Index And Count Must Refer To Location Within String

Mar 29, 2011

numberofchar = timefull.Length
If timefull = "" Then
Else
If numberofchar = 11 Then
timefull = timefull.Remove(2, 9) ' isolate the hour depends on number of digits in hour parameter
Else
timefull = timefull.Remove(1, 9)
End If
End If
This is my code, it doesn't work when I copy into form load. But when I try it in another form, it works. Index and count must refer to a location within the string. Parameter name: count

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Index And Length Must Refer To A Location Within The String?

Jul 7, 2009

why this error happens with a bit of code i was trying? The code is actually intended to be for an onclick event, so it actually works there.

But im just curious as to why it errors as an onchange event. This is 9am pre-caffeine, so the reason is probably starring me in the face! On a form i have a text box, and a combo box. The combo box has various options in it, natch. Its a search form, which then fills a gridview with the results.

Drop down list options are: home number, mobile number, post code, Name, DOB

I thought id try and be "clever" and do away with the need for the combo box. Since a mobile number begins with "07", names are just characters, postcodes are character character number, and home number is all numbers and doesent begin with "07", and date of birth has /'s in it.

So i tried this to test the idea:

Private Sub AppSearchTB_TextChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles AppSearchTB.TextChanged
Dim TLength As Integer = 2

[Code]....

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Index And Length Must Refer To Location Within String?

Sep 13, 2011

I am trying to get the first 50 letters, so I used the subString function to get it. As you can see, I used this code to get it:
<%# Eval("BannerDescription").ToString.Substring(1, 50)%>

But unfortunately it's not working and an error message is coming up:
Index and length must refer to a location within the string.
Because the user is the one who is controlling the data entry! Some times he gonna enter 10 letters other times maybe 1000 letter?

I tried them all but can we use it this way :
<%# IIf(Eval("BannerDescription").ToString().Length > 49, Eval("BannerDescription").ToString().Substring(0, 49), Eval("BannerDescription"))%>

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Mar 1, 2009

I keep getting the error saying that index and length must refer to a location within the string.

Public Class MainForm
Private Sub btnAdd_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnAdd.Click
Dim description As String = String.Empty
Dim invCount As String = String.Empty

[code]....

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VS 2008 Index And Length Must Refer To A Location Within The String?

Sep 28, 2009

Dim Phone as string = "478-742-4050 478-256-6550"
If _Phone.Length > 25 Then
_Phone = IsNull(ReturnValue.Substring(0, 25).ToString, "")
End If
Return _Phone

Error: "Index and length must refer to a location within the string. Parameter name: length"

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Sep 7, 2009

why error "Index and length must refer to a location within the string."appear when the process of the program is going to executeNonQuery, i'm looking the error for 2 day's i still can't find it.

[Code]...

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VS 2008 ArgumentOutOfRangeException - Index And Length Must Refer To A Location Within The String

Jun 23, 2009

I got this error and I don't know what should I do. Index and length must refer to a location within the string. Parameter name: length That's the line that i get the error on:

[Code]...

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Oct 12, 2009

why when i upload less than 10 item the program do but more than it like 15 and above the program give me error saying "Index and length must refer to a location within the string."

here is my codes below

For Each myDatarow In tblLocal.Select("sync ='0'") '
' tblServer.ImportRow(myDatarow)
' dataimpt = myDatarow.Item(4).ToString

[Code].....

the error appear when the program is going to update the 14th data... meaning from 1st to 13th data program works in the 14th it's not it gives me error "Index and length must refer to a location within the string

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Oct 15, 2010

I'm working on a vb.net project, when I execute the project I get the following error message: "error message: index and length must refer to a location within the string"

Public Sub New(ByVal lineIn As String)
parent = Trim(lineIn.Substring(0, colStarts(1)))
enfant = Trim(lineIn.Substring(colStarts(1), colStarts(2) - colStarts(1)))
des_F = Trim(lineIn.Substring(colStarts(2), colStarts(3) - colStarts(2)))

[Code]...

I get the error msg in the line marked bold. When i checked the input file, the length of all the fields looks fine. I dont understand the cause of this error.

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Apr 17, 2009

this is not working?

[Code]...

End WhileI am trying to read from the ": " to the end of the line. I keep getting this error: Index and length must refer to a location within the string. Parameter name: length

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am getting the above exception while swaping Items in the list(lstRoutePriority).PFB my code

if (lstRoutePriority.SelectedIndex > 0)
{
//Swap the two items

[Code].....

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Dec 21, 2008

im basically working on my final years project on the vb.net with the ilog business rules. i have trouble solving this error :Index and length must refer to a location within the string. Parameter name: length And the output show this :[size=2]

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SubString Function - Index And Length Must Refer To Location

Feb 13, 2012

Consider the Statement:
Dim pstr As String
FileOpen(2, pfilepath, OpenMode.Input)
pstr = LineInput(2)
pstr = pstr.Substring(13, pstr.Length)
Label1.Text = pstr
FileClose(2)
And it is Giving me the following error:
Index and length must refer to a location within the string. Parameter name: length.

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"Index and length must refer to a location within the string. Parameter name: length" whenever I run this code

[Code]...

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Substring Size - "Index And Length Must Refer To A Location Within The String. Parameter Name: Length"

Jul 21, 2010

If using the following in an if statement I get an error: If trg.Name.Substring(4, 6).ToUpper <> ("ABCDEF") Then I get the error: "Index and length must refer to a location within the string. Parameter name: length"

I assume this is because the string (trg.name) is too small for the 4, 6 substring. What would be the correct method of working around this problem? VB.net Studio 2008.

