repliesim basically working on my final years project on the vb.net with the ilog business rules. i have trouble solving this error :Index and length must refer to a location within the string. Parameter name: length And the output show this :[size=2]
View 4 RepliesI am trying to import a text file into a data table using VB.NET. I need to loop thru each line of the text file and put certain elements of that line in a new row of the data table. The line may contain 50 elements, but I only need to get 15 of them. The very first line is a header row, which contains "File Name", "Object Name", "Object Weight", etc. The trick is the element locations move from file to file. For example, "File Name" element may be located at 0 in one file and then 15 in the next file. I need to find the exact location of my desired elements and save them to a variable. Then use that variable to locate the exact piece of data in the text file line to place in my new row.
The code below obviously doesn't work, but it kind of illustrates what I need to have done.
Try
With dt
.Columns.Add("fltObjectWeight", Type.GetType("System.Double"))
.Columns.Add("vchObjectName", Type.GetType("System.String"))
[Code].....
numberofchar = timefull.Length
If timefull = "" Then
Else
If numberofchar = 11 Then
timefull = timefull.Remove(2, 9) ' isolate the hour depends on number of digits in hour parameter
Else
timefull = timefull.Remove(1, 9)
End If
End If
This is my code, it doesn't work when I copy into form load. But when I try it in another form, it works. Index and count must refer to a location within the string. Parameter name: count
why this error happens with a bit of code i was trying? The code is actually intended to be for an onclick event, so it actually works there.
But im just curious as to why it errors as an onchange event. This is 9am pre-caffeine, so the reason is probably starring me in the face! On a form i have a text box, and a combo box. The combo box has various options in it, natch. Its a search form, which then fills a gridview with the results.
Drop down list options are: home number, mobile number, post code, Name, DOB
I thought id try and be "clever" and do away with the need for the combo box. Since a mobile number begins with "07", names are just characters, postcodes are character character number, and home number is all numbers and doesent begin with "07", and date of birth has /'s in it.
So i tried this to test the idea:
Private Sub AppSearchTB_TextChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles AppSearchTB.TextChanged
Dim TLength As Integer = 2
[Code]....
I am trying to get the first 50 letters, so I used the subString function to get it. As you can see, I used this code to get it:
<%# Eval("BannerDescription").ToString.Substring(1, 50)%>
But unfortunately it's not working and an error message is coming up:
Index and length must refer to a location within the string.
Because the user is the one who is controlling the data entry! Some times he gonna enter 10 letters other times maybe 1000 letter?
I tried them all but can we use it this way :
<%# IIf(Eval("BannerDescription").ToString().Length > 49, Eval("BannerDescription").ToString().Substring(0, 49), Eval("BannerDescription"))%>
trying to determine the index of a child node using the key string so I can add a new child node to it.I am using this code:
vNodesIndex = TreeView1.Nodes.IndexOfKey(Key)
But only works for the root node when I try to find an exiting child node the code returns -1 (Not Found)
I keep getting the error saying that index and length must refer to a location within the string.
Public Class MainForm
Private Sub btnAdd_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnAdd.Click
Dim description As String = String.Empty
Dim invCount As String = String.Empty
[code]....
Consider the Statement:
Dim pstr As String
FileOpen(2, pfilepath, OpenMode.Input)
pstr = LineInput(2)
pstr = pstr.Substring(13, pstr.Length)
Label1.Text = pstr
FileClose(2)
And it is Giving me the following error:
Index and length must refer to a location within the string. Parameter name: length.
Dim Phone as string = "478-742-4050 478-256-6550"
If _Phone.Length > 25 Then
_Phone = IsNull(ReturnValue.Substring(0, 25).ToString, "")
End If
Return _Phone
Error: "Index and length must refer to a location within the string. Parameter name: length"
How would I find a part of a document by class name?Like heres the code of what I cam trying to find[code]...
View 1 Replieswhy error "Index and length must refer to a location within the string."appear when the process of the program is going to executeNonQuery, i'm looking the error for 2 day's i still can't find it.
[Code]...
I got this error and I don't know what should I do. Index and length must refer to a location within the string. Parameter name: length That's the line that i get the error on:
[Code]...
I was looking at a previous post and the poster was talking about htmlelement, so what I want to know is if you can use this function to find a html element on a wb page.I'm trying to make a program that will find the img src url for an image on a website and then return that url to the imagelocation of a picturebox.
View 5 Replieswhy when i upload less than 10 item the program do but more than it like 15 and above the program give me error saying "Index and length must refer to a location within the string."
here is my codes below
For Each myDatarow In tblLocal.Select("sync ='0'") '
' tblServer.ImportRow(myDatarow)
' dataimpt = myDatarow.Item(4).ToString
[Code].....
the error appear when the program is going to update the 14th data... meaning from 1st to 13th data program works in the 14th it's not it gives me error "Index and length must refer to a location within the string
I'm working on a vb.net project, when I execute the project I get the following error message: "error message: index and length must refer to a location within the string"
Public Sub New(ByVal lineIn As String)
parent = Trim(lineIn.Substring(0, colStarts(1)))
enfant = Trim(lineIn.Substring(colStarts(1), colStarts(2) - colStarts(1)))
des_F = Trim(lineIn.Substring(colStarts(2), colStarts(3) - colStarts(2)))
[Code]...
I get the error msg in the line marked bold. When i checked the input file, the length of all the fields looks fine. I dont understand the cause of this error.
I have a generic list - SupportedTypeGroups. Each SupportedTypeGroup has SupportedTypes property (generic list of SupportedType). How to construct a Linq query to locate SupportedType with required name?
View 3 RepliesI am working on a very basic draw poker program. I need to analyze the hands. So far I have been able to identify a a pair, straight, a flush , and a straight flush. I'm not sure how to find three of a kind, full house, etc I have a function that uses a hash table to find out if there are duplicates in my array. I can use it identfy a sequence of cards. (i.e. if it returns a 5, that would be five cards in sequence) I'm not sure how to/if at all to use this for a pair , three of kind etc.. Maybe a differant approach would be useful. I've tried various pseudo code idea on paper and just don't see it.
[Code]...
I'm using a web browser in my vb forum and it to find a certain element then click it when the element loads. The thing is though i don't want it to use the actual mouse if you understand what im saying. Like a appliation thats clicking certain elements but i can still use my mouse to do stuff that i want. Here's the code i have so far
[Code]...
How can you find a specific HTML element in a webbrowser.document? I'm making a program that will go to a specified address on the internet and find a html element and get the src link from the element then return the src to the imagelocation of a picturebox. Is this at least possible?
View 8 RepliesI need to know how to find the HTML element the mouse if hovering over such as a link so that I can open the link in a new tab, what would be an easy way of doing this?
View 3 Replies