ToolTip Does Not Appear When Set To A Long String?
Dec 20, 2010
I am working in VB.Net 2010 framework 2.0.I am setting a big string to tooltip object. In this case tooltip is not appearing. If the string is short (say of 10 lines), tooptip is appearing properly.The following is the code:[code]....
If the "PanelText" is too long (say 50 lines), it does not appear. Sometimes it shows an empty tooltip.
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Dec 20, 2010
I am working in VB.Net 2010 framework 2.0. I am setting a big string to tooltip object. In this case tooltip is not appearing. If the string is short (say of 10 lines), tooptip is appearing properly.
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Dec 16, 2009
how to hide bollon tooltip When user click on the ballon tooltip?
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Jun 24, 2011
I am adding ToolTips to my forms and sometimes to get the point across my text string can get lengthily. This results in a long single line. Currently I am simply adding manual carriage returns after a test run and then making changes when it looks right. Has to be a better way.
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Jun 22, 2010
Does anyone know if it's possible to skin the tooltip window so it looks like: Attachment 2448.Instead of the yellow box or the balloon like it does now?
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Jul 13, 2010
I have a very long string. I need to parse this string so I can get information out of it. I know what each segment starts with and ends with. The length of the information will vary. I don't know what the easiest way of parsing this string.
Example data will be
ST*997*232898~AK1*HC*8888*~NM1*2*TESTING........
So i will want to get everything from ST to AK1then AK1 to NM1 and so on and so on.
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May 15, 2012
error message i get during compile programe:
string must be exactly one character long. Couldn't store <1 > in scopee column.
Expected type is char.
this is my sql db:
[code]....
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Apr 21, 2012
Is there another way to make it so I can add long text to a textbox instead of doing:
richtextbox1.text = "Long string"
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Apr 16, 2012
I have a client application that connects to a WCF service, i get the file size from the server as a long value then i convert it at the client to a string so it appears like ex:52.21 MB the application gets too many files sizes every time user changes the directory pathso the question is :should i convert the values to a string format from WCF service app then return it to the client as a string format or should i just return the size as a long value and let the client to convert it to a string format in other way which value take more bytes in the memory:
[Code]...
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Apr 22, 2011
I have a text file with names that have spaces and commas. For some reason when I read the file it gives me this error. Code is below. Also, I am reading the file into a combobox.
[Code]...
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Jan 10, 2012
A question: How can I create a string that is x characters long, but is made up of "space bar" characters?
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Oct 13, 2010
In vba, There is an address held by a long type which points to a null-terminated string, but I can't find a way to get the string from this address:
long str_address = ...
string str = ?
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Jul 7, 2011
look at this code and see how i can speed it up? Its calling a sub to count commas in long string.Calling part 'Sort the incomming messages Dim count_Coma As Integer = CountCharacter(_InMessToAction, ","c)
The sub. This takes about 0.7 of a second to count 20 commas in string _InMessToAction. Was hoping to get it down to 0.1... if at all possible.
[Code]...
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Oct 26, 2009
I want to convert a List (of Long) into a string array.
Reason: it's a list of database IDs and I want to make a comma delimited string to pass into a stored proc.I tried this:
Dim commaDelimitedList As String = String.Join(",", itemIDList.Cast(Of String)().ToArray)
but I'm clearly not using the Cast correctly since it throws an exception:
System.InvalidCastException: Unable to cast object of type 'System.Int64' to type 'System.String'..
Is there a way to get Cast working for this, or am I stuck with ConvertAll and a delegate function?
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May 22, 2009
Display multirows if the string is too long on datagridview?[code]...
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Oct 28, 2011
Ive been searching the Stackoverflow but couldnt find the exact thread that my problem is this, i want to be able to find and take out any occurances of 8 digits wihtin a string.
Dim SetOfMatches As MatchCollection
Dim MyRegex As New Regex("A^d{8}$A")
Dim TestString As String = "testing 12345678 testing"
myMatches = myRegex.Matches(TestString)
For each Row as Match in myMatches
console.writeline(row.value)
Next
this doesnt not generate any hits. but i want to find the 8 digit occurance in the middle of the string.
I am very basic in RegEx.
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Dec 29, 2009
I am trying to split a long string of data into an array:
[Code]....
Ive tried a few ways to write out the regex, but to no avail. Also, sometimes responseFromServer2 contains newlines, and sometimes it does not, depending on the response I get from the server...
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Feb 14, 2010
i am trying to convert test from a label into a 'long integer' type. i will then use this long integer type to read from the database (Ms access 07). i will be reading an autoNumber from the database
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Sep 18, 2011
Is there a easer way of coding in stead of wrighting long long paragraphs like this in one line [code]All of this is on one line and i got lots of info to put down.."The game will begin on your 16th birthday with your mother waking you up. Today you are to go to the castle for the first time. Leave your bed and open your dresser for a Strength Seed. "
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Mar 3, 2011
I'm trying to make a hash calculator (For testing now)
I know that MD5 is a 1 way(Meaning that there is no decryption for it, yet)
now I was wondering if SHA-1 is a two way. Also, is there any other hashing method that are 2way?
reason is that I want to convert a long string (Lets say 550 chars) into something lower (From 550chars to something lower then 550chars)
I can use a Key, but every possibility will give me bigger length then the actual string.
