Dynamically Create Array Based On String Length Property and Index Of Method
May 4, 2009
I would like to format output to a property of a custom control I have made.For instance I have a literal control in my control and when populated I want to check if it is longer than 30 characters long, if so, then go to the next space (as to not cut the word off) after the 30th character and place a <br /> tag in to place the next 30 characters on the next line.So if there were 100 characters in a string, there would be 3 line breaks in the label.I have the looping worked out to get the label populated but cannot get how to dymaically create the array based on the string lenth property and index of method.
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Jul 20, 2010
how to split a string into an array based on it's length?Say if I want the length to be 350 then every 350 chars in a textbox will be split into an array like [code]
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Jul 13, 2010
i have an array contains a-z.Then i have a textbox and when click on the button, it will replace the text inside the textbox to the index number of the array.Example, from "abc" will become "0 1 2" The code below do the job.how to do so that i can replace the text inside the textbox from "0 1 2" back to "abc" based on the array?
Dim txtKey As String = readKeyTxt.Text
readKeyTxt.Text = ""
For Each b As String In txtKey[code].....
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Apr 17, 2009
this is not working?
[Code]...
End WhileI am trying to read from the ": " to the end of the line. I keep getting this error: Index and length must refer to a location within the string. Parameter name: length
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Feb 17, 2011
am getting the above exception while swaping Items in the list(lstRoutePriority).PFB my code
if (lstRoutePriority.SelectedIndex > 0)
{
//Swap the two items
[Code].....
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Mar 23, 2009
"Index and length must refer to a location within the string. Parameter name: length" whenever I run this code
[Code]...
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Jul 21, 2010
If using the following in an if statement I get an error: If trg.Name.Substring(4, 6).ToUpper <> ("ABCDEF") Then I get the error: "Index and length must refer to a location within the string. Parameter name: length"
I assume this is because the string (trg.name) is too small for the 4, 6 substring. What would be the correct method of working around this problem? VB.net Studio 2008.
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May 25, 2011
Is it possible to select a value of a drop down by its dynamic index that is returning from another function whereas selectindex = 2 (generated dynamically)
selenium.Select(Id, "index = SelectIndex")
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Aug 11, 2010
I need to get the ID number from an acces table (I am working with GIS .. I do not nkow if that helps) from a record (I do not know if I am using the correct technical words here)
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Jul 7, 2009
why this error happens with a bit of code i was trying? The code is actually intended to be for an onclick event, so it actually works there.
But im just curious as to why it errors as an onchange event. This is 9am pre-caffeine, so the reason is probably starring me in the face! On a form i have a text box, and a combo box. The combo box has various options in it, natch. Its a search form, which then fills a gridview with the results.
Drop down list options are: home number, mobile number, post code, Name, DOB
I thought id try and be "clever" and do away with the need for the combo box. Since a mobile number begins with "07", names are just characters, postcodes are character character number, and home number is all numbers and doesent begin with "07", and date of birth has /'s in it.
So i tried this to test the idea:
Private Sub AppSearchTB_TextChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles AppSearchTB.TextChanged
Dim TLength As Integer = 2
[Code]....
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Sep 13, 2011
I am trying to get the first 50 letters, so I used the subString function to get it. As you can see, I used this code to get it:
<%# Eval("BannerDescription").ToString.Substring(1, 50)%>
But unfortunately it's not working and an error message is coming up:
Index and length must refer to a location within the string.
Because the user is the one who is controlling the data entry! Some times he gonna enter 10 letters other times maybe 1000 letter?
I tried them all but can we use it this way :
<%# IIf(Eval("BannerDescription").ToString().Length > 49, Eval("BannerDescription").ToString().Substring(0, 49), Eval("BannerDescription"))%>
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Nov 16, 2011
I just don't understand why (intValues.Length - 1) is used: to be precise why the ( - 1 ) is there?
Dim intValues(25) as integer
For intCount = 0 to (intValues.Length -1)
MessageBox.show (intValues(intCount).ToString())
Next
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Mar 1, 2009
I keep getting the error saying that index and length must refer to a location within the string.
Public Class MainForm
Private Sub btnAdd_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnAdd.Click
Dim description As String = String.Empty
Dim invCount As String = String.Empty
[code]....
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Sep 28, 2009
Dim Phone as string = "478-742-4050 478-256-6550"
If _Phone.Length > 25 Then
_Phone = IsNull(ReturnValue.Substring(0, 25).ToString, "")
End If
Return _Phone
Error: "Index and length must refer to a location within the string. Parameter name: length"
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Sep 7, 2009
why error "Index and length must refer to a location within the string."appear when the process of the program is going to executeNonQuery, i'm looking the error for 2 day's i still can't find it.