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Substring Give Error - Says Index And Location Must Refert To A Location Withing String

Oct 22, 2011

I got a error when I run this code:

Dim btch As String
Dim LeftPart As String

[CODE]...

It says index and location must refert to a location withing string

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Ndex And Length Must Refer To A Location Within String

Aug 10, 2009

I was trying to make a simple program to search in my mysql db, but i'm seeing this error :{"Index and length must refer to a location within the string. Parameter name: length"}[code]

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Oct 27, 2009

trying to determine the index of a child node using the key string so I can add a new child node to it.I am using this code:

vNodesIndex = TreeView1.Nodes.IndexOfKey(Key)

But only works for the root node when I try to find an exiting child node the code returns -1 (Not Found)

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Oct 1, 2011

This is what I have, but It doesn't work with strings for some reason (only text files):

[Code]...

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Jan 19, 2010

just wanna get that simple problem.,but i am confused bout this i cant get the index location of an array>

my problem is have to display 5 elements so the index is 0 to 4 right?

example i entered 1 2 3 4 5 then i searched 3 the location should be index 2?right?

how can i get the index location of the searched number?if you can make me understand sub and functions too..

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Jan 6, 2009

I have a button that is supposed to display a form:

Code:
Private Sub btnEditAssociate_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnEditAssociate.Click
frmEditAssociate.ShowDialog()
End Sub

Code:An error occurred creating the form. The error is : index 0 is either negative or above rows count.There is a database call on the form load property of that form, so the problem could be with that, but the when I step into the showdialog() call it produces that error on the show dialog line, so I can never see what is going wrong.

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OleDBException Invalid Index 0 For This OleDbParameterCollection With Count=0?

Aug 26, 2010

If ContractID = -1 Then
For Each itm In Tbl_ContractsList
Dim oleconnection As New OleDb.OleDbConnection(connectionstring)
'From TBL_Contracts"
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[Code]...

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Is there any way by which I can add a location to Windows 7 search index and make it indexed in .Net?

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Jan 19, 2010

i need to find the location of element by index

example i enter 5 numbers

1 2 3 4 5

search a number, i search 3 it should display the lindex location? for me to understand more about vb,,more on arrays..

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Get Index Location Of A Piece Of Data In An Array

Sep 15, 2011

I am trying to import a text file into a data table using VB.NET. I need to loop thru each line of the text file and put certain elements of that line in a new row of the data table. The line may contain 50 elements, but I only need to get 15 of them. The very first line is a header row, which contains "File Name", "Object Name", "Object Weight", etc. The trick is the element locations move from file to file. For example, "File Name" element may be located at 0 in one file and then 15 in the next file. I need to find the exact location of my desired elements and save them to a variable. Then use that variable to locate the exact piece of data in the text file line to place in my new row.

The code below obviously doesn't work, but it kind of illustrates what I need to have done.

Try
With dt
.Columns.Add("fltObjectWeight", Type.GetType("System.Double"))
.Columns.Add("vchObjectName", Type.GetType("System.String"))

[Code].....

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Dec 20, 2009

How do I refer to a form in my project by using a string variable? I'm running Visual Studio 2008.My main screen has a number of dropdown menus that, when an item is selected, a form will open:

Dim Mdi_frm_Doors As New frm_Doors Mdi_frm_Doors.MdiParent =Mdi_frm_Doors.Show()In this example, I am providing the name of the form directly (frm_Doors). What I would like to do is refer to the form as a string variable.I'm already doing something similar to access specific controls on other open forms (where str_Field is the name of the control I am accessing):

[Code]...

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Apr 22, 2010

I have a string called testlabel, and would like to refer to it via the string "testlabel", how do I do this?

for instance:

dim testlabel as label
dim a as string = "test"
dim b as string = "label"

'what is the line I need here? a & b.text = "hello world"

to get testlabel.text to read "hello world"?

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Nov 12, 2010

Is there a way to reference an object by using the value of a string read from a text file? Here's an example of what I mean: I have a user control called 'Fish', one called 'Cats', and one called 'Dogs' and so on.... I have a text file containing this line, amongst many others in a long script written after compile time by the user:

[Code]...

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Forms :: Refer To Object Via String?

Apr 21, 2010

I have a label testlabel. is there some way I can refer to it as:

dim t as string = "testlabel"
(something here referring to the OBJECT with the same name as the string).text = "mytext"

? I have 50 labels with text to change and would love to be able to:

for i = 1 to 50
dim t as string = "testlabel" & i
convertsomehow(t, label).text = "mytext"
next

so that this would change testlabel1, testlabel2, testlabel3, ... , testlabel50.

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VS 2008 - How To Refer To Objects Via String

May 9, 2011

I have lots of labels that I need to refer to.
E.g. label1 = listbox1.selecteditem.tostring & "123"
label2 = listbox1.selecteditem.tostring & "123"

I have 20 labels which i need to repeat the same process for. What I found was this code which always gives me the null reference error.
CType(Me.Controls("Label" & i), Label).Text = "what i want here"

I have stated dim i as integer = 1
And later i = i + 1 until it is 20.

I've tried i.tostring and cstr(i) when referring to it but it keeps saying it doesn't exists even though i have labels 1 to 20 named label1, label2 etc. on my Form.

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