Possible To Open A Zipped File
Jul 1, 2009Is it possible to open a zipped file with VB.NET .What I want to do is open a zip-file that contains of several eml-files and read them into my application.
View 7 RepliesIs it possible to open a zipped file with VB.NET .What I want to do is open a zip-file that contains of several eml-files and read them into my application.
View 7 RepliesI have the following unzip function which works fine if I have only 1 zipped folder..However, how can update it to accomodate a zipped folder within a zipped folder. Therefore, lets assume you have a folder name A.zip within this folder you have B.zip. Presently, it unzips folder A and leaves folder B zipped. I would like to unzip both A and B folder..
Code:Private Sub unzip(ByVal filename As String, ByVal targetdir As String, ByVal overwrite As Boolean, Optional ByVal password As String = "")
Dim inputStrm As New ZipInputStream(File.OpenRead(filename))
inputStrm.Password = password
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How do I write a Text file as a compressed (zipped ) file?
View 1 RepliesI would like to ZIP a file with VBA. The following code from Code [URL]..
View 2 RepliesI am trying to programmatically extract from a compressed zipped folder which has the path of c:abc.zip and 4 files within the folder (one.txt, two. txt,three.txt and four.txt). I want to place two.txt in a destination path of c:xyz wo.txt.
View 3 RepliesHow do I write a Text file as a compressed (zipped ) file?Using vb 2008, .Net
View 5 RepliesWhen I right click a file folder, I get an option called Explore on my pop-up menu. It lets me do this for zipped records also. I want to be able to do this programmatically in my Visual Basic program. How do I explore a file folder and expose its contents in a Listbox. How can I do this for a zipped file? If a folder is zipped and contains a list of files in it, can I go into the file and delete the file without having to unzip the folder. Today, I was able to cut files out of a zipped file and paste the individual files somewhere else. Can I do this programmatically?
View 5 Replieshow to loop through a zip file and return all the file extensions in the zipped file.
View 2 RepliesI need to make a zipped copy of a spreadsheet I create in xlsx format in Access2007. This needs to follow the creation of the spreadsheet as the path and file name are also created programmatically.
My code at present is:
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can we unzip a zipped folder using microsoft APIs or namespaces perhaps System.IO.Compression. However, it seems to be cumbersome to use them. With a thrid party dll file it works perfectly fine, however i dont want to use it as we dont know what is actually happening inside. Can we have a piece of code which unzips a zipped folder.
View 3 RepliesWhy would a .sln solution file open and appear empty in Microsoft Visual Basic 2010 Express - i.e. no windows showing projects and code files etc.When I inspect the file in a text editor, it contains references to vbproj files (which are present) which indicate that it should not appear as empty.No error messages are reported when the file is opened.
View 2 RepliesI would like to open the excel file after create the excel file. The creating file function is done, but the system unable to open the excel file. My coding as below:
Dim xlApp As Excel.Application
Dim xlWorkBook As Excel.Workbook
Dim misValue As Object = System.Reflection.Missing.Value
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how to use open file dialogs to open a file to a text box?
View 6 RepliesI've noticed that when you click on a web page in Windows Explorer, or open a file in general, and the default application to open it is internet explorer, ie opens and opens the file. However, when I tried this on my Web Browser it opened, but ignored the file and went on its usual routine. How can I get my Web Browser to open and open the file that was clicked on in explorer?
View 1 RepliesI saved a file with the extension .doc. I use the RichText to write and save the text. I did not set any encoding type when I saved it. When I tried to open the file in the Richtextbox again, I got all the formatting characters in the RTF file. How do I correct this? How do I open and re-open a .doc file in the Rich Text box control without the formatting showing up in the box with the document contents?
View 4 Repliesim having a slight problem with my open file dialogue box, i need to be able to open the dialgue box, and click the file and open in my pdf reader, or at least load it to my other form ive created. what ive go so far:
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I like to open a file. The open option should be shown in a separate window. My code works fine but the open window is not displaying to open a file. Here is the code:
private void OpenMyFile()
{
string path = GetPath() + ViewState["fileopen"];
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I'm trying to create a program where I open a file using a open file dialog and take the information from a text file and output them into various listboxes and textboxes
The first problem I had encountered was at :
With CurrentCustomer
.EmployeeID = ToInt32(Fields(0))
.Name = Fields(1)
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Using VB to open a .csv file with "excel.workbooks.open", editing it, then saving as .csv.
Even though it is saved as .csv, it is still identified as .xls.
