Strip First 75 Characters Of String And Maintain Word Structure?
Jan 31, 2011
I am trying to strip the first 75 characters from various strings (sentences / phrases) and it seems right but I need to ensure that the no words are truncated in the process. Meaning that if the 75 character is part of a word it needs to fall back to the beginning of the word or nearest space..
I thought of stripping the entire string into separate words and then counting the length of combining the words and stopping when I reach the target but what do I do in the case when it is not a valid sentence just a bunch of characters jammed together or spaces and one character. I thought of using grammar parsing tool libraries and parsing into tokens etc but that seems too over complicated.
Here is what I have so far:
If htext.Length() > 75 Then
Dim regex2 As Regex = New Regex("^.{0,75}", RegexOptions.IgnoreCase)
Dim m2 As Match = regex2.Match(htext)
[Code].....
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Jan 28, 2011
I am trying to strip the first 75 characters from various strings (sentences / phrases) and it seems right but I need to ensure that the now words are truncated in the process. Meaning that if the 75 character is part of a word it needs to fall back to the beginning of the word or nearest space..
I thought of stripping the entire string into separate words and then counting the length of combining the words and stopping when I reach the target but what do I do in the case when it is not a valid sentence just a bunch of characters jammed together. I thought of using grammar parsing tool libraries and parsing into tokens etc but that seems to over complicated.
if text.length() > 75 then
ctext = text.remove(text.length, 75) & "..."
endif
I put elipses at the end but using the above I also get the error:
does anyone have any better suggestions.
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Apr 29, 2010
I have had a look at 2010 to see if any options have been added to
System.StringSplitOptions
and we still have;
None
or
RemoveEmptyEntries
Anyway after answering another STRING related question here.>>
[URL]
I thought about how the String.Split method works.
Often I have wanted to split a string on the characters that terminate a sentence such as a full stop >> . << ,
a question mark >> ? << or an exclamation mark >> ! << and still keep the string split characters.
[Code]....
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Example string:
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I need to get: "Repair: getthis! "
Other example
Machine: dddddd Repair: hi"
I need to get: "Repair: hi"
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<description>Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, when an unknown printer took a galley of type and scrambled it to make a type specimen book. It has survived not only five centuries, but also the leap into electronic typesetting, remaining essentially [...]</description>
[Code]...
How we can do with a string by showing continuation with [...] after a word break?
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[Code]...
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<
If Line.Contains(Me.rtbSearch.Text) Then
'show search form
[code].....
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GroupName.Substring(0, 3) = "jt_"
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If (GroupName.Length > 2) Then
If (GroupName.Substring(0, 3) = "jt_") Then
Note that the two comparisons need to be on separate lines. If they are on the same line, such as:
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dp.SyntaxHighlighter.HighlightAll('9844f9bfb55449e6a786fa62aaadfa20')
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[Code]...
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Private Sub btnSimpleStrip_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnSimpleStrip.Click
Dim iStartTagPos As Integer ' Store start Position of the Start tag
Dim iEndTagPos As Integer
Dim iStartSearching As Integer
[Code]...
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