Substring Size - "Index And Length Must Refer To A Location Within The String. Parameter Name: Length"
Jul 21, 2010
If using the following in an if statement I get an error: If trg.Name.Substring(4, 6).ToUpper <> ("ABCDEF") Then I get the error: "Index and length must refer to a location within the string. Parameter name: length"
I assume this is because the string (trg.name) is too small for the 4, 6 substring. What would be the correct method of working around this problem? VB.net Studio 2008.
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Apr 17, 2009
this is not working?
[Code]...
End WhileI am trying to read from the ": " to the end of the line. I keep getting this error: Index and length must refer to a location within the string. Parameter name: length
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Mar 23, 2009
"Index and length must refer to a location within the string. Parameter name: length" whenever I run this code
[Code]...
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Feb 17, 2011
am getting the above exception while swaping Items in the list(lstRoutePriority).PFB my code
if (lstRoutePriority.SelectedIndex > 0)
{
//Swap the two items
[Code].....
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Feb 13, 2012
Consider the Statement:
Dim pstr As String
FileOpen(2, pfilepath, OpenMode.Input)
pstr = LineInput(2)
pstr = pstr.Substring(13, pstr.Length)
Label1.Text = pstr
FileClose(2)
And it is Giving me the following error:
Index and length must refer to a location within the string. Parameter name: length.
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Jul 7, 2009
why this error happens with a bit of code i was trying? The code is actually intended to be for an onclick event, so it actually works there.
But im just curious as to why it errors as an onchange event. This is 9am pre-caffeine, so the reason is probably starring me in the face! On a form i have a text box, and a combo box. The combo box has various options in it, natch. Its a search form, which then fills a gridview with the results.
Drop down list options are: home number, mobile number, post code, Name, DOB
I thought id try and be "clever" and do away with the need for the combo box. Since a mobile number begins with "07", names are just characters, postcodes are character character number, and home number is all numbers and doesent begin with "07", and date of birth has /'s in it.
So i tried this to test the idea:
Private Sub AppSearchTB_TextChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles AppSearchTB.TextChanged
Dim TLength As Integer = 2
[Code]....
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Sep 13, 2011
I am trying to get the first 50 letters, so I used the subString function to get it. As you can see, I used this code to get it:
<%# Eval("BannerDescription").ToString.Substring(1, 50)%>
But unfortunately it's not working and an error message is coming up:
Index and length must refer to a location within the string.
Because the user is the one who is controlling the data entry! Some times he gonna enter 10 letters other times maybe 1000 letter?
I tried them all but can we use it this way :
<%# IIf(Eval("BannerDescription").ToString().Length > 49, Eval("BannerDescription").ToString().Substring(0, 49), Eval("BannerDescription"))%>
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Mar 1, 2009
I keep getting the error saying that index and length must refer to a location within the string.
Public Class MainForm
Private Sub btnAdd_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnAdd.Click
Dim description As String = String.Empty
Dim invCount As String = String.Empty
[code]....
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Sep 28, 2009
Dim Phone as string = "478-742-4050 478-256-6550"
If _Phone.Length > 25 Then
_Phone = IsNull(ReturnValue.Substring(0, 25).ToString, "")
End If
Return _Phone
Error: "Index and length must refer to a location within the string. Parameter name: length"
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Sep 7, 2009
why error "Index and length must refer to a location within the string."appear when the process of the program is going to executeNonQuery, i'm looking the error for 2 day's i still can't find it.
[Code]...
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Jun 23, 2009
I got this error and I don't know what should I do. Index and length must refer to a location within the string. Parameter name: length That's the line that i get the error on:
[Code]...
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Oct 12, 2009
why when i upload less than 10 item the program do but more than it like 15 and above the program give me error saying "Index and length must refer to a location within the string."
here is my codes below
For Each myDatarow In tblLocal.Select("sync ='0'") '
' tblServer.ImportRow(myDatarow)
' dataimpt = myDatarow.Item(4).ToString
[Code].....
the error appear when the program is going to update the 14th data... meaning from 1st to 13th data program works in the 14th it's not it gives me error "Index and length must refer to a location within the string
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Oct 15, 2010
I'm working on a vb.net project, when I execute the project I get the following error message: "error message: index and length must refer to a location within the string"
Public Sub New(ByVal lineIn As String)
parent = Trim(lineIn.Substring(0, colStarts(1)))
enfant = Trim(lineIn.Substring(colStarts(1), colStarts(2) - colStarts(1)))
des_F = Trim(lineIn.Substring(colStarts(2), colStarts(3) - colStarts(2)))
[Code]...
I get the error msg in the line marked bold. When i checked the input file, the length of all the fields looks fine. I dont understand the cause of this error.
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Dec 21, 2008
im basically working on my final years project on the vb.net with the ilog business rules. i have trouble solving this error :Index and length must refer to a location within the string. Parameter name: length And the output show this :[size=2]
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Aug 10, 2009
I was trying to make a simple program to search in my mysql db, but i'm seeing this error :{"Index and length must refer to a location within the string. Parameter name: length"}[code]
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Oct 22, 2011
I got a error when I run this code:
Dim btch As String
Dim LeftPart As String
[CODE]...