Is there an alternate way to open this .csv file so that when it is saved as .csv the excel application actually identifies it as a comma delimited, not a spreadsheet?
I am trying to use the open file dialog box in VB 2005 to open up an existing txt, or rtf file from a directory into a rich text box. I am able to get the Open file dialog to appear and the directories, but when I try to open the file it doesnt import it into the text box. Here is the code I am using
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Years ago when coding with VB6 and earlier, I used a file open command to create, read, and write a file that made it easy to store useful information.I believe it was binary and you wrote/read the data to a specific line in the file. When you opened the file with something like notepad, it just showed random ascii chars. When I needed a line of data, I could specify what line to load it from.
View 2 RepliesI've gone through about 16 hours and two packs of cigarettes trying to figure this out. First a little background. I was using 6.0 up until 2004 when I went to prison. I'm out now, and trying to relearn the trade, using VS 2005. I'm currently porting some 6.0 code from another project, SpyCast Webcam Studio, into VB 8.0. It's disheartening, to say the least. None of the old built-in subs/functions work anymore, so I have to scour the forums to relearn each and every function.The section I'm doing now takes a snapshot from the webcam (Video API --> PictureBox --> Save as Jpeg), then upens the file to upload it to the server via HTTP POST. I've been using this code in SpyCast for years with no trouble, but I spent many hours trying to piece together the right code to open the binary file to read its contents. I pieced together two methods I found around the forums, one using FileStream() though the code I found wasn't for binary files, even though it said it was, so that code doesn't really work. Method two uses Microsoft.VisualBasic.FileOpen() and works better.
Here's the kicker. By the time I run through the rest of the rigamarole of uploading the file, by the time I read it on the webserver, it's *slightly* corrupted. It's a valid Jpeg, no errors, but the picture looks like when I use to watch the Playboy Channel when I was a kid scrambled with weird colors and whatnot. [code] Each "chunk" is basically one "line" of the file. It looks like a single LineInput() return is the text between two carriage returns. Am I correct? I tested this with a flat text file, and it looks true. However, That one input line returns the text or data with the carriage returns *stripped*! ***?!? =( Fine, I have no problem adding my own vbCrLf to each LineInput(), if I were opening text. but this's binary. A character could be Chr(10) or Chr(13), both of which are removed from the original file contents.So I could very well need to use something other than LineInput(), but I haven't found any other examples on the web using this method.
I need a code for the open file dialog that if a file is not supported then a message box appears stating the error. This is my open file dialog code. [code] The message box pops up like it is suppose to, when you click ok the open file comes back up like it is suppose to. When you put in the correct file the message box comes back up again. Also the message pops up even if the correct file is put in the open file. but if you close the file dialog the image is where it is suppose to be.I believe the code for the public sub wrongfile is what is the problem. can some one look it over and let me know what changes are needed.
View 7 Replieshow can i save 2 textboxes(string) into 1 file? and when open the file, the string goes to definite texboxes...
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What i am trying to do is open a save file dialog and write to a .txt firl the contents of my listview. so far:
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i have this, but i'm not to sure how to write to the .txt file i know i need to use a for each to loop the contents of the list view
It is saved on my desktop for easy access.I can close the program. I can click the solution to open it right back up, no problems.I then zip my file (also to the desktop)
My problem: I moved the original file (Project A) to another folder and extracted the unzipped Project A onto the desktop. When I open the new Project A's solution file, nothing happens besides VB starting up. It doesn't show me anything.
I get mixed results in Google, so I'm wondering how can I simply launch a ReadMe.txt file in Notepad thats in the same directory as my application?
View 1 RepliesI need to open an excel file from vb.net and then search it for specific data. I then need to take those data and insert them into text boxes on a form that i have created. This is all controlled by a button click. I already have some code that will open a file dialog box and let me navigate to the correct file, but I am having trouble with the search portion. I have tried the Find function but I am not sure of the proper syntax. I am using Visual Studio 2008 and Excel 2003.
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I have a checked list box that is populated with the text from a text file. I started off with this code:
Dim FileToLoad As String
FileToLoad = TextBox3.Text
Dim fs As FileStream = New FileStream(FileToLoad, FileMode.Open)
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Well im making a program that will Add the Safe File Name of the File opened in the Open File Dialog to the first column of the listview and the File name and path to the second. What i want it so when i double click on the Safe file name it will open the file specified in the path in the second column.i already got the add file to it.
View 4 Replies