[Code]...
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Jun 23, 2009
I got this error and I don't know what should I do. Index and length must refer to a location within the string. Parameter name: length That's the line that i get the error on:
[Code]...
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Oct 18, 2011
Im trying to format the length of a DataGridViewComboBoxColumn based on the length of the longest string in the comboBox. Here is the code I currently have but it only formats the DataGridViewComboBoxColumn based on the users previous selection in the comboBox.
Is there a way to have the DataGridViewComboBoxColumn at the length of the longest string in the comboBox? Here is my code.
Private Sub comboTest_SelectionChangeCommitted(ByVal sender As Object, ByVal e As EventArgs) Handles comboTest.SelectionChangeCommitted
Dim senderComboBox As ComboBox = CType(sender, ComboBox)
[Code].....
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Nov 2, 2011
MVC 3. Vb.net. Part of my app generates PDF files using Itextsharp. Some strings are too long to go onto the background image correctly. So I basically need to split this string when its over 26 characters long and when it splits it cant split in the middle of a word. from there I will use newline to add the string to the right to the next line... I did start bulding the function that I will pass the string into test for length and then pass back the string after it finishes.
Private Function stringLength(ByVal _string As String) As String
If _string.Length < 26 Then
_string.Split(
End If
End Function
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Oct 20, 2011
does anyone know how I can format the width of a DataGridViewComboBoxColumn based on the size of the string which the user selects?
my code is the following, Im way off!
Private Sub colwidth_SelectionChangeCommitted(ByVal sender As Object, ByVal e As EventArgs)
If (comboTest.SelectionLength > 0) Then
[Code]....
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Oct 12, 2009
why when i upload less than 10 item the program do but more than it like 15 and above the program give me error saying "Index and length must refer to a location within the string."
here is my codes below
For Each myDatarow In tblLocal.Select("sync ='0'") '
' tblServer.ImportRow(myDatarow)
' dataimpt = myDatarow.Item(4).ToString
[Code].....
the error appear when the program is going to update the 14th data... meaning from 1st to 13th data program works in the 14th it's not it gives me error "Index and length must refer to a location within the string
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Oct 15, 2010
I'm working on a vb.net project, when I execute the project I get the following error message: "error message: index and length must refer to a location within the string"
Public Sub New(ByVal lineIn As String)
parent = Trim(lineIn.Substring(0, colStarts(1)))
enfant = Trim(lineIn.Substring(colStarts(1), colStarts(2) - colStarts(1)))
des_F = Trim(lineIn.Substring(colStarts(2), colStarts(3) - colStarts(2)))
[Code]...
I get the error msg in the line marked bold. When i checked the input file, the length of all the fields looks fine. I dont understand the cause of this error.
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Feb 28, 2010
How can to make control arrays in vb.net ? there is no INDEX property or Load method like VB6. so how i can do it ?
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Sep 2, 2010
I've created some classes that will be used to provide data to stored procedures in my database. The varchar parameters in the stored procs have length specifications (e.g. varchar(6) and I'd like to validate the length of all string properties before passing them on to the stored procedures.
Is there a simple, declarative way to do this?
I have two conceptual ideas so far:
Attributes
public class MyDataClass
{
[MaxStringLength = 50]
[Code]....
This seems like a lot of work and will really make my currently-simple classes look pretty ugly, but I suppose it will get the job done. It will also take a lot of copying and pasting to get this right.
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Jun 12, 2012
I need to create a sample question types web form in VB.NET which allow user to the following:he user selects the control type from dropdown (TextBox, RadioButton, ListBox etc). Generate controls dynamically based on the control type on the webform.It will always show the TextBox (where user writes the question) and (generated control - TextBox, RadioButton, ListBox etc) and save those values to the database.
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Mar 23, 2011
Is it possible to (or how can I) assign values to a class property array like this:
MyImgClass.RGB = (255,255,255)
I'm not sure how to build my Public Property setter to allow this, if it's possible at all.
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Sep 11, 2011
I have a long string like this
dim LongString as String = "123abc456def789ghi"
And I want to split it into a string array. Each element of the array should be in 3 characters length[code]...
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May 10, 2011
I have a problem to make the comparison from char to string array using Naive Algorithm in vb.net.[code]The problem is the system cannot compare the input from s1 to compare with s2.
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Jan 21, 2011
I'm trying to reference a public property from a string. How can this be done in vb.net?I have the text value of "FirstName" stored in strucParam(i).TxtPropertyName.[code]...
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Mar 30, 2012
[Code]...
I want to create a ProgressBar with my array length, whithout timer object. When ProgressBar increment, the value in array appears in a label.
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Jan 31, 2011
How can I create an empty string that is a certain length?
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