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Mar 9, 2009
I have a String with 15 places that I would like to split into 3 pieces: (First 3 digits), (next 3 digits), (remaining 9 digits).
How in VB2008 can I do that? Everything I have read so far indicates seperating by a certain character (ie: "," or " ") but no mention of character place. Seems like a simple thing, but after 2 hours of searching I'm still coming up empty
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Mar 17, 2011
I am trying to update an Oracle Database record and i keep getting this error:
ORA-01704: string literal too long 5
I looked up that error and it seems that i have a limit of 4000 charters since i am using Oracle 10g. However, the prgblem is that its the same exact data i am putting back into that record so that is why i am unsure as to why its giving me that error for the same amount of data i took out of it.
Here is my update code:
Dim myCommand As New OracleCommand()
Dim ra As Integer
Try
[code]....
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Jun 26, 2009
I'm pulling records from a db table (sybase) where I have run into a problem with a long varchar field. Using the OLEdb class I convert the field into a string variable which works fine in most cases, but there are problem with a few records. Examining the field in the database it shows that the value is not null, but the length of the field is 0.(SELECT field, length(field) FROM table). When I try to convert this into a string the result is rubbish.strContent = objReader.Item(i). I can't figure out what's the problem here, so I have avoided the issue by doing a table update before I start the process of getting data (I set the field value to null if field.length = 0
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Jan 12, 2009
I nedd some help in generating a random alph-numeric password for a form that I building. The form should suggest a password that 18 characters long. The user would either agree to this password or enter their own password.[code]When I use this I get a two digit number.
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Jun 7, 2011
I am having an issue where the I am trying to use some Regular Expression in a constraint. The issue is it is evaluating the Regex as a string, and throwing an error. "Cannot convert String 'd+' to long".
.MapPageRoute("Parts",
"{PartName}/{Part}/",
"~/Inventory/Default.aspx",
Nothing,
New RouteValueDictionary(New With
{.Part = "d+"}))
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Nov 18, 2011
I have a DataGridView with one column, I set for that column
DefaultcelStyle->Wrapmode=True
Modify data a with a long string, I call also
vb.net
DataGridView1.AutoResizeRows()
DataGridView1.Refresh()
But the DataGridView doesn't refresh wrap,il looks like this : I change manually current selected row moving to another record and now the refresh is done :
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Apr 16, 2009
I would like to ask for some on how to create a random string with number and letters in 8 characters long in VB 2008
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Sep 27, 2009
I have a program that requires a string. The string is 20 characters long. The string also have to be split into 2 words the first word is 12 characters and the second is 8. If the strings is not 20 characters long I get an error. I wanted to know how can I get the program to start back over and let me enter another 2 more words if the string is not 20 characters long. At the moment after I get the string is not 20 characters long error it continues to read the rest of the program but I want it to stop after an error and let me start over from the beginning.
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Nov 10, 2010
I have a task to resolve, it is regading extracting characters from a long string to the console, the extracted text shall be reformatted and saved into a CSV file. The string comes out of a database.
It looks something like: UNH+RAM6957+ORDERS:D:96A:UN:EGC103'BGM+38G::ZEW+REQEST6957+9'DTM+Z05:0:805'DTM+137:20100930154
The values are seperated by '.I can query the database and display the string on the console, but now I need to extract the Keyword 'ORDERS' for example, and lets say it's following 5 Characters. So the output should look like: ORDERS:D:96A then I need to extract the keyword 'BGM' and its following five characters so the output should look like: BGM+38G:After extracting all the keywords, the result should be comma seperated and look like:
ORDERS:D:96A,BGM+38G: it should be saved into a CSV file automatically.
I tried already:
'Lookup for containing KeyWords
Dim FoundPosition1 = p_EDI.Contains("ORDERS")
Console.WriteLine(FoundPosition1)
Which gives the starting position of the Keyword.I tried to trim the whole thing around the keyword "DTM". The EDI variable holds the entire string from the Database:
Dim FoundPosition2 = EDI
FoundPosition2 = Trim(Mid(EDI, InStr(EDI, "DTM")))
Console.WriteLine(FoundPosition2)
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Jun 11, 2010
I am trying to input a very long list of dog breed names into a DB via phpmyadmin, this will take me for ever manualy and I was thinking if I could work out how to write something quick and nasty to create the sql string for each dog breed it would save me so much time. The sql query for each added forum is in the following format:
[Code]...
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