It says index and location must refert to a location withing string
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Sep 15, 2011
I'm creating a file thats need to be in this format url... I need to be able to set the limit of the string length for certain fields.Is there an easy way to set the limit of the field so that if the string was larger then the limit then just take the substring and if smaller would add extra spaces?I was able to accomplish something similar to this with integers by just using .toString("00000").
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Mar 10, 2010
I'm writing some code that takes a report from the mainframe and converts it to a spreadsheet. They can't edit the code on the MF to give me a delimited file, so I'm stuck dealing with it as fixed width. It's working okay now, but I need to get it more stable before I release it for testing. My problem is that in any given line of data, say it could have three columns of numbers, each five chars wide at positions 10, 16, and 22. If on this one particular row, there's no data for the last two cols, it won't be padded with spaces; rather, the length of the string will be only 14. So, I can't just blindly have
[Code]...
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Jul 4, 2010
I had set a print format to print some word in a Text box, when I input the text in text box is an normal size from system,but I want it print out to printer follow the Rectangle size that is was set to print out on paper.actuary i want it can auto size the font size follow by the length of string.
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Mar 29, 2011
numberofchar = timefull.Length
If timefull = "" Then
Else
If numberofchar = 11 Then
timefull = timefull.Remove(2, 9) ' isolate the hour depends on number of digits in hour parameter
Else
timefull = timefull.Remove(1, 9)
End If
End If
This is my code, it doesn't work when I copy into form load. But when I try it in another form, it works. Index and count must refer to a location within the string. Parameter name: count
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Oct 20, 2011
does anyone know how I can format the width of a DataGridViewComboBoxColumn based on the size of the string which the user selects?
my code is the following, Im way off!
Private Sub colwidth_SelectionChangeCommitted(ByVal sender As Object, ByVal e As EventArgs)
If (comboTest.SelectionLength > 0) Then
[Code]....
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Feb 10, 2010
A string can contain from 0 to approximately 2 billion (2 ^ 31) Unicode characters. Does this mean the length field for the string is a 4 byte unsigned binary field, or is it a 4 byte signed binary ?
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May 4, 2009
I would like to format output to a property of a custom control I have made.For instance I have a literal control in my control and when populated I want to check if it is longer than 30 characters long, if so, then go to the next space (as to not cut the word off) after the 30th character and place a <br /> tag in to place the next 30 characters on the next line.So if there were 100 characters in a string, there would be 3 line breaks in the label.I have the looping worked out to get the label populated but cannot get how to dymaically create the array based on the string lenth property and index of method.
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Jan 31, 2012
When I load in the file to my program.
GPRS: 232154,456464,546
IP Addr: 123.456.2.789,9001
Interval: 12.5422
It appear Length cannot be less than zero. Parameter name: length.
My program is...
Private Sub Loadbtn_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Loadbtn.Click
'Dim strFileName As String
[Code]....
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Dec 9, 2010
I keep getting the error saying that index and length must refer to a location within the string. I am sure there is just something minor that I am missing but I am having a difficult time figuring it out.
CODE:
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Jan 6, 2010
I have a field displaying on a datagrid that the user has asked to be variable length based on the data that is returned. Is there an easy way to determine how many characters are returned for a field and then converting that to a pixel length so that I can change the length of the field in the code.
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Feb 7, 2011
I have a SqlDataReader and need to read a varbinary(max) column from it using the SqlDataReader.GetBytes() method. This method populates a byte array and therefore needs to know what length of data to read.This is where I get confused.. Clearly I want to read all the data that has been returned from the database in this row/column so what 'length' parameter should I pass?As far as I can see, the SqlDataReader doesn't provide any methods to discover what length of data is available, therefore this method seems fairly awkward to me.I'm tempted to just pass int.MaxValue here and forget about the issue but something about this doesn't sit right with me.
I am aware that I can instead call
byte[] value = (byte[])dataReader["columnName"];
.. and this seems to completely take care of the length issue internally. However I am working with a set of complicated code generation templates that have been built around the SqlDataReader.GetXXXX() methods. So I am tied into using GetBytes and need to understand its proper usage.
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Jun 21, 2012
I have a SqlDataReader and need to read a varbinary(max) column from it using the SqlDataReader.GetBytes() method. This method populates a byte array and therefore needs to know what length of data to read.This is where I get confused.. Clearly I want to read all the data that has been returned from the database in this row/column so what 'length' parameter should I pass?As far as I can see, the SqlDataReader doesn't provide any methods to discover what length of data is available, therefore this method seems fairly awkward to me.I'm tempted to just pass int.MaxValue here and forget about the issue but something about this doesn't sit right with me.
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Oct 23, 2009
Getting error filling grid view from reading through data table:
Dim myDataTable As DataTable = myDataSet.Tables("SunTrust")
Dim myRow As DataRow
Dim i As Integer = 1
Try
[code]....
Error:Index was out of range. Must be non-negative and less than the size of the collection.Parameter name: index
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Jul 30, 2009
I want to determine size/length of an array that is, how many elements are in my 1 dimen array, can't seem to find the right method that works